jpql

I am writing a JPQL query which queries based on a Categories collection. My categories can be null and hence I am checking using :categories=NULL. @Query("Select v from Vendor v join v.org vorg join v.categories cats WHERE vorg.email =:email AND (cats in :categories or :categories = NULL)") Set<Vendor> filterVendors(@Param("emailId") String emailId, @Param("categories") Set<Category> categories); The above works fine when categories is NULL. However, when categories is more than one value I get the error java.sql.SQLException: Operand should contain 1 column(s) And the hibernate relevant

I've the following DB model: Category -< ProductCategory >- Product -< Variant ( Category has many-to-many relationship with Product and Product has one-to-many relationship with Variant ) Now I need to get all Category records that have product with active variants. I'm getting these objects via the following JPQL query: @Query("select distinct c from Category c join c.products as p join p.variants as pv where pv.active = true") It works well - returns categories accurately - however every single Category contains all the products - not only these with active variants. How can I filter out

I'm performing a Query to my DB in JPA . The Query "queries" 4 tables, and the result aggregates columns from that different tables. My Query is something like: Query query = em.createQuery("SELECT o.A, o.B, o.C, e.D, c.E FROM Table1 o, Table2 i, Table3 e, Table4 c WHERE o.X = i.X AND i.Y = e.Y AND i.Z = c.Z"); How can I get the query result and extract the different fields? I created a class (MyObject) that represents each item of the result list, and I want to convert the query.getResultList() into a List< MyObject> . How can I do it? This kind of query returns a List<Object[]> . So you just

Is there a possiblity in JPA 2.0 to set a collection for in-clause in jpql-query? (I'm using EclipseLink) The next example fails: TypedQuery<Person> q = em.createQuery("select p from Person p where p.name in (?1)", Person.class); List<String> names = Arrays.asList(new String[] { "Bill Gates", "Steve Jobs" }); // THIS FAILS q.setParameter(1, names); List<Person> persons = q.getResultList(); for (Person p: persons) { System.out.println(p.getName()); } Is there another way to do it? Here is what the JPA 2.0 specification says about IN expressions: 4.6.9 In Expressions The syntax for the use of

Is it possible to write & call user-defined function in JPQL? It's not supported by JPA specification itself, however, some JPA implementations may provide such an extension. For example, in Hibernate you can subclass a Dialect and define customs SQL functions by calling registerFunction() . Many dialect-specific functions are already defined this way. Is it possible to write & call user-defined function in JPQL? The short answer - No. The long answer is that native functions cannot be referenced in JPQL queries, as JPQL as a very well defined grammar. For instance, the SELECT clause of a JPQL

I have following problem: when I try to delete an entity that has following relation: @OneToMany(mappedBy="pricingScheme", cascade=CascadeType.ALL, orphanRemoval=true) private Collection<ChargeableElement> chargeableElements; with a CrudRepository through a provided delete method it removes the entity along with its all chargeable elements which is fine. The problem appears when I try to use my custom delete: @Modifying @Query("DELETE FROM PricingScheme p WHERE p.listkeyId = :listkeyId") void deleteByListkeyId(@Param("listkeyId") Integer listkeyId); it says: com.mysql.jdbc.exceptions.jdbc4

How to create a request for a complex query in JpaRepository with the use of @Query ? I am concerned about the relationships between entities. They may affect the preparation of the request. Needed query SQL, my version @Query: Ok so more advisable way of declaring your query would be : @Query( "SELECT bu.email " + "FROM Businesscentr bu INNER JOIN bu.bannersSet bs INNER JOIN bs.clicks c " + "WHERE c.fullNameClient = :fullNameClient" // optional ) You only use the old join style when you have to join by non-primarykey values. 来源： https://stackoverflow.com/questions/41897719/how-to-create-a