intersect

I have number of User nodes and Skills nodes. The relationship is between skills and users. USING PERIODIC COMMIT 1000 LOAD CSV WITH HEADERS FROM "file:/xyz.csv" AS row FIELDTERMINATOR '|' WITH row LIMIT 15 CREATE (u:User {company: row.company, salary: row.salary_float, designation: row.designation, experience: row.experience_float}) FOREACH (s IN split(row.tag_skill, "@") | MERGE (skill:SKILL {name: s}) ON CREATE SET skill.name = s CREATE (u)-[:KNOWS]->(skill)) I also need a relationship between user nodes where if User A is connected to a number for Skill nodes [s1,s2,s3,s4,s5,s6] and if

I am trying to run this worksheet change event for two different columns(A) and (I)... Private Sub Worksheet_Change(ByVal Target As Range) Dim A As Range, B As Range, Inte As Range, r As Range Set A = Range("A:A") Set Inte = Intersect(A, Target) If Inte Is Nothing Then Exit Sub Application.EnableEvents = False For Each r In Inte r.Offset(0, 1).Value = Date Next r Application.EnableEvents = True End Sub This event is something i found on this forum. Its purpose is to make it so whenever data is ever entered into column "a" it auto inputs the date into the cell directly right of it. I want this

So I have successfully made a ray the represents the mouse unprojected into the world, and now I need to check if that ray can intersect with a quad object, here is the code I use to get the ray: public Ray GetMouseRay() { Vector2 mousePosition = new Vector2(cursor.getX(), cursor.getY()); Vector3 nearPoint = new Vector3(mousePosition, 0); Vector3 farPoint = new Vector3(mousePosition, 1); nearPoint = viewport.Unproject(nearPoint, projectionMatrix, viewMatrix, Matrix.Identity); farPoint = viewport.Unproject(farPoint, projectionMatrix, viewMatrix, Matrix.Identity); Vector3 direction = farPoint -

I'm trying to make a simple game and i need to know if picturebox1( my character) collides with other pictureboxes ( the walls). I have already worked out how do this but it only works with my character and 1 other picturebox for example: If picturebox1.bounds.intersectWith(picturebox2.bounds) then collision = true end if I tried to do something else like this: For Each PictureBox In Me.Controls If PictureBox1.Bounds.IntersectsWith(PictureBox.Bounds) Then collision = True Else : collision = False End If Next But then the boolean collision would always be true because picturebox1 (the character

This question already has an answer here: Extracting common characters from multiple vectors of different lengths 1 answer I have the following data as an example: basketball = c("MISS W. Johnson 18' Pullup Jump Shot", "MISS Barnes 12' Pullup Jump Shot", "MISS Carter 19' Pullup Jump Shot") How do I find the most common words or 'intersect' them so that I will only have "MISS Pullup Jump Shot" as the result? This works, but I'm not sure how robust it is given your question is a little vague. Reduce(intersect, strsplit(basketball," ")) #[1] "MISS" "Pullup" "Jump" "Shot" 来源： https://stackoverflow

while looking at this question C# Similarities of two arrays it was noted that the initial linq call was significantly slower than subsequent calls. What is being cached that is making such a difference? I am interested in when we can expect to achieve this type of behavior (perhaps here it is simply because the same lists are used over and over). static void Main(string[] args) { var a = new List<int>() { 7, 17, 21, 29, 30, 33, 40, 42, 51, 53, 60, 63, 66, 68, 70, 84, 85, 91, 101, 102, 104, 108, 109, 112, 115, 116, 118, 125, 132, 137, 139, 142, 155, 163, 164, 172, 174, 176, 179, 184, 185, 186,

I would like to intersect two lists in Python (2.7). I need the result to be iterable: list1 = [1,2,3,4] list2 = [3,4,5,6] result = (3,4) # any kind of iterable Providing a full iteration will be performed first thing after the intersection, which of the following is more efficient? Using a generator: result = (x for x in list1 if x in list2) Using filter(): result = filter(lambda x: x in list2, list1) Other suggestions? Thanks in advance, Amnon Neither of these. The best way is to use sets. list1 = [1,2,3,4] list2 = [3,4,5,6] result = set(list1).intersection(list2) Sets are iterable, so no