jqgrid-asp.net

How to jsonify “Add” post/parameters for jqGrid

随声附和 提交于 2019-12-02 09:56:08
This one's killing me. I've read through a lot of Oleg 's comments, and through the documentation , but I think I'm overlooking something really simple. I have a jqGrid populated by calling a webmethod that returns JSON. We're good there. I'm using the Navigator for my "Add" button, and using onSelectRow w/ jqGrid.editRow() for my editing. I get the dialog box when clicking the "Add" button, and can fill everything in. However, I get a error Status: 'Internal Server Error'. Error code: 500 return message after clicking the Submit button. Using Firebug, the Response is {"Message":"Invalid JSON

how to implement autocomplete dropdownlist in inline JqGrid editing [closed]

江枫思渺然 提交于 2019-12-02 08:06:56
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . please,share code for implementing. enter image description here refer the Image please...the same way i need to implement.. please help 回答1: See the demo from the answer which uses select2, which is more powerful as jQuery UI autocomplete. See the demo from more old answer which

Jqgrid. Locate rowId from key value

岁酱吖の 提交于 2019-12-01 11:35:40
I've got a basic jqgrid implementation. $('.fsJqGrid').jqGrid({ datatype: "local", height: 175, colNames: ['FeatureId', 'Name', ''], colModel: [ { name: 'FeatureId', index: 'FeatureId', width: 75, align: 'left', sorttype: "int", hidden: true, key: true }, { name: 'Name', index: 'Name', width: 180 }, { name: 'tools', index: 'tools', width: 150} ] }); function FeatGridAddRow(jqTableName, feature) { ///<summary>Adds a row of data to a Feature JQGrid</summary> var RowId = $("#" + jqTableName).jqGrid('getGridParam', 'reccount'); feature.tools = 'MyToolHtml'; $("#" + jqTableName).jqGrid('addRowData'

Getting value of a column on click of a row in jqGrid

丶灬走出姿态 提交于 2019-12-01 11:25:09
I am using Asp.Net/C# , in one of my page I am using jqGrid to display list of users to the Admin , The jqGrid contains following columns User Code First Name Middle Name Last Name Email Here is my markup <cc1:JQGrid ID="ModifyAccountUserDetailsjqGrid" AppearanceSettings-Caption="User Details" runat="server" Width=800 DataSourceID=ModifyAccountDataSource> <Columns> <cc1:JQGridColumn HeaderText="User Code" ShowToolTip=false PrimaryKey=true DataField="UserCode"></cc1:JQGridColumn> <cc1:JQGridColumn HeaderText="First Name" ShowToolTip=false DataField="FirstName"></cc1:JQGridColumn> <cc1

Jqgrid. Locate rowId from key value

[亡魂溺海] 提交于 2019-12-01 08:33:16
问题 I've got a basic jqgrid implementation. $('.fsJqGrid').jqGrid({ datatype: "local", height: 175, colNames: ['FeatureId', 'Name', ''], colModel: [ { name: 'FeatureId', index: 'FeatureId', width: 75, align: 'left', sorttype: "int", hidden: true, key: true }, { name: 'Name', index: 'Name', width: 180 }, { name: 'tools', index: 'tools', width: 150} ] }); function FeatGridAddRow(jqTableName, feature) { ///<summary>Adds a row of data to a Feature JQGrid</summary> var RowId = $("#" + jqTableName)

Jqgrid selection issue with duplicates columns

人走茶凉 提交于 2019-12-01 01:54:51
I m facing a issue in Jqgrid with row selection. I have duplicated rows in the grid. whenever i select the duplicate or it select the first record of that duplicate row. It's common problem for many people who start to use jqGrid. Such strange selection behavior exist if you fill the grid with rows having id duplicates . So it's extremely important to understand how the ids from your input will be used by jqGrid . jqGrid use internally HTML markup to display the grid. It uses <table> , <tbody> (the body of the table - has no column headers), <tr> (row of the table) and <td> (table of the table

Change the Sequence of JqGrid Columns

陌路散爱 提交于 2019-11-30 15:24:35
I wanted to change the grid column sequence dynamically. For e.g. By default the grid will be loaded in LoginId, FirstName and LastName sequence. Based on some condition, I need to change the FirstName and LastName sequence. Is there any way I can do this? I tried doing like: {name:'UserName',index:'UserName',width:82,sortable:false}, if(true) { {name:'FirstName',index:'FirstName',width:65,sortable:false}, {name:'LastName',index:'LastName',width:65,sortable:false}, } else { {name:'LastName',index:'LastName',width:65,sortable:false}, {name:'FirstName',index:'FirstName',width:65,sortable:false},

how to set postData in jqgrid AFTER it has been constructed?

别说谁变了你拦得住时间么 提交于 2019-11-30 14:19:36
I generate my jqgrid from model class which I pass into view. I get constructed and working jqgrid. However, I want to set postData on one view, where I use jqGrid, from script in that view, after I call helper for creating jqgrid, without having to change whole partial view which creates jqgrid. I tried running $("#@Model.Id").jqGrid('setGridParam', { postData: { test: 233} }); and $("#@Model.Id").setGridParam({ postData: { test: 233} }); but without error or any result. If I set postData in jqgrid parameters (in partial view where it is constructed, it works. I also checked that grid exists,

jqgrid: several questions - matrix display

不问归期 提交于 2019-11-30 07:53:42
问题 I have data of matrix stored in table as below tables: MatrixDimensions - MatrixId, NoOfRows, NoOfCol MatrixValues - MatrixId, RowNo, ColNo, Value How can I make jqGrid to take no. of rows & columns dynamically and also display the serialized data in matrix? Is there a direct way or will I have to implement for loops to upload the data in matrix? Can I display rows as columns and columns as rows (so having column headers vertically aligned)? Can I enable only inline editing and disable form

How to change a row's particular cell value in jqgrid

女生的网名这么多〃 提交于 2019-11-30 06:29:43
问题 I want to change a particular rows's cell value, I have the row Id. and I have tried using the following. But it doesnt work. $("#my-jqgrid-table").jqGrid('setCell',rowId,'Currency', '12321'); I am using loadonce: true Please can someone help me with this. Thanks 回答1: You can use getRowData and setRowData methods to achieve this (they are working directly with data array ): var rowData = $('#my-jqgrid-table').jqGrid('getRowData', rowId); rowData.Currency = '12321'; $('#my-jqgrid-table')