ipv6

I used IPAddressUtil.isIPv6LiteralAddress (ipAddress) method to validate IPv6, but this method fails for ipv6-address/prefix-length format (format is mentioned in RFC 4291 section 2.3) of IPV6. Could anyone know any validators which validate " ipv6-address/prefix-length " format? Legal representations of IPV6 ABCD:EF01:2345:6789:ABCD:EF01:2345:6789 2001:DB8:0:0:8:800:200C:417A FF01:0:0:0:0:0:0:101 0:0:0:0:0:0:0:1 0:0:0:0:0:0:0:0 2001:DB8::8:800:200C:417A FF01::101 ::1 :: 0:0:0:0:0:0:13.1.68.3 0:0:0:0:0:FFFF:129.144.52.38 ::13.1.68.3 FFFF:129.144.52.38 2001:0DB8:0000:CD30:0000:0000:0000:0000/60

Is there a way in Java to tell it to return IPv6 only? I've tried everything and can't get it to work. try { InetAddress inet = InetAddress.getByName(hostName); boolean status = inet.isReachable(5000); if (status) { System.out.println(inet.getCanonicalHostName() + " Host Reached\t" + java.net.Inet6Address.getByName(hostName).getHostAddress()); } else { System.out.println(inet.getCanonicalHostName() + " Host Unreachable"); } } catch (UnknownHostException e) { System.err.println("Host does not exists"); } catch (IOException e) { System.err.println("Error in reaching the Host"); } The line I use

6PE即通过mpls以隧道的方式传输IPv6报文。 6PE信令，PE从CE上收到IPv6单播路由，PE为该路由分配一个MPLS标签，再通告给RR，即带标签的IPv6单播路由。 　　　　 另外ldpv4在PE、P之间正常分发标签。 PE给RR的特定iBGP信息: (前缀、标签、下一跳) iBGP Route IPv6 LU (AFI=2,SAFI=4) NLRI:fc00::10:2:34:0/112 标签 24040，MED 100 下一跳：::ffff:172.16.0.44 6PE转发，出站的报文在PE上封装2层标签，内层为IPv6单播路由分发的标签，外层为ipv4 fec标签。 PE-CE之间的配置，简化示例突出重点： 1.interface{ 　　ipv4 addr 　　ipv6 addr } 2.protocol{ 　　bgp 　　　　group eBGP-65000{//多协议 　　　　　　 family inet unicast; 　　　　　　family inet6 unicast; 　　　　 neighbor 10.1.0.0; 　　　　} } 3.policy-options//改写 IPv6下一跳。 { 　　 from family inet6; 　　then next-hop fc00::10:1:0:1; } 来源： https://www.cnblogs

One of our Java program when started, it only listen on IPv6 (8080) e.g. # netstat -ntpl Proto Recv-Q Send-Q Local Address Foreign Address State PID/Program name tcp 0 0 0.0.0.0:22 0.0.0.0:* LISTEN - tcp6 0 0 :::8080 :::* LISTEN - tcp6 0 0 :::22 :::* LISTEN - The problem is it is not accessible from outside (except localhost), to solve this, I have this manually add -Djava.net.preferIPv4Stack=true But this make the program is only for IPv4 network. Is it possible to do something like the sshd as above, both support IPv4 and IPv6? paulsm4 I suspect it's less a Java programming issue than an OS

How should I perform conversion from IPv6 to long and vice versa? So far I have: public static long IPToLong(String addr) { String[] addrArray = addr.split("\\."); long num = 0; for (int i = 0; i < addrArray.length; i++) { int power = 3 - i; num += ((Integer.parseInt(addrArray[i], 16) % 256 * Math.pow(256, power))); } return num; } public static String longToIP(long ip) { return ((ip >> 24) & 0xFF) + "." + ((ip >> 16) & 0xFF) + "." + ((ip >> 8) & 0xFF) + "." + (ip & 0xFF); } Is it correct solution or I missed something? (It would be perfect if the solution worked for both ipv4 and ipv6) Andrei

Is there a good way to match an IPv6 address to an IPv6 subnet using CIDR notation? What I am looking for is the IPv6 equivalent to this: Matching an IP to a CIDR mask in PHP 5? The example given above can't be used since an IPv6 address is 128 bits long, preventing the bitwise left-shift from working properly. Can you think of any other way? EDIT: Added my own solution to the list of answers. Since you cannot convert IPv6 addresses to integer, you should operate bits, like this: $ip='21DA:00D3:0000:2F3B:02AC:00FF:FE28:9C5A'; $cidrnet='21DA:00D3:0000:2F3B::/64'; // converts inet_pton output to

I wanted to know how I can parse an IPv6 address in C and convert it to a 128 bit value? So a hex address like 1:22:333:aaaa:b:c:d:e needs to be converted to its 128 bit equivalent binary. The problem is the IP address could be of the type ::2 and its variant since they are valid IPv6 address. The input is from the keyboard and hence is in ASCII format. You can use POSIX inet_pton to convert a string to a struct in6_addr . #include <arpa/inet.h> ... const char *ip6str = "::2"; struct in6_addr result; if (inet_pton(AF_INET6, ip6str, &result) == 1) // success! { //successfully parsed string into

Is this possible? How can you convert an ipv4 to an ipv6 address? a few example from here: 0.0.0.0 -> :: 127.0.0.1 -> ::1 I'm searching a solution in Java. Thanks, There is no IPv4 to IPv6 mapping that is meaningful. things like 0.0.0.0 and 127.0.0.1 are special cases in the spec, so they have equivalent meaning. But given an IPv4 address it tells you nothing about what its specific IPv6 address would be. You can use a DNS lookup to see if a given IP address resolves to a host which in turn resolves to an IPv6 address in addition to an IPv4 address, but the DNS server would have to be

Checking the environment variables and also HTTP configuration options does not reveal something. Is there a way to do this? With git 2.8 (March 2016), you can force git fetc h/ push / clone to use IPV4 or IPV6. (for git pull , see below Git 2.16, Q1 2018) See commit c915f11 (03 Feb 2016) by Eric Wong ( ele828 ) . (Merged by Junio C Hamano -- gitster -- in commit e84d5e9 , 24 Feb 2016) connect & http : support -4 and -6 switches for remote operations Sometimes it is necessary to force IPv4-only or IPv6-only operation on networks where name lookups may return a non-routable address and stall