julian-date

问题 How can a date/time object in R be transformed on the fraction of a julian day? For example, how can I turn this date: date <- as.POSIXct('2006-12-12 12:00:00',tz='GMT') into a number like this > fjday [1] 365.5 where julian day is elapsed day counted from the january 1st. The fraction 0.5 means that it's 12pm, and therefore half of the day. This is just an example, but my real data covers all the 365 days of year 2006. 回答1: Since all your dates are from the same year (2006) this should be

问题 I need to convert Julian timestamp to Regular timestamp in UNIX using Bash. On Tandem OS, conversion is pretty straightforward - Example: 212186319010244541 $OLSAPP SYSTST 1> #interprettimestamp 212186319010244541 #interprettimestamp 212186319010244541 expanded to: 2455860 2011 10 25 16 10 10 244 541 I wish to do the same on UNIX environment. The conversion will be a part of a parser script. So one-liners would be greatly appreciated. UPDATE : INTERPRETTIMESTAMP inbuilt function on Tandem

问题 yy = 15 (year), D = 150 (day of year), HH = 10 (hour) Date myDateWrong = new SimpleDateFormat("yyDHH").parse("1515010"); Date myDateTrue = new SimpleDateFormat("yyD").parse("15150"); myDateTrue is right: 30/05/2015. myDateWrong must be 30/05/2015 10:00:00 but it seem that 28/07/2015 18:00:00. Whats the problem in here? 回答1: I'm going to guess that the wrongDate took a single digit for the month (as you specified) and then took the rest of the digits for the hour (much as it took the rest of

问题 How to get today's Julian day number (JDN) equivalent? or any date's, for that matter? I've looked and looked, but only found some functions that produced "year-dayOfYear", not something like: 2457854. 回答1: in bash date +%j returns julian date. [root@TX-Serv-1 ~]# date +%j 108 Also Julian dates in the future are pretty easy too. [root@es-host01 ~]# date --date='10 days' +%j 119 [root@es-host01 ~]# date --date='2 weeks' +%j 123 回答2: I ended up porting one myself. Here is a SSCCE: #!/bin/bash

问题 I am trying to convert calendar date like so: '2018-08-07' to julian calendar day like so '219' . I have tried for a long time and seem to run out of ideas. The julian day calendar is this one I am using: https://landweb.modaps.eosdis.nasa.gov/browse/calendar.html Still new to programming so I am trying to figure out where I went wrong. Appreciate your help, folks. This is what I have so far: from datetime import date import datetime from PyAstronomy import pyasl df = datetime.datetime(2018,

问题 I am trying to convert calendar date like so: '2018-08-07' to julian calendar day like so '219' . I have tried for a long time and seem to run out of ideas. The julian day calendar is this one I am using: https://landweb.modaps.eosdis.nasa.gov/browse/calendar.html Still new to programming so I am trying to figure out where I went wrong. Appreciate your help, folks. This is what I have so far: from datetime import date import datetime from PyAstronomy import pyasl df = datetime.datetime(2018,

问题 I'm trying to create a julian date in python and having major struggles. Is there nothing out there as simple as: jul = juliandate(year,month,day,hour,minute,second) where jul would be something like 2457152.0 (the decimal changing with the time)? I've tried jdcal, but can't figure out how to add the time component (jdcal.gcal2jd() only accepts year, month and day). 回答1: Not a pure Python solution but you can use the SQLite in memory db which has a julianday() function: import sqlite3 con =

问题 First I'm sorry for the poor English but I'll try to be as understandable as possible. I'm trying to make a Oracle Database SQL Query which subtracts the datetime value of two existing columns, I managed how to do it using the instruction shown below but the column TEMPO that I created is returning with NUMBER format. SELECT M.NUMOS, M.CODFUNCOS, M.DTINICIOOS, M.DTFIMSEPARACAO, M.DTFIMSEPARACAO - M.DTINICIOOS AS TEMPO FROM PCMOVENDPEND M WHERE DTFIMSEPARACAO IS NOT NULL AND DATA >= SYSDATE-1

问题 I want to use GregorianCalendar instead of Time class, how android documentation suggest, but how manage julian day for store a date as a int in my sqlLite db? How can i convert this code? public static long normalizeDate(long startDate) { // normalize the start date to the beginning of the (UTC) day Time time = new Time(); time.set(startDate); int julianDay = Time.getJulianDay(startDate, time.gmtoff); return time.setJulianDay(julianDay); } And when i query a row how can get the normal date

问题 I want to use GregorianCalendar instead of Time class, how android documentation suggest, but how manage julian day for store a date as a int in my sqlLite db? How can i convert this code? public static long normalizeDate(long startDate) { // normalize the start date to the beginning of the (UTC) day Time time = new Time(); time.set(startDate); int julianDay = Time.getJulianDay(startDate, time.gmtoff); return time.setJulianDay(julianDay); } And when i query a row how can get the normal date