interpolation

Issues with 2D-Interpolation in Scipy

喜夏-厌秋 提交于 2019-12-06 06:14:32
问题 In my application, the data data is sampled on a distorted grid, and I would like to resample it to a nondistorted grid. In order to test this, I wrote this program with examplary distortions and a simple function as data: from __future__ import division import numpy as np import scipy.interpolate as intp import pylab as plt # Defining some variables: quadratic = -3/128 linear = 1/16 pn = np.poly1d([quadratic, linear,0]) pixels_x = 50 pixels_y = 30 frame = np.zeros((pixels_x,pixels_y)) x

Explanation of Interpolate Hermite method

旧巷老猫 提交于 2019-12-06 05:54:55
I've currently got this bounty running on how to resample audio data with the intention of increasing the pitch . Many solutions have been made and I have to admit I'm feeling a bit overwhelmed by the choices and information. I was directed to this solution and found this chunk of code: public static float InterpolateCubic(float x0, float x1, float x2, float x3, float t) { float a0, a1, a2, a3; a0 = x3 - x2 - x0 + x1; a1 = x0 - x1 - a0; a2 = x2 - x0; a3 = x1; return (a0 * (t * t * t)) + (a1 * (t * t)) + (a2 * t) + (a3); } public static float InterpolateHermite4pt3oX(float x0, float x1, float

Interpolate multiple NA values with R

只谈情不闲聊 提交于 2019-12-06 05:25:03
问题 I want to interpolate multiple NA values in a matrix called, tester. This is a part of tester with only 1 column of NA values, in the whole 744x6 matrix other columns have multiple as well: ZONEID TIMESTAMP U10 V10 U100 V100 1 20121022 12:00 -1.324032e+00 -2.017107e+00 -3.278166e+00 -5.880225574 1 20121022 13:00 -1.295168e+00 NA -3.130429e+00 -6.414975148 1 20121022 14:00 -1.285004e+00 NA -3.068829e+00 -7.101699541 1 20121022 15:00 -9.605904e-01 NA -2.332645e+00 -7.478168285 1 20121022 16:00

Python Interpolation with matplotlib/basemap

谁都会走 提交于 2019-12-06 04:51:07
问题 I am rather new to programming and am having a very hard time understanding interpolation. Every single source I can find that attempts to explain it is extremely cryptic (especially the package specific sites for basemap/matplotlib). I am mapping using matplotlib's basemap however the nature of my data is that it comes in 5 degree by 5 degree blocks (lat lon blocks). I want to smooth out the map by interpolation. So first here is my code. from netCDF4 import Dataset import numpy as np import

How to use interpn on non-monotonic data

半腔热情 提交于 2019-12-06 04:16:58
Below is some part of my data. The 1st column R is the value I got from the experiment, and X Y Z are the coordinates. I am trying to use matlab n-D interpolation function. Matlab said my coordinates are not monotonic increased value. But I cant change or rearrange my coordinates. Did I use the wrong function? Please tell me what should I do. R X Y Z 5.05256e-18 0.016 0.015 0.032 4.99958e-18 0.016 0.015 0.064 5.04485e-18 0.016 0.015 0.128 5.49613e-18 0.016 0.0195 0.032 5.45348e-18 0.016 0.0195 0.064 5.43161e-18 0.016 0.0195 0.128 5.9393e-18 0.016 0.03 0.032 5.98785e-18 0.016 0.03 0.064 6

Interpolate values from a grid efficiently in R

旧城冷巷雨未停 提交于 2019-12-06 03:59:56
问题 I have a grid of ocean depth data by location, and am trying to interpolate depth values for a selection of GPS points. We've been using RSAGA::pick.from.points, which works fine for small data sets. require(RSAGA) depthdata <- cbind.data.frame(x=c(74.136, 74.135, 74.134, 74.133, 74.132, 74.131, 74.130, 74.129, 74.128, 74.127), y=rep(40, times=10), depth=c(-0.6, -0.6, -0.9, -0.9, -0.9, -0.9, -0.9, -0.9, -0.6, -0.6)) mylocs <- rbind(c(-74.1325, 40), c(-74.1305, 40)) colnames(mylocs) <- c("x",

Nginx proxy_pass directive string interpolation

左心房为你撑大大i 提交于 2019-12-06 03:45:29
I'm running Nginx on Kubernetes. When I use the following proxy_pass directive it works as expected: proxy_pass "http://service-1.default"; However the following does not work: set $service "service-1"; proxy_pass "http://$service.default"; I get an error saying no resolver defined to resolve service-1.default As far as I can tell proxy_pass is receiving the exact same string so why is it behaving differently? I need to use a variable because I'm dynamically getting the service name from the URL using a regex. I've found the reason and a solution. Nginx detects if a variable is being used in

What's the difference between single and double quotes in Perl?

☆樱花仙子☆ 提交于 2019-12-06 03:33:29
问题 I am just begining to learn Perl. I looked at the beginning perl page and started working. It says: The difference between single quotes and double quotes is that single quotes mean that their contents should be taken literally, while double quotes mean that their contents should be interpreted When I run this program: #!/usr/local/bin/perl print "This string \n shows up on two lines."; print 'This string \n shows up on only one.'; It outputs: This string shows up on two lines. This string

Image interpolation in IE10

£可爱£侵袭症+ 提交于 2019-12-06 03:02:46
This is my use case: I have a web page with a responsive design. The page is vertically split in two halves, on the right hand side I want to show an image (a PDF page rendered as PNG or JPG). The size of the image should change as soon as the window is resized. I thought I already solved this. I render the image on the server to be big enough for the biggest possible window size (according to our company setup). Chrome and Firefox scale down (and interpolate) the image just fine. But then there is Internet Explorer 10: If the image size is scaled down to anything beneath 100% it looks like a

SciPy interp2D for pairs of coordinates

久未见 提交于 2019-12-06 02:55:28
问题 I'm using scipy.interpolate.interp2d to create an interpolation function for a surface. I then have two arrays of real data that I want to calculate interpolated points for. If I pass the two arrays to the interp2d function I get an array of all the points, not just the pairs of points. My solution to this is to zip the two arrays into a list of coordinate pairs and pass this to the interpolation function in a loop: f_interp = interpolate.interp2d(X_table, Y_table,Z_table, kind='cubic') co