jpa-2.0

I'm trying to decide whether to switch from having Hibernate sprinkled all over to using JPA2.0 and thus be provider portable. 1.Does JPA2.0 support custom user-types? 2.I'm on the verge of implementing Terracotta as a second-level cache to Hibernate with its clustering abilities mainly in mind. I would imagine, but I don't actually know, that JPA2.0 also defines a spec for second-level cache providers. If I'm right, does Terracotta implement it? (If someone could point me to a getting started with Terracotta and JPA I'd appreciate it). Thanks in advance, Ittai Does JPA2.0 support custom user

I'm working on a JPA Compliancy kit for my internship... Part of that kit involves testing correct implementation of corner cases. @ManyToMany has a mappedBy attribute. JPA states that: String mappedBy - The field or property that owns the relationship. Required unless the relationship is unidirectional. No default is given - the default column is empty. Given a bidirectional @ManyToMany - this example is from the JPA 2.0 JSR-317 specification itself! Customer @ManyToMany @JoinTable(name="CUST_PHONES") public Set<PhoneNumber> getPhones() { return phones; } PhoneNumber @ManyToMany(mappedBy=

I have a query SELECT d.name, count(e.id) FROM department d LEFT OUTER JOIN employee e on e.department_id = d.id and e.salary > 5000 and how i can convert this to jpa right now i have: CriteriaQuery<Object[]> criteria = builder.createQuery(Object[].class); Root<Department> root = criteria.from(Department.class); Path<String> name = root.get("name"); Expression<Long> empCount = builder.count(root.get("employees").get("id")); criteria.multiselect(name,empCount); TypedQuery<Object[]> query = em.createQuery(criteria); I simplified both examples by removing ordering and grouping can anyone tell me

I’m using JPA 2.1, Hibernate 4.3.6.Final, and MySQL 5.5.37. How do I write a JPQL query that does a join? I’m trying below final String jpqlQuery = "SELECT m FROM Message m LEFT JOIN MessageReadDate mr " + " INNER JOIN m.group g " + " LEFT JOIN g.classroom c " + " LEFT JOIN c.ROSTER u WHERE " + " u.USER = :recipient AND " + " u.ENABLED = 1 AND " + " c.ENABLED = 1 AND " + " g.NAME = '' AND " + " m.author <> :author"; Query query = m_entityManager.createQuery(jpqlQuery); but getting the error “Path expected for join! … Invalid path: 'g.classroom'”. org.hibernate.hql.internal.ast.ErrorCounter -

I am using JPA 2.0. (EclipseLink 2.0.2) If an entity contains relations, for example: @OneToMany(cascade = CascadeType.ALL, mappedBy = "userId") private Collection<Blog> blogCollection; I am getting the following error when I am sending it through RPC: com.google.gwt.user.client.rpc.SerializationException: Type 'org.eclipse.persistence.indirection.IndirectList' was not included in the set of types which can be serialized by this SerializationPolicy or its Class object could not be loaded. For security purposes, this type will not be serialized.: instance = {[]} In general all the Persistence

@TableGenerator(name="Emp_Gen",table="ID_GEN", pkColumnName = "GEN_NAME",pkColumnValue = "Employee_GEN",valueColumnName = "GEN_VAL",initialValue = 1000,allocationSize = 100) Every is ok,but initialValue is not effective. Below is the table named "employee"(Note:MySql,Hibernate-JPA is used) I think the first row 'id' is 1000,not 1,right?But if it's 1,the second should be 101.... Who can help me a stupid man? What it comes to the first value being 1 instead of 1001 that is Hibernate bug HHH-4228 , with status Won't fix . Correct first value in your case is 1001 instead of 1000, because

I want to know if JPQL is capable of doing a case-insensitive search on a collection of string. Scenario: Table1: Column1 (int) | Column2(string) 1 ABC 2 XYZ I am looking for a JPQL query which does something like this from Table1 a where upper(a.column2) in upper(:listOfCol2Values) Can I achieve this without having to change the case at the application code where i set the collection. Cheers. No you cannot. Reason is that UPPER and LOWER operate to the strings, so they do not take collection as argument. You can always do : from Table1 a where (upper(a.column2) = upper(:value1) or upper(a