integer

来源： https://stackoverflow.com/questions/46406072/how-to-convert-string-to-int-without-using-library-functions-in-python

来源： https://stackoverflow.com/questions/63018564/decoding-alphanumeric-code-into-key-values-object-using-bytes

来源： https://stackoverflow.com/questions/2024648/convert-a-string-to-int-but-only-if-really-is-an-int

问题 Recently, I saw this question which asks how you can divide integers with ceil rounding (towards positive infinity). Unfortunately the answers either don't work for signed integers or have problems with underflows and overflows. For instance, the accepted answer has this solution: q = 1 + ((x - 1) / y); When x is zero, there is an underflow to ~0 and the the result is incorrect. How can you implement ceil rounding correctly for signed and unsigned integers and how do you implement other

问题 Recently, I saw this question which asks how you can divide integers with ceil rounding (towards positive infinity). Unfortunately the answers either don't work for signed integers or have problems with underflows and overflows. For instance, the accepted answer has this solution: q = 1 + ((x - 1) / y); When x is zero, there is an underflow to ~0 and the the result is incorrect. How can you implement ceil rounding correctly for signed and unsigned integers and how do you implement other

问题 For a BigDecimal number such as 42.7, how can I tear this apart to get the integer part (42) and the decimal fractional part (0.7)? I would like to retrieve both as BigDecimal objects. But I will take what I can get and make BigDecimal object from them. 回答1: setScale() I think I’d go for setScale() . BigDecimal bd = new BigDecimal("42.7"); BigDecimal integerPart = bd.setScale(0, RoundingMode.DOWN); BigDecimal fractionalPart = bd.subtract(integerPart); System.out.println(integerPart); System

问题 For a BigDecimal number such as 42.7, how can I tear this apart to get the integer part (42) and the decimal fractional part (0.7)? I would like to retrieve both as BigDecimal objects. But I will take what I can get and make BigDecimal object from them. 回答1: setScale() I think I’d go for setScale() . BigDecimal bd = new BigDecimal("42.7"); BigDecimal integerPart = bd.setScale(0, RoundingMode.DOWN); BigDecimal fractionalPart = bd.subtract(integerPart); System.out.println(integerPart); System

问题 Recently, I heard that clang got a new feature, _ExtInt . I know that it lets you specify the size of an integer (odd or even like 13-bit int), but how do you use it? 回答1: _ExtInt is to be used as a normal specifier. For example: _ExtInt(13) foo; Here you declared foo to be of 13 bits. Remember to not put short or long type of keywords before it (cause it wouldn't really make sense), though you can put signed or unsigned ( signed is default). Note that you aren't allowed to do things like;

问题 Recently, I heard that clang got a new feature, _ExtInt . I know that it lets you specify the size of an integer (odd or even like 13-bit int), but how do you use it? 回答1: _ExtInt is to be used as a normal specifier. For example: _ExtInt(13) foo; Here you declared foo to be of 13 bits. Remember to not put short or long type of keywords before it (cause it wouldn't really make sense), though you can put signed or unsigned ( signed is default). Note that you aren't allowed to do things like;

问题 I have a text files that I read to a list. This list contains integers and strings. For example, my list could look like this: ["name", "test", "1", "3", "-3", "name" ...] Now, I want to convert all numbers into integers using the .isdigit() method or the isinstance() function. for example: for i in range len(mylist): if mylist[i].isdigit(): mylist[i] = int(mylist[i]) The problem is that "-3".isdigit() for example would return False . Any tips for a simple solution to circumvent the problem