interpolation

Angular JS - “Error: [$interpolate:interr] Can't interpolate:” from a working function

假装没事ソ 提交于 2019-12-05 08:12:42
I'm getting the following error in one of my functions: Error: [$interpolate:interr] http://errors.angularjs.org/1.3.0-rc.4/$interpolate/interr?p0=%7B%7B%20crea…&p1=TypeError%3A%20Cannot%20read%20property%20'startDate'%20of%20undefined at Error (native) at file:///C:/Users/Zuh/Desktop/MSF_Juba_2014/Radio%20Room%20App/angular.min.js:6:421 at z.exp (file:///C:/Users/Zuh/Desktop/MSF_Juba_2014/Radio%20Room%20App/angular.min.js:86:481) at file:///C:/Users/Zuh/Desktop/MSF_Juba_2014/Radio%20Room%20App/angular.min.js:56:215 at q (file:///C:/Users/Zuh/Desktop/MSF_Juba_2014/Radio%20Room%20App/angular

Correct Way To Move UIButton Between Two Points?

允我心安 提交于 2019-12-05 06:48:19
问题 Trying to make a small tapping game, where you have a grid of squares and need to tap them in different orders. Occasionally these squares will swap places with each other. I figure that I will need to put the locations of each square into an array. Then when it is time to move, go from the current location to a one selected at random from the array, and then deleting that location in the array so I don't get multiple buttons in the same place. Unfortunately I can't even get the UIButtons to

Angular $compile template for dynamic email

眉间皱痕 提交于 2019-12-05 04:30:24
I am trying to load a html template with ng-repeats in it and then use the $compile service to compile it and use the compiled html in an email. The problem.... Ok before asking let me set terminology... binding placeholder: {{customer.name}} binding value: 'john doe' Using $interpolate i get the actual binding values but does not work with ng-repeats. Example: var html = $interpolate('<p>{{customer.name}}</p>')($scope) Returns: '<p>john doe</p>' Ng-repeats do not work Using $compile i get the bindings placeholders ie {{customer.name}} but what I need is the binding value 'john doe' . Example:

natural neighbour interpolation. error in calculating polygon intersection area

删除回忆录丶 提交于 2019-12-05 04:27:54
问题 I am trying to write this algorithm in R. Does it exist in any package already?!? This is what I did (with help from SO and various blog posts): library(rgdal) library(ggmap) require("maptools") require("plyr") locations<- unique(cbind(data22[,1], data22[,2])) [,1] [,2] [1,] 24.9317 60.1657 [2,] 24.9415 60.1608 [3,] 24.9331 60.1577 [4,] 24.9228 60.1477 [5,] 24.9370 60.1545 [6,] 24.9491 60.1559 [7,] 24.9468 60.1591 [8,] 24.9494 60.1675 [9,] 24.9561 60.1609 [10,] 24.9218 60.1632 [11,] 24.9213

Shift interpolation does not give expected behaviour

纵饮孤独 提交于 2019-12-05 04:17:09
When using scipy.ndimage.interpolation.shift to shift a numpy data array along one axis with periodic boundary treatment ( mode = 'wrap' ), I get an unexpected behavior. The routine tries to force the first pixel ( index 0 ) to be identical to the last one ( index N-1 ) instead of the "last plus one ( index N )". Minimal example: # module import import numpy as np from scipy.ndimage.interpolation import shift import matplotlib.pyplot as plt # print scipy.__version__ # 0.18.1 a = range(10) plt.figure(figsize=(16,12)) for i, shift_pix in enumerate(range(10)): # shift the data via spline

Extrapolate with LinearNDInterpolator

社会主义新天地 提交于 2019-12-05 04:15:26
问题 I've got a 3D dataset that I want to interpolate AND extrapolate linearly. The interpolation can be done easily with scipy.interpolate.LinearNDInterpolator. The module can only fill in a constant/nan for values outside the parameter range, but I don't see why it would not offer an option to turn on extrapolation. Looking at the code, I see that the module is written in cython. With no experience in cython, it is hard to play around with the code to implement extrapolation. I can write it in

Angular 2 binding within binding. Interpolation within event

只愿长相守 提交于 2019-12-05 04:07:56
Trying to do the following and getting "Got interpolation ({{}}) where expression was expected" error. <ul> <li *ngFor="#item of items"> <a href='' (click)="foo('{{item.name}}')">{{item.name}}</a> </li> </ul> Thanks! Don't use {{}} (interpolation) inside any event handler code (on a view), do pass expression directly which will get evaluated against Component context( this ), like over here you're trying to pass item.name to foo function. So removing {{}} parenthesis would do the trick. <a href="" (click)="foo(item.name)"> {{item.name}} </a> 来源: https://stackoverflow.com/questions/36659854

Sass variable interpolation with backslash in output

自闭症网瘾萝莉.ら 提交于 2019-12-05 03:46:44
I'm creating some icon font rules for using in my site. Using Sass I wanted to list all the icons in a list variable and use @each to loop through them all. Code looks like this: $icons: wifi 600, wifi-hotspot 601, weather 602; @each $icon in $icons { .icon-#{nth($icon, 1)}, %icon-#{nth($icon, 1)} { content: "\#{nth($icon, 2)}"; } } The problem is the backslash on the content: line. I need it for the character encoding, but it escapes the variable interpolation, outputting CSS that looks like this: .icon-wifi { content: "\#{nth($icon, 2)}"; } Adding one more backslash like this: content: "\\#

Interpolating 1 dimensional array using OpenCV

流过昼夜 提交于 2019-12-05 02:53:15
问题 I define an array of 2 values, and try to use the imgproc module's resize function to resize it to 10 elements with linear interpolation as interpolation method. cv::Mat input = cv::Mat(1, 2, CV_32F); input.at<float>(0, 0) = 0.f; input.at<float>(0, 1) = 1.f; cv::Mat output = cv::Mat(1, 11, CV_32F); cv::resize(input, output, output.size(), 0, 0, cv::INTER_LINEAR); for(int i=0; i<11; ++i) { std::cout<< output.at<float>(0, i) << " "; } The output I would have expected is: 0.0 0.1 0.2 0.3 0.4 0.5

How does bicubic interpolation work?

流过昼夜 提交于 2019-12-05 01:22:05
问题 After reading text about this said topic, i found out that it considers 16 of the original neighboring pixels. What i want to know is how does it compute the color value of the new pixel. If the color values of the 16 pixels are known, how could you compute the value of the new one? 回答1: I think it's pretty well explained in Wikipedia. You need the intensity values of 4*4=16 pixels, from which you can calculate the interpolated value at any point within that 4*4 grid. If you mean how to do