ip-address

问题 I'm looking to pad IP addresses with 0's example 1.2.3.4 -> 001.002.003.004 50.51.52.53 -> 050.051.052.053 Tried this: [string]$paddedIP = $IPvariable [string]$paddedIP.PadLeft(3, '0') Also tried split as well, but I'm new to powershell... 回答1: You can use a combination of .Split() and -join . ('1.2.3.4'.Split('.') | ForEach-Object {$_.PadLeft(3,'0')}) -join '.' With this approach, you are working with strings the entire time. Split('.') creates an array element at every . character. .PadLeft

问题 I'm looking to pad IP addresses with 0's example 1.2.3.4 -> 001.002.003.004 50.51.52.53 -> 050.051.052.053 Tried this: [string]$paddedIP = $IPvariable [string]$paddedIP.PadLeft(3, '0') Also tried split as well, but I'm new to powershell... 回答1: You can use a combination of .Split() and -join . ('1.2.3.4'.Split('.') | ForEach-Object {$_.PadLeft(3,'0')}) -join '.' With this approach, you are working with strings the entire time. Split('.') creates an array element at every . character. .PadLeft

问题 I am struggling with regex to extract IP and subnet mask info from a snmp walk output. Here is how output looks like. [<SNMPVariable value='255.255.255.0' (oid='iso.3.6.1.2.1.4.21.1.11.10.10.2.0', oid_index='', snmp_type='IPADDR')>, <SNMPVariable value='255.255.255.192' (oid='iso.3.6.1.2.1.4.21.1.11.10.0.0.0', oid_index='', snmp_type='IPADDR')>, <SNMPVariable value='255.255.255.0' (oid='iso.3.6.1.2.1.4.21.1.11.10.10.10.0', oid_index='', snmp_type='IPADDR')>, <SNMPVariable value='255.255.255

问题 I have a variable named $Ip . This variable has an IP inside like "172.13.23.34". I would like to get the 3rd octet or the next character between 172.13. and .34 which is a string number 23 in this case and store in another variable to set up a VLANID with the command below. $Ip = 172.13.23.34 $VLANID = ? Set-Netadapter -Name "Ethernet" -VlanID $VLANID How can I get this specific information? 回答1: While -split, the regex-based string-splitting operator , or the literal-substring-based Split()

问题 I have a variable named $Ip . This variable has an IP inside like "172.13.23.34". I would like to get the 3rd octet or the next character between 172.13. and .34 which is a string number 23 in this case and store in another variable to set up a VLANID with the command below. $Ip = 172.13.23.34 $VLANID = ? Set-Netadapter -Name "Ethernet" -VlanID $VLANID How can I get this specific information? 回答1: While -split, the regex-based string-splitting operator , or the literal-substring-based Split()

问题 I am writing a (rather simple :) networking application, and am testing it using localhost:27488 ( 127.0.0.1:27488 ). I am using a System.Net.Sockets.TcpClient for the connection, which takes a System.Net.IPAddress to specify the host... the only thing is, I can't figure out how to initialize the class with the right IP address. I went over the MSDN docs and it says it takes either a Byte(4) or an Int64 ( long ) for the address. The probelm is, when I initialize the IPAddress like this: Dim

问题 I am writing a (rather simple :) networking application, and am testing it using localhost:27488 ( 127.0.0.1:27488 ). I am using a System.Net.Sockets.TcpClient for the connection, which takes a System.Net.IPAddress to specify the host... the only thing is, I can't figure out how to initialize the class with the right IP address. I went over the MSDN docs and it says it takes either a Byte(4) or an Int64 ( long ) for the address. The probelm is, when I initialize the IPAddress like this: Dim

问题 I am writing a (rather simple :) networking application, and am testing it using localhost:27488 ( 127.0.0.1:27488 ). I am using a System.Net.Sockets.TcpClient for the connection, which takes a System.Net.IPAddress to specify the host... the only thing is, I can't figure out how to initialize the class with the right IP address. I went over the MSDN docs and it says it takes either a Byte(4) or an Int64 ( long ) for the address. The probelm is, when I initialize the IPAddress like this: Dim

问题 I am using a laptop as my server and a mobile device as my client. I need to send messages between them. I am able to do that by using the local ip address of the laptop and connecting them both to the same wifi network. But how I do use the ip address if I need to send messages though they are connected to different internet through different wifi networks. This is the code in client: client = new Socket("192.168.0.103", 4444); //local ip address of server This is the code in server:

问题 I am trying to get the client machine information for access log. How to get Client Device name and Ip address in ASP.NET / C#? 回答1: You can get the direct client IP from the Request.UserHostAddress property: public ActionResult Index() { string ip = Request.UserHostAddress; ... } This being said, there are many situations where this might not be good enough. Suppose for example that your web server is behind a reverse proxy such as nginx or HAProxy. In this case the UserHostAddress will