jaxb

Caused by: java.lang.ClassNotFoundException: javax.xml.bind.Validation

强颜欢笑 提交于 2020-05-04 06:06:05
Caused by: java.lang.ClassNotFoundException: javax.xml.bind.Validation JAXB API是java EE 的API,因此在java SE 9.0 中不再包含这个 Jar 包。 java 9 中引入了模块的概念,默认情况下,Java SE中将不再包含java EE 的Jar包 而在 java 6/7 / 8 时关于这个API 都是捆绑在一起的 引入下面依赖即可 jaxb-api maven地址: http://mvnrepository.com/artifact/javax.xml.bind/jaxb-api jaxb-impl maven地址: http://mvnrepository.com/artifact/com.sun.xml.bind/jaxb-impl jaxb-core maven地址: http://mvnrepository.com/artifact/com.sun.xml.bind/jaxb-core activation maven地址: http://mvnrepository.com/artifact/javax.activation/activation <dependency> <groupId>javax.xml.bind</groupId> <artifactId>jaxb

Java 注解指导手册 – 终极向导

若如初见. 提交于 2020-05-02 18:16:29
原文链接 原文作者:Dani Buiza 译者:Toien Liu 校对:深海 编者的话:注解是java的一个主要特性且每个java开发者都应该知道如何使用它。 我们已经在Java Code Geeks提供了丰富的教程, 如 Creating Your Own Java Annotations , Java Annotations Tutorial with Custom Annotation 和 Java Annotations: Explored & Explained . 我们也有些文章是关于注解在不同类库中的应用,包括 Make your Spring Security @Secured annotations more DRY 和 Java Annotations & A Real World Spring Example . 现在,是时候汇总这些和注解相关的信息到一篇文章了,祝大家阅读愉快。 目录 什么是注解 介绍 消费器 注解语法和注解元素 在什么地方使用 使用案例 内建注解 Java 8 与注解 自定义注解 提取注解 注解集成 使用注解的知名类库 小结 下载 资料 在这篇文章中我们将阐述什么是Java注解,它们如何工作,怎么使用它们。 我们将揭开Java注解的面纱,包括内建注解或称元注解,还将讨论Java8中与之相关的的新特性。 最后,我们将实现自定义的注解

How to deserialize xml with jaxb using builder class

痴心易碎 提交于 2020-04-30 09:17:21
问题 I want to deserialize xml with Jaxb and using builder class Below is my xml input <Test> <Head>Hey</Head> <Message code="MNP">[Hey How are yu] <care>test2</care> <care>test1</care> </Message> </Test> This Xml has mixed content. Below is classes which I used to deserialize: @XmlRootElement(name = "Test") public class Test { private final String header; private final List<Message> message; private Test(final Builder builder) { this.header = builder.header.orElse(null); this.message = builder

How to deserialize xml with jaxb using builder class

时光怂恿深爱的人放手 提交于 2020-04-30 09:17:06
问题 I want to deserialize xml with Jaxb and using builder class Below is my xml input <Test> <Head>Hey</Head> <Message code="MNP">[Hey How are yu] <care>test2</care> <care>test1</care> </Message> </Test> This Xml has mixed content. Below is classes which I used to deserialize: @XmlRootElement(name = "Test") public class Test { private final String header; private final List<Message> message; private Test(final Builder builder) { this.header = builder.header.orElse(null); this.message = builder

import com.sun.xml.internal.ws.client.ClientTransportException, can't read this import

China☆狼群 提交于 2020-04-30 07:49:38
问题 I can't resolve this problem, i try to do import com.sun.xml.internal.ws.client.ClientTransportException but i can't import it. Exception in thread "main" com.sun.xml.internal.ws.client.ClientTransportException: The server sent HTTP status code 404: Not Found at com.sun.xml.internal.ws.transport.http.client.HttpTransportPipe.checkStatusCode(HttpTransportPipe.java:296) at com.sun.xml.internal.ws.transport.http.client.HttpTransportPipe.createResponsePacket(HttpTransportPipe.java:245) at com.sun

import com.sun.xml.internal.ws.client.ClientTransportException, can't read this import

