jodatime

I want to parse strings like "8y5d" or "-6y144d" into a joda time period object. Thanks Use the PeriodFormatterBuilder : PeriodFormatter yearsAndMonths = new PeriodFormatterBuilder() .printZeroRarelyFirst() .appendYears() .appendSuffix("y", "y") .printZeroRarelyLast() .appendDays() .appendSuffix("d", "d") .toFormatter(); System.out.println(yearsAndMonths.parsePeriod("8y5d").toDurationFrom(new DateTime()).getStandardDays()); 来源： https://stackoverflow.com/questions/11669255/how-do-i-parse-a-string-like-8y5d-to-a-period-object-in-joda-time

I use JodaTime library for time operations. I have two dates: Date One: DateTime time_server = new DateTime(server_time_milisecs). withZone(DateTimeZone.forID("Europe/Zurich")); //+0100 Shows: 2013-01-27 13:44:42 Date two: DateTime time_local = new DateTime(DateTime.now()). withZone(DateTimeZone.getDefault()); //Have "Europe/Moscow" timezone +0400 Shows: 2013-01-27 16:41:47 I need to find real interval including timezone Interval interval = new Interval(time_local, time_server); Long.toString(interval.toDurationMillis())); Result: 174040 miliseconds - NOT CORRECT int secs = Seconds

I am using Dozer to map between a Document class to DocumentManagementBean class, both of my own making. Both have a property, with getters and setters, of Joda DateTime type, called dateAdded. When Document object d has property dateAdded =x, calling mapper.map(d, DocumentManagementBean.class) all fields get auto-mapped correctly (since I have full control over code base I am able to get away with no dozer-config and rely simply on matching property names), EXCEPT the dateAdded field, where the new DocumentManagementBean dmb ends up with the current DateTime in its dateAdded property, instead

How can I convert a java.util.Date to String using DateTimeFormatter dateTimeFormatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss") The Date object which I get is passed DateTime now = new DateTime(date); assylias If you are using Java 8, you should not use java.util.Date in the first place (unless you receive the Date object from a library that you have no control over). In any case, you can convert a Date to a java.time.Instant using: Date date = ...; Instant instant = date.toInstant(); Since you are only interested in the date and time, without timezone information (I assume

By default, the toString method of Instant uses the DateTimeFormatter.ISO_INSTANT formatter. That formatter won’t print the digits for fraction-of-second if they happen to be 0. java-time examples: 2015-10-08T17:13:07.589Z 2015-10-08T17:13:07Z Joda-Time examples (and what I'd expect from java.time): 2015-10-08T17:13:07.589Z 2015-10-08T17:13:07.000Z This is really frustrating to parse in some systems. Elasticsearch was the first problem I encountered, there's no pre-defined format that supports optional millis, but I can probably work around that with a custom format. The default just seems

I have a ISO 8601 date, lets say: 2012-01-19T19:00-05:00 My machine timezone is GMT+1 I'm trying to use joda to parse this and convert it to the respective GMT date and time: DateTimeFormatter simpleDateISOFormat = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mmZZ"); creationDate = simpleDateISOFormat.withZone(DateTimeZone.UTC) .parseDateTime(date + "T" + time) .toDate(); Now the result that I'm expecting is Fri Jan 20 00:00:00 CET 2012 Instead I'm getting: Fri Jan 20 01:00:00 CET 2012 I believe this is because I'm in timezone GMT + 1 . Is there a way to parse the date faking to be in a

I'm currently testing out some webapp technologies in a java project and was wondering why the pages sometimes load fast and sometimes take almost 5s to load. I finally found out that it is this line LocalDateTime now = new LocalDateTime(); When it's called the first time, it takes forever to get the current time. When called after that, even somewhere completely different, it's pretty fast however. I'm currently using <dependency> <groupId>joda-time</groupId> <artifactId>joda-time</artifactId> <version>1.6.2</version> </dependency> Has anyone had any similar experience? Really stuck here.. I

I've been bashing my head with this proof of concept for a while. I want to consume a REST endpoint that returns JSON payload with an ISO8601 UTC timestamp: { ... "timestamp" : "2014-08-20T11:51:31.233Z" } and I want to consume it using a command line Java client written as a Jersey 2 client with Jackson/Spring Boot. The marshalling POJO is defined as follows: @JsonIgnoreProperties(ignoreUnknown = true) @JsonInclude(Include.NON_NULL) public class GreetingResource { @JsonProperty("timestamp") private DateTime date; ... } After following recommendations shown in: https://jersey.java.net

How can I get the following format: 2015-01-31T00:00:00Z (ISO8601 GMT date format) Out of a DateTime object in joda time (java) ? Eg. DateTime time = DateTime.now(); String str = // Get something like 2012-02-07T00:00:00Z Thanks! :) The JODA Javadoc indicates that toString for DateTime outputs the date in ISO8601. If you need to have all of the time fields zeroed out, do this: final DateTime today = new DateTime().withTime(0, 0, 0, 0); System.out.println(today); That will include milliseconds in the output string. To get rid of them you would need to use the formatter that @jgm suggests here.