jqgrid

Uncaught TypeError: Cannot read property 'replace' of null jqgrid

由 做~自己de王妃 提交于 2019-12-25 05:21:23
问题 i am new to programming. when i try this below function, it works well unless there is a blank cell in the column. if there is any blank value in the cell then it is not working and then entire page goes blank. please help me to fix. function growth (cellvalue) { var gcolor; var numval=cellvalue var val = Number(numval.replace("%","")); if (val<0) { gcolor = 'red'; } else if (val>0) { gcolor = 'green'; } return '<span class="cellWithoutBackground" style="background-color:' + gcolor + ';">' +

JQgrid data property returns [] on a grid with data

由 只谈情不闲聊 提交于 2019-12-25 05:13:40
问题 When I try: $(MyGrid).jqGrid('getGridParam'); On a grid with 24 elements, data has nothing. Do you know under which conditions this might happen? (related with JQGrid: Get elements from different pages) 回答1: The padameter data hold local data of the grid. It will be not filled (stay empty array) if you use remote source ( datatype: "json" or datatype: "xml" ) without loadonce: true option. In the case jqGrid just fill the grid (HTML table) with the page of data returned from the server. In

JqGrid DataBinding exception while exporting to excel file

由 三世轮回 提交于 2019-12-25 05:03:35
问题 I am trying to export JqGrid to excel so i follow this instruction and i use it like at below. var grid = new JqGridModelParticipiant().JqGridParticipiant; var query = db.ReservationSet.Select(r => new { r.Id, Name = r.Doctor.Name, Identity = r.Doctor.Identity, Title = r.Doctor.Title.Name, Total = r.TotalTL, Organization = r.Organization.Name }); grid.ExportToExcel(query,"file.xls"); And i get below exception on the line of " grid.ExportToExcel(query,"file.xls");" Data binding directly to a

JQGrid date formatter not applying local time offset correctly : Grails

由 泄露秘密 提交于 2019-12-25 05:01:40
问题 I have a simple table in the DB (MySql) which contains the date in the standard Date format. I am doing a simple select in grails and rendering the output to a JSON format for the jqgrid to pick up. In jqgrid I have the following cell definition: {name : 'processedDate',width:110,formatter:'date', formatoptions: {srcformat: 'Y-m-dTH:i:sZ',newformat:'d/m/Y H:i'}} The date I expect to see on the screen is 31/03/2013 22:06 which is what is displayed in the mysqlworkbench which I get from another

JQGrid date formatter not applying local time offset correctly : Grails

由 感情迁移 提交于 2019-12-25 05:01:34
问题 I have a simple table in the DB (MySql) which contains the date in the standard Date format. I am doing a simple select in grails and rendering the output to a JSON format for the jqgrid to pick up. In jqgrid I have the following cell definition: {name : 'processedDate',width:110,formatter:'date', formatoptions: {srcformat: 'Y-m-dTH:i:sZ',newformat:'d/m/Y H:i'}} The date I expect to see on the screen is 31/03/2013 22:06 which is what is displayed in the mysqlworkbench which I get from another

jqgird: problems paging from an existing table

由 橙三吉。 提交于 2019-12-25 04:50:40
问题 I had started another post wanting to know how to use jqgrid when you are converting a html table to grid. I've got that working. However the data is not paged. It converts table to grid, displays the pager controls and all; however it shows page 1 of 0 . The data is paged only when I select a different page size from the drop-down. Why is the data not paged? Do I need to call anything else to make this happen? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org

How to do server side Sorting/Paging in jqgrid in ASP.net MVC

由 為{幸葍}努か 提交于 2019-12-25 04:39:09
问题 I am constructing a jqgrid with the following code: $(document).ready(function () { $("#Data").jqGrid({ url: '/Home/LoadData', loadonce:true, datatype: "json", mtype: "GET", colNames:["ID"], colModel: [ { name: "Id",index:'ID',width:800, align: "center"} ], pager: "#Pager", rowNum: '10', rowList: [10, 20, 30], sortname: "ID", sortorder: "asc", height: "auto", gridview:true, sortname: "ID", viewrecords: true, caption: "My First Grid", loadComplete: function (data) { var $this = $(this),

Want to fix some columns

由 旧城冷巷雨未停 提交于 2019-12-25 04:21:32
问题 I want to fix some columns so that user cannot drag and drop these columns and cannot reorder these columns also.Is it doable how can i do it. 回答1: There is code inside grid.jqueryui.js that uses the jQuery UI Sortable Interaction to enable drag-and-drop columns. The following selector determines which columns can be dragged-and-dropped: "items": '>th:not(:has(#jqgh_'+tid+'_cb'+',#jqgh_'+tid+'_rn'+',#jqgh_'+tid+'_subgrid),:hidden)', So basically the selector will choose any column header that

Want to fix some columns

由 耗尽温柔 提交于 2019-12-25 04:20:03
问题 I want to fix some columns so that user cannot drag and drop these columns and cannot reorder these columns also.Is it doable how can i do it. 回答1: There is code inside grid.jqueryui.js that uses the jQuery UI Sortable Interaction to enable drag-and-drop columns. The following selector determines which columns can be dragged-and-dropped: "items": '>th:not(:has(#jqgh_'+tid+'_cb'+',#jqgh_'+tid+'_rn'+',#jqgh_'+tid+'_subgrid),:hidden)', So basically the selector will choose any column header that

Builtin search panel disable whole grid with search panel. 2 more questions

由 一世执手 提交于 2019-12-25 04:18:02
问题 1 - Is it possible to change the layout of Add and Edit popups? 2 - How to disable navigation in the Edit popup?. Right and left buttons to navigate through records. 3 - I am testing JQGrid built in search. Problem is when ever I click on that small search icon popup disable whole grid with it search panel on top of it. Tried alot but no success. Note: All the other panels like Edit, Add etc are working fine jQuery().ready(function () { jQuery("#list10").jqGrid({ //url: 'server.php?q=2', data
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