偶尔善良 提交于 2020-04-30 07:48:22
问题 I can't resolve this problem, i try to do import com.sun.xml.internal.ws.client.ClientTransportException but i can't import it. Exception in thread "main" com.sun.xml.internal.ws.client.ClientTransportException: The server sent HTTP status code 404: Not Found at com.sun.xml.internal.ws.transport.http.client.HttpTransportPipe.checkStatusCode(HttpTransportPipe.java:296) at com.sun.xml.internal.ws.transport.http.client.HttpTransportPipe.createResponsePacket(HttpTransportPipe.java:245) at com.sun

SpringMVC关于json、xml自动转换的原理研究[附带源码分析](使用JAXB转换XML)

别说谁变了你拦得住时间么 提交于 2020-04-26 23:42:15
前言 SpringMVC是目前主流的Web MVC框架之一。 如果有同学对它不熟悉,那么请参考它的入门blog: http://www.cnblogs.com/fangjian0423/p/springMVC-introduction.html 现象 本文使用的demo基于maven,是根据入门blog的例子继续写下去的。 我们先来看一看对应的现象。 我们这里的配置文件 *-dispatcher.xml中的关键配置如下(其他常规的配置文件不在讲解,可参考本文一开始提到的入门blog): (视图配置省略) < mvc:resources location ="/static/" mapping ="/static/**" /> < mvc:annotation-driven /> < context:component-scan base-package ="org.format.demo.controller" /> pom中需要有以下依赖(Spring依赖及其他依赖不显示): < dependency > < groupId > org.codehaus.jackson </ groupId > < artifactId > jackson-core-asl </ artifactId > < version > 1.9.13 </ version > </ dependency

002-02-RestTemplate-初始化调用流程

我的未来我决定 提交于 2020-04-18 07:44:51
一、简述   调用 RestTemplate 的默认构造函数,RestTemplate 对象在底层通过使用 java.net 包下的实现创建 HTTP 请求,可以通过使用 ClientHttpRequestFactory 指定不同的HTTP请求方式。   使用的是spring5.0.1   默认使用 SimpleClientHttpRequestFactory,是 ClientHttpRequestFactory 实现类。如下流程: 1)使用默认构造方法new一个实例   RestTemplate template = new RestTemplate(); 2)RestTemplate 内部通过调用 doExecute 方法,首先就是获取 ClientHttpRequest doExcute核心处理 // 通过ClientHttpRequestFactory工厂生产一个ClientHttpRequest ClientHttpRequest request = this .createRequest(url, method); if (requestCallback != null ) { // 封装了请求头和请求体,使用了HttpMessageConverter requestCallback.doWithRequest(request); } //

Spring boot - Server did not recognize the value of HTTP Header SOAPAction

折月煮酒 提交于 2020-04-17 20:04:47
问题 I want to consume soap service using jaxb. The generated request from jaxb is <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"> <SOAP-ENV:Header/> <SOAP-ENV:Body> <ns2:Add xmlns:ns2="http://tempuri.org/"> <ns2:intA>10</ns2:intA><ns2:intB>20</ns2:intB> </ns2:Add> </SOAP-ENV:Body> </SOAP-ENV:Envelope> But the response is a soap exception as stated in the title. Caused by: org.springframework.ws.soap.client.SoapFaultClientException: System.Web.Services.Protocols

JAXB: Unmarshal to subclass based on element value

时间秒杀一切 提交于 2020-04-05 05:00:09
问题 I am trying to parse an XML file using JAXB which contains a list of items. The class of the items depends on the value of an element in the XML. This is a legacy system and I can't easily change the input format. For example, given the following XML and class definitions: <root> <type>a</type> <item> <a>a1</a> </item> <item> <a>a2</a> </item> </root> @XmlRootElement(name = "root") public class Root { @XmlElement String type; @XmlElement(name="item") List<Item> items; } public class Item {}