initialization

问题 In ipython I imported tensorflow as tf and numpy as np and created an TensorFlow InteractiveSession . When I am running or initializing some normal distribution with numpy input, everything runs fine: some_test = tf.constant(np.random.normal(loc=0.0, scale=1.0, size=(2, 2))) session.run(some_test) Returns: array([[-0.04152317, 0.19786302], [-0.68232622, -0.23439092]]) Just as expected. ...but when I use the Tensorflow normal distribution function: some_test = tf.constant(tf.random_normal([2,

问题 I can't for the life of me figure out how to do this properly. I have a class that needs to store some constants (text that corresponds to values in an enum type) - I have it declared like this (publicly) in my class: const static char* enumText[]; And I'm trying to initialize it like this: const char* MyClass::enumText[] = { "A", "B", "C", "D", "E" }; However gcc gives me the following error: 'const char* MyClass::enumText[]' is not a static member of 'class MyClass' What am I doing wrong?

问题 Assuming a purely non-optimizing compiler, is there any difference in machine code between initializing a variable and assigning it a value after declaration? Initialization method : int x = 2; Assignment method : int x; x = 2; I used GCC to output the assembly generated for these two different methods and both resulted in a single machine instruction: movl $2, 12(%esp) This instruction just sets the memory held by the x variable to the value of 2 . GCC may be optimizing this because it can

问题 Assuming a purely non-optimizing compiler, is there any difference in machine code between initializing a variable and assigning it a value after declaration? Initialization method : int x = 2; Assignment method : int x; x = 2; I used GCC to output the assembly generated for these two different methods and both resulted in a single machine instruction: movl $2, 12(%esp) This instruction just sets the memory held by the x variable to the value of 2 . GCC may be optimizing this because it can

问题 Here are two ways to initialize a variable in C++11: T a {something}; T a = {something}; I tested these two in all scenarios I could think of and I failed to notice a difference. This answer suggests that there is a subtle difference between the two: For variables I don't pay much attention between the T t = { init }; or T t { init }; styles, I find the difference to be minor and will at worst only result in a helpful compiler message about misusing an explicit constructor. So, is there any

问题 Here are two ways to initialize a variable in C++11: T a {something}; T a = {something}; I tested these two in all scenarios I could think of and I failed to notice a difference. This answer suggests that there is a subtle difference between the two: For variables I don't pay much attention between the T t = { init }; or T t { init }; styles, I find the difference to be minor and will at worst only result in a helpful compiler message about misusing an explicit constructor. So, is there any

问题 I'm not sure why I'm getting this error, but shouldn't this code compile, since I'm already checking to see if queue is getting initialized? public static void Main(String[] args) { Byte maxSize; Queue queue; if(args.Length != 0) { if(Byte.TryParse(args[0], out maxSize)) queue = new Queue(){MaxSize = maxSize}; else Environment.Exit(0); } else { Environment.Exit(0); } for(Byte j = 0; j < queue.MaxSize; j++) queue.Insert(j); for(Byte j = 0; j < queue.MaxSize; j++) Console.WriteLine(queue.Remove

问题 I'm not sure why I'm getting this error, but shouldn't this code compile, since I'm already checking to see if queue is getting initialized? public static void Main(String[] args) { Byte maxSize; Queue queue; if(args.Length != 0) { if(Byte.TryParse(args[0], out maxSize)) queue = new Queue(){MaxSize = maxSize}; else Environment.Exit(0); } else { Environment.Exit(0); } for(Byte j = 0; j < queue.MaxSize; j++) queue.Insert(j); for(Byte j = 0; j < queue.MaxSize; j++) Console.WriteLine(queue.Remove

问题 I'm reading source code of nginx and find it's not initializing many of the numerical variables, including ngx_int_t ngx_last_process; ,here ngx_int_t defined as long int #if 0 ngx_last_process = 0; #endif So here @Igor Sysoev think it unnecessary to do the initialization? But in the programe it's assuming the default value is 0 : for (s = 0; s < ngx_last_process; s++) { if (ngx_processes[s].pid == -1) { break; } } Is it guranteed that un-initialized variable will have 0 value in c at all?

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 6 years ago . public class A{ { System.out.println("hi i am IIB"); } public A(){ System.out.println("hi i am constructor"); } public static void main(String... args){ A objA=new A(); } } 回答1: iib will get execute before the constructor is called No, this is not what happens. The code written in instance