inheritance

Dynamic Method invocation (Objects and reference in inheritance )

天大地大妈咪最大 提交于 2019-12-25 16:47:15
问题 Suppose I have 2 classes ........ A Class is base class and class B is derived class and if i create a reference such as : A a=new B(); does it mean that reference a points to object of B Class ? If yes than how am i able to call overridden methods of A in B and not other methods of B ? thank you in advance class A { m1() { } } class B extends A { m1() { } m2() { } } A a=new B(); a.m1(); //it will call overridden m1() in B a.m2(); //it doesnt work if reference "a" points to object of B than

Hibernate: bug when mapping a reference to an alternative/natural key column of a sub table?

女生的网名这么多〃 提交于 2019-12-25 16:45:10
问题 The original question stems from this question: Why is this JPA 2.0 mapping giving me an error in Eclipse/JBoss Tools? As you can see this constellation also freaks out the Eclipse Dali JPA validator. The JPA spec seems to allow this as seen here (somewhat reliable): Does the JPA specification allow references to non-primary key columns? The exact code posted in the first question also raises a Hibernate MappingException: Exception in thread "main" javax.persistence.PersistenceException:

What the heck do I get when I subclass `declarative_base` using SqlAlchemy?

百般思念 提交于 2019-12-25 16:45:03
问题 I have a simple SqlAlchemy application: import sqlalchemy as sa import sqlalchemy.ext.declarative as dec import sqlalchemy.engine.url as saurl import sqlalchemy.orm as saorm import sqlalchemy.schema as sch import abc class ItemTable(): __tablename__ = 'book_items' @abc.abstractmethod def _source_key(self): pass rowid = sa.Column(sa.Integer, sa.Sequence('book_page_id_seq'), primary_key=True) src = sa.Column(sa.String, nullable=False, index=True, default=_source_key) dlState = sa.Column(sa

How to override ostream << operator for already defined type

蹲街弑〆低调 提交于 2019-12-25 16:42:01
问题 I'm currently working on a port of an existing library which makes use of ostream to write to a terminal. The ostream was derived as part of the port. The ostream derivative class used is defined as so: class owstream: public std::ostream { public: CTerminal * output; giac::context * contextptr; owstream(CTerminal *, giac::context * contextptr , int = 0); virtual ~owstream(); }; This is used to output some data, typically integers and doubles. The problem is that the platform I'm working on

How to override ostream << operator for already defined type

馋奶兔 提交于 2019-12-25 16:41:30
问题 I'm currently working on a port of an existing library which makes use of ostream to write to a terminal. The ostream was derived as part of the port. The ostream derivative class used is defined as so: class owstream: public std::ostream { public: CTerminal * output; giac::context * contextptr; owstream(CTerminal *, giac::context * contextptr , int = 0); virtual ~owstream(); }; This is used to output some data, typically integers and doubles. The problem is that the platform I'm working on

Querying from child of model given django inheritance and m2m link to parent

守給你的承諾、 提交于 2019-12-25 14:09:24
问题 Among my models, I have Exercise which has a m2m link to Workout. I also have WorkoutPlan and LogBook which are types of Workouts. WorkoutPlan is where ideal workouts are stored. LogBook is where a user stores the workout they actually completed. They can also link a LogBook to a WorkoutPlan to indicate that the actual performance was connected to an original ideal plan. class Exercise(NameDescModel): muscles = models.ManyToManyField(Muscle, blank=True) groups = models.ManyToManyField(Group,

Querying from child of model given django inheritance and m2m link to parent

与世无争的帅哥 提交于 2019-12-25 14:08:21
问题 Among my models, I have Exercise which has a m2m link to Workout. I also have WorkoutPlan and LogBook which are types of Workouts. WorkoutPlan is where ideal workouts are stored. LogBook is where a user stores the workout they actually completed. They can also link a LogBook to a WorkoutPlan to indicate that the actual performance was connected to an original ideal plan. class Exercise(NameDescModel): muscles = models.ManyToManyField(Muscle, blank=True) groups = models.ManyToManyField(Group,

How can I add new existing property to my control?

半世苍凉 提交于 2019-12-25 14:06:21
问题 I have my own control: public class newControl : Control { } There is a Text property, but there is not a TextAlign property. For example, I need this property similar to the TextAlign property of a Button , but I don't want inherit it from a button class. So can I inherit only TextAlign property? If yes, how? 回答1: Yes, you can just add it. The built in enumeration is called ContentAlignment : using System.ComponentModel; using System.Windows.Forms; public class newControl : Control { private

Stoyan Stefanov: JavaScript Patterns - “The Default Pattern”

ぐ巨炮叔叔 提交于 2019-12-25 12:14:31
问题 In chapter 6 (Code Reuse Patterns) there is following example: // the parent constructor function Parent(name) { this.name = name || 'Adam'; } // adding functionality to the prototype Parent.prototype.say = function () { return this.name; }; // empty child constructor function Child(name) {} // inheritance magic happens here inherit(Child, Parent); In section "Classical Pattern #1 — The Default Pattern" the implementation of the inherit() function is: function inherit(C, P) { C.prototype =

Stoyan Stefanov: JavaScript Patterns - “The Default Pattern”

北慕城南 提交于 2019-12-25 12:14:25
问题 In chapter 6 (Code Reuse Patterns) there is following example: // the parent constructor function Parent(name) { this.name = name || 'Adam'; } // adding functionality to the prototype Parent.prototype.say = function () { return this.name; }; // empty child constructor function Child(name) {} // inheritance magic happens here inherit(Child, Parent); In section "Classical Pattern #1 — The Default Pattern" the implementation of the inherit() function is: function inherit(C, P) { C.prototype =