问题
I am writing a (rather simple :) networking application, and am testing it using localhost:27488 (127.0.0.1:27488).
I am using a System.Net.Sockets.TcpClient for the connection, which takes a System.Net.IPAddress to specify the host... the only thing is, I can't figure out how to initialize the class with the right IP address. I went over the MSDN docs and it says it takes either a Byte(4) or an Int64 (long) for the address.
The probelm is, when I initialize the IPAddress like this:
Dim ipAddr As New System.Net.IPAddress(127001)
it returns the address as 25.240.1.0. From what I understand from the docs, 127001 should return 127.0.0.1... Maybe I missed something there? http://msdn.microsoft.com/en-us/library/13180abx.aspx
回答1:
Short answer: use TcpClient.Connect( String, Int ) instead; it accepts an IPv4/IPv6 address or hostname/alias, so you are not limited to connecting by IP. e.g.:
Dim client As TcpClient
client.Connect( "localhost", 27488 )
client.Connect( "127.0.0.1", 27488 )
But where did 25.240.1.0 come from? Try the following:
- Open Calc, switch to Programmer view, select Dec
- Type in
127001, then switch to Hex - Write out the result, adding zeroes on the left to pad to 4 bytes/32 bits:
0001F019 - Separate that number into individual bytes:
00 01 F0 19 - Reverse the byte order:
19 F0 01 00 - Convert each byte back to decimal:
25 240 1 0 - With dots:
25.240.1.0
Why reverse the bytes? Your processor architecture is little-endian; numbers are represented in memory with the least significant byte first. IPv4 addresses are standardized to big-endian format (most significant byte first; a.k.a. network order). The IPAddress( Int64 ) constructor is reversing the bytes to convert from LE to BE.
Reversing the steps above, the correct value for loopback in the IPAddress( Int64 ) constructor would be &H0100007F (hex) or 16777343 (decimal).
The IPAddress( Byte[4] ) constructor takes the byte array in network order, so that would be New Byte() { 127, 0, 0, 1 }
回答2:
You are misunderstating how it works. Ip address consists of 4 bytes, representing them as 127.0.0.1 is just a human readable convention. Under the hood, 127.0.0.1 is represented as ((127 << 24) | (0 << 16) | (0 << 8) | 1).
In your case, it would be much easier and more readable to just use .Parse(string) method like this:
IPAddress.Parse("127.0.0.1");
回答3:
Why not try the IPAddress.Parse method?
You'd do something like:
Dim ipAddr as IPAddress = IPAddress.Parse("127.0.0.1")
来源：https://stackoverflow.com/questions/6929487/system-net-ipaddress-returning-weird-addresses