jsonp

php上传视频文件怎么实现

依然范特西╮ 提交于 2019-12-04 07:24:36
我们平时经常做的是上传文件,上传文件夹与上传文件类似,但也有一些不同之处,这次做了上传文件夹就记录下以备后用。 首先我们需要了解的是上传文件三要素: 1.表单提交方式:post (get方式提交有大小限制,post没有) 2.表单的enctype属性:必须设置为multipart/form-data. 3.表单必须有文件上传项:file,且文件项需要给定name值 上传文件夹需要增加一个属性webkitdirectory,像这样: <input id="fileFolder" name="fileFolder" type="file" webkitdirectory> 功能介绍: 树形目录导航。您可以通过树型目录导航和路径导航栏快速跳转到指定目录。在跳转后树型目录将会自动选中当前的目录。 ​ 路径导航,点击根目录按钮便可返根目录 ​ 文件和目录重命名 ​ 点击删除按钮 ​ 点击确定后,页面中的文件消失 批量上传文件 ​ 粘贴上传 复制文件夹、文件或图片 ​ 在页面中选择好相应的上传目录,点击粘贴上传按钮,数据即可快速开始上传 ​ 批量上传文件和文件夹 ​ 数据库记录 ​ 文件和目录下载 ​ 工程截图 ​ 以下是实例的部分脚本文件与文件块处理代码: //文件上传对象 function FileUploader(fileLoc, mgr) { var _this = this;

Read continuous feed from CouchDB using Ajax/jQuery

南楼画角 提交于 2019-12-04 07:20:44
I want to listen for continuous changes from CouchDB using jQuery - now this works: http://localhost:5984/testdb/_changes?feed=continuous which means that I get a new line of json every time there is a db update - but how do I read updates off this URL using jQuery? I tried using this but it doesn't work: $.ajax( { url : "http://localhost:5984/testdb/_changes?feed=continuous&callback=?", dataType : 'json', success : function(data) { alert(data.results.length); } }); Edit : $.ajax calls the "success" function and returns immediately, it doesn't "poll" for changes.. (timeline column for ajax

Cannot store a value in local storage

这一生的挚爱 提交于 2019-12-04 07:14:45
问题 I have fetched a list of items from web service, now i want to store the item_name on which I have clicked. I cannot store that item name, if its "bread butter" , it stores only "bread". What shall i do now? <script> var sub_catidall = []; var sub_catnameall = []; function selected_index(sub_cat_name_all) { alert("selected sub category" + sub_cat_name_all); //window.localStorage.setItem("current_sub_id_all",sub_cat_id_all); window.localStorage.setItem("DishName", sub_cat_name_all); window

Error when echo $_GET[“jsoncallback”]

ぃ、小莉子 提交于 2019-12-04 06:58:29
问题 <?php $query = mysql_query("Select id, name From table"); while($row = mysql_fetch_array($query)) { echo $_GET["jsoncallback"] . '(<option value='.$row['id'].'>'.$row['name'].'</option>)'; } ?> When I echo result, it is error, how to fix it? 回答1: Since you didn't write exactly what you're trying to do, i'm guessing you're trying to return a list of HTML options that a JS callback function will place in your document. try this: <?php $options = ''; $query = mysql_query("Select id, name From

MVC pass JSON ViewModel to View

痞子三分冷 提交于 2019-12-04 06:57:34
I have an MVC application that I'm using various JsonResult endpoints to populate the javascript ViewModel. I have been using several jQuery Ajax requests to populate the model, but I'd like as much of the inital model to be passed to the view on the server. The ViewModel has 3-5 pieces (depending on where the user is in the application): Basic page links, these don't change very often and could be the exact same throughout the entire user's session User notifications. User data. (optional) Viewable data (optional) misc data I'm currently using this code to load the first three pieces: $

Implementing JSONP in Spring MVC 3.2

北慕城南 提交于 2019-12-04 06:13:58
I understand that custom filters can be used in earlier version of Spring MVC to implement JSONP. Additionally this example describes a method to implement JSONP in Spring MVC 3.1 by extending the MappingJacksonHttpMessageConverter class and modifying the domain objects. Is there a simpler (or conventional) method to address JSONP in Spring MVC 3.2 besides using the above methods? I did not see JSONP addressed at all in the Spring 3.2 documentation. simpler way like this @RequestMapping(value = "/jsonp", method = RequestMethod.GET) @ResponseBody public String jsonp(@RequestParam("c")String

Angularjs $http get method for JSONP data without CALLBACK parameter [duplicate]

假装没事ソ 提交于 2019-12-04 06:12:54
问题 This question already has an answer here : Not a Legal JSONP API — How to get data without CALLBACK parameter (1 answer) Closed last year . I have problem by printing in the table, some JSON that is on the server. This is my JSON process([ { "name": "A", "value": "41" }, { "name": "B", "value": "71" }, { "name": "C", "value": "20" }],"2017.07.11 15:48:33"); My controller: myApp.controller('liveTable', function ($scope, $http) { $http.get('http://something.com/get.php?jsonp=2017') .then

jQuery .ajax() with jsonp not invoking success callback function

对着背影说爱祢 提交于 2019-12-04 06:05:28
I have a facebook iframe application that makes a cross domain request to my server and requests data in JSONP format. This is my client side code: jQuery.ajax({ url: '***', type: 'post', data: { method: 'set_user_prizes' }, dataType: 'jsonp', jsonp: false, jsonpCallbackString: 'callback123', success: function(data, textStatus, jqXHR){ console.log('success_function'); console.log(data); } }); The problem is my success callback method isn't being invoked and I'm not sure why. Using Firebug I can see my server's response: callback123({"success":true,"associated_prizes":[{"prizes_id":"6"},{

Subsequent JSONP requests give status 404 despite GET status 200

点点圈 提交于 2019-12-04 06:00:35
问题 So I am able to make the first JSONP request to the yelp API work to return business data for me, but any subsequent requests I make lead to the callback for failure that logs a status code of 404. Yet when I pull up the network tab in Chrome Dev Tools I see that all the subsequent GET requests I made all have status 200 and I do see valid response data. How can that be when the callback for failure was called? How can I fix this? I'd like to be able to receive data more than once. The

在ASP.NET MVC3 中利用JSONP跨域登录WEB系统

ぃ、小莉子 提交于 2019-12-04 05:55:44
在信息系统开发的时,根据相关业务逻辑难免会多系统之间互相登录。一般情况下我们需要在多系统之间使用多个用户名和密码。这样客户就需要在多个系统之间重复登陆。每次登录都需要输入用户名和密码。最近比较流行的就是OAuth。新浪微博这个开放系统做的就很好。但OAuth并非本文讨论范畴。这里主要讨论jQuery1.5 jsonp 在Asp.net MVC3 中的应用。 本文应用场景: 假设您的开发团队欲为某集团公司开发一整套信息管理系统,目前首要开发的就是一套订单系统和一套内部OA系统。前提是这两套系统使用同一套数据库。只是两个不同的MVC3.0 Web项目。也就是说会在同一个IIS上部署两个虚拟目录。 我们的目标是在不使用WCF、WebService 等技术实现跨域登录。也就是说用户用同一个帐号登录了订单系统,那么客户就可以直接登录OA系统。而不需要在OA系统上再输入一次用户名和密码。反之亦成立。 jQuery1.5 JSONP 使用: < script type = " text/javascript " > 2 $( function () { 3 var oAUri = " @ViewBag.OAVRUri " ; 4 var user = " @ViewBag.User " ; 5 var pwd = " @ViewBag.PassWord " ; 6 7 $.ajax({ 8