infinite

Compute an (infinite) tree from fixpoint operator using delay modality

由 蹲街弑〆低调 提交于 2019-12-05 02:03:35
问题 Here is a functional programming puzzle involving loop-tying and infinite data structures. There is a bit of background, so hang tight. The setting. Let us define a data type representing recursive data types: type Var = String data STerm = SMu Var STerm | SVar Var | SArrow STerm STerm | SBottom | STop deriving (Show) i.e. t ::= μα. t | α | t → t | ⊥ | ⊤ . Note that ⊥ denotes the type with no inhabitants, while ⊤ denotes the type with all inhabitants. Note that (μα. α) = ⊥ , as μ is a least

Infinite scroll plugin modify the path with custom query

由 梦想与她 提交于 2019-12-05 00:34:34
问题 I am using the infinite scroll plugin (infinite-scroll) with jQuery isotope and was wondering if it's possible to modify the path with custom query parameters as user scrolls down the page to view more items. Is there a way to access the path and modify one of the query parameter. It's hitting the path ok for the first time returning the first set of items and after that it hitting the next pages , 1,2 3 ok but using the same query parameters I used for the first time only updating the page

Firebase: Google OAuth Infinite Redirects

由 吃可爱长大的小学妹 提交于 2019-12-04 19:33:35
I'm fairly new to Firebase. I'm trying to hook up Google OAuth to my Firebase instance. I set everything up and got the client ID and client secrete. I added localhost to the whitelist in the Firebase dashboard. I then used the Firebase example below: <html> <head> <script src="https://cdn.firebase.com/js/client/2.0.4/firebase.js"></script> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script> </head> <body> <script> var ref = new Firebase("https://<firebase url>.firebaseio.com"); ref.authWithOAuthRedirect("google", function(error, authData) { if (error) {

POJ 3358 Period of an Infinite Binary Expansion 经典数论：欧拉函数+欧拉定理+快速幂取模

由 做~自己de王妃 提交于 2019-12-04 15:42:48
Period of an Infinite Binary Expansion Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3707 Accepted: 1047 Description Let { x } = 0. a 1 a 2 a 3... be the binary representation of the fractional part of a rational number z . Suppose that { x } is periodic then, we can write { x } = 0. a 1 a 2... ar ( ar +1 ar +2... ar + s ) w for some integers r and s with r ≥ 0 and s > 0. Also, ( ar +1 ar +2... ar + s ) w denotes a nonterminating and repeating binary subsequence of { x }. The subsequence x 1 = a 1 a 2 ... ar is called the preperiod of { x } and x 2 = ar +1 ar +2 ... ar + s is the

Is it possible to set a number to NaN or infinity?

由 大城市里の小女人 提交于 2019-12-04 07:24:58
问题 Is it possible to set an element of an array to NaN in Python? Additionally, is it possible to set a variable to +/- infinity? If so, is there any function to check whether a number is infinity or not? 回答1: Cast from string using float() : >>> float('NaN') nan >>> float('Inf') inf >>> -float('Inf') -inf >>> float('Inf') == float('Inf') True >>> float('Inf') == 1 False 回答2: Yes, you can use numpy for that. import numpy as np a = arange(3,dtype=float) a[0] = np.nan a[1] = np.inf a[2] = -np.inf

Making the diamond square fractal algorithm infinite

由 痴心易碎 提交于 2019-12-04 06:48:45
I'm trying to generate an infinite map, as such. I'm doing this in Python, and I can't get the noise libraries to correctly work (they don't seem to ever find my VS2010, and doing it in raw Python would be way too slow). As such, I'm trying to use the Diamond-Square Algorithm . Would it be possible, in some way, to make this technically infinite? If not, should I just go back to attempting to get one of the Python noise bindings to work? This can be done. Divide up your landscape into "tiles", and apply the midpoint displacement algorithm (as I prefer to call it) within each tile. Each tile

vue-infinite-loading简要教程

由 孤街浪徒 提交于 2019-12-04 04:32:00
function 可以实现瀑布流式累加载。 install npm i vue-infinite-loading --save import InfiniteLoading from 'vue-infinite-loading' 或 const InfiniteLoading require('vue-infinite-loading') <script src="/path/to/vue-infinite-loading/dist/vue-infinite-loading.js"></script> usage 需要累加载页面元素时。 放在页面底部。 在InfinityLoading组件中监听infinite事件。 infinite事件触发的函数有一个特殊事件参数（$state）。 $state.loaded() => 表示已经加载成功，用于当次加载数据成功时。此时出现slot="no-more"的内容 $state.complete() => 表示已经加载完成，用于加载数据结束时。此时出现slot="no-resluts"的内容 $state.reset() => 表示 <tag slot="no-more"></tag> => 表示在没有更多元素时（即加载完数据时）显示 在InfinityLoading组件中设置ref="child"。运行this.$refs.child.

loop carousel jquery [duplicate]

由 狂风中的少年 提交于 2019-12-04 04:17:46
问题 This question already exists : Closed 7 years ago . Possible Duplicate: my carousel does not work am a bit puzzled! i got this carousel am creating and i desire that it loops. everything else works out fine, but, when the last image has slid up i want the first one to do the same after it, then the second...infinitely. i have tried many things like appending the first image to the last. i have also tried showing back the images after the last(this one tries but gives an undesirable effect). i

Infinite list of infinite counters

由 时间秒杀一切 提交于 2019-12-04 02:04:39
For those with suspicious minds, this is not homework, just curious. Given a finite alphabet, is it possible to construct a list of infinitely long words made from the alphabet in reverse lexographic order? i.e. given the alphabet "ab" is it possible to construct the list: ["aaaaaa...", "baaaaa...", "abaaaa...", "bbaaaa...", "aabaaa...", ...] where ... represents the list (and list of lists) extending to infinite length. A naïve attempt is: counters alphabet = [c:ounter | ounter <- counters alphabet, c <- alphabet] but this doesn't work since it is left recursive. Of course, with a working

why does an infinite loop of the unintended kind increase the CPU use?

由 安稳与你 提交于 2019-12-04 01:54:26
I know an infinite loop to the unintended kind usually causes a high CPU usage. But, I don't quite understand why. Can anyone explain that to me? The CPU cannot do anything else while it's executing that loop (which never ends). Even if you're using a pre-emptive multi-tasking system (so that infinite loop will only clog forever its own process or thread), the loop will "eat" its time slice each time the OS's pre-emptive scheduler hands it the CPU for the next slice -- doing nothing, but eating up one slice's worth of CPU time each and every time, so that much CPU is lost to all other threads
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