int

问题 I'm trying to read a text file to get a version number but for some reason no matter what I put in the text file it always returns 0 (zero). The text file is called version.txt and it contains no spaces or letters, just 1 character that is a number. I need it to return that number. Any ideas on why this doesn't work? static int i; public static void main(String[] args) { String strFilePath = "/version.txt"; try { FileInputStream fin = new FileInputStream(strFilePath); DataInputStream din =

问题 This question already has answers here : How can I read inputs as numbers? (10 answers) How to convert strings into integers in Python? (14 answers) Closed 4 years ago . I am quite a newbie in Python. I wrote this and got this error when i typed a letter in the input: TypeError: unorderable types: str() >= int() Here is the code that I wrote: user_input = input('How old are you?: ') if user_input >= 18: print('You are an adult') elif user_input < 18: print('You are quite young') elif user

问题 int plus unsigned int returns an unsigned int. Should it be so? Consider this code: #include <boost/static_assert.hpp> #include <boost/typeof/typeof.hpp> #include <boost/type_traits/is_same.hpp> class test { static const int si = 0; static const unsigned int ui = 0; typedef BOOST_TYPEOF(si + ui) type; BOOST_STATIC_ASSERT( ( boost::is_same<type, int>::value ) ); // fails }; int main() { return 0; } 回答1: If by "should it be" you mean "does my compiler behave according to the standard": yes . C+

问题 Convert the following int argument into a string without using any native toString functionality. public string integerToString(int integerPassedIn){ //Your code here } Since everything inherits from Object and Object has a ToString() method how would you convert an int to a string without using the native ToString() method? The problem with string concatenation is that it will call ToString() up the chain until it hits one or hits the Object class. How do you convert an integer to a string

问题 I am trying to pass long value to the method and use it there to create a Long Array. However, I am getting "possible lossy conversion from long to int" error while creating an array long[] array = new long[n]; although I have not used any integers values. import java.util.Scanner; import java.util.ArrayList; public class test{ public static void main(String[] args){ Scanner input = new Scanner(System.in); long n = input.nextLong(); System.out. although("result is " + n + " is " + testing(n))

问题 I had to split an int "123456" each value of it to an Int[] and i have already a Solution but i dont know is there any better way : My solution was : public static int[] intToArray(int num){ String holder = num.ToString(); int[] numbers = new int[Holder.ToString().Length]; for(int i=0;i<numbers.length;i++){ numbers[i] = Convert.toInt32(holder.CharAt(i)); } return numbers; } 回答1: I believe this will be better than converting back and forth. As opposed to JBSnorro´s answer I reverse after

问题 This is a rather silly question but why is int commonly used instead of unsigned int when defining a for loop for an array in C or C++? for(int i;i<arraySize;i++){} for(unsigned int i;i<arraySize;i++){} I recognize the benefits of using int when doing something other than array indexing and the benefits of an iterator when using C++ containers. Is it just because it does not matter when looping through an array? Or should I avoid it all together and use a different type such as size_t ? 回答1:

问题 Utilities.getDistance(uni, enemyuni) <= uni.getAttackRange() Utilities.getDistance returns double and getAttackRange returns int. The above code is part of an if statement and it needs to be true. So is the comparison valid? Thanks 回答1: Yes, it's valid - it will promote the int to a double before performing the comparison. See JLS section 15.20.1 (Numerical Comparison Operators) which links to JLS section 5.6.2 (Binary Numeric Promotion). From the latter: Widening primitive conversion (§5.1.2

问题 I can't seem to find the answer I'm looking for regarding a simple question: how do I round up any number to the nearest int ? For example, whenever the number is 0.2, 0.7, 0.2222, 0.4324, 0.99999 I would want the outcome to be 1. So far I have int b = (int) Math.ceil(a / 100); It doesn't seem to be doing the job, though. 回答1: Math.ceil() is the correct function to call. I'm guessing a is an int , which would make a / 100 perform integer arithmetic. Try Math.ceil(a / 100.0) instead. int a =