infinite-loop

JQuery infinite slider - simulate the MacApp Store

由 拜拜、爱过 提交于 2019-12-08 11:58:52
问题 If anyone knows the slider on the mac app store then this is what I have recreated. Three problems though. There seams to be an animation delay between the slider on the right and that on the main fader The insertAfter function is doing nothing The slider is not on an infinite loop I have set up a fiddle for testing if anyone can solve it. http://jsfiddle.net/Z5uER/2/ $(document).ready(function(){ $('.sismain a').css('opacity', 0); var slideqnt = $('.sismain a').length; var slidecur = 0; var

Dynamically loading posts with Wordpress

由 半腔热情 提交于 2019-12-08 09:50:56
问题 This helpful idea from Andy Gaskell supports 50% of my next question: I'd like to load posts dynamically with WordPress. Fetching them with Andy's function does work, but How do I bind the load to each and every one of the posts? Can I insert PHP generated content (post permalink, for example) to the JS script? Thank you. 回答1: Got it: $("#triggerDIV a").click(function(id){ event.preventDefault(); // prevent a element from executing var id = this.getAttribute('href'); // get the link $("

Why I receive this error using componentWillReceiveProps?

由 ℡╲_俬逩灬. 提交于 2019-12-08 08:59:13
问题 Receive error: × Maximum update depth exceeded. This can happen when a component repeatedly calls setState inside componentWillUpdate or componentDidUpdate. React limits the number of nested updates to prevent infinite loops. Tried to delete part with error and setState (because it looks like the reason of infinite loop). Didn't help componentWillReceiveProps(nextProps){ if(nextProps.auth.isAuthenticated){ this.props.history.push('/dashboard') } // if(nextProps.errors){ // this.setState({ //

c++ breaking out of loop by key press at any time

由 心不动则不痛 提交于 2019-12-08 08:00:30
What I have here is a loop that is supposed to read the output on a piece of equipment every 500 milliseconds. This part works fine. However, when I try to introduce cin.get to pick up the key "n" being pressed to stop the loop, I only get as many outputs as the number of key presses up to this point. If I press any keys (apart from 'n') several times followed by enter, I will get a few more outputs. What I need is the loop keep looping without any interaction until I want it to stop. Here's the code: for(;;) { count1++; Sleep(500); analogInput = ReadAnalogChannel(1) / 51.0; cout << count1*0.5

Why I receive this error using componentWillReceiveProps?

由 浪尽此生 提交于 2019-12-08 07:54:28
Receive error: × Maximum update depth exceeded. This can happen when a component repeatedly calls setState inside componentWillUpdate or componentDidUpdate. React limits the number of nested updates to prevent infinite loops. Tried to delete part with error and setState (because it looks like the reason of infinite loop). Didn't help componentWillReceiveProps(nextProps){ if(nextProps.auth.isAuthenticated){ this.props.history.push('/dashboard') } // if(nextProps.errors){ // this.setState({ // errors: nextProps.errors // }) // console.log('Error'); // } }; history.push causes a rerender, it

jQuery .remove() call in callback triggers infinite loop

由 岁酱吖の 提交于 2019-12-08 05:42:21
问题 While I have the problem itself seemingly resolved, I'm hoping someone can shed some light on the why of this... Below are two snapshots of the same function whose job is to remove a div that contains a user feedback message. It's setup to use an optional timeout, if a timeout is specified it makes a call to itself using setTimeout() which then removes the div. The only difference between the two versions of the function is where this.remove() is called - in the problem version I send a

Combining Tkinter mainloop with another event listener

由 走远了吗. 提交于 2019-12-08 05:40:01
问题 I am trying to build a program that listens for certain key combinations and then shows information to the user in a Tkinter window. To do this, I'm using a keylogger like so (simplified for this example): from pyHook import HookManager from pythoncom import PumpMessages import Tkinter as tk def on_keyboard_event(event): label.config(text=event.Key) root.update() return True hm = HookManager() hm.KeyDown = on_keyboard_event hm.HookKeyboard() root = tk.Tk() label = tk.Label(root, text='Hello

How to avoid infinite loops in the .NET RegEx class?

由 ◇◆丶佛笑我妖孽 提交于 2019-12-08 05:38:59
问题 Got a simple task to get a XPath expression and return a prefix that matches the parent of the node that (might be) selected. Example: /aaa/bbb => /aaa /aaa/bbb/ccc => /aaa/bbb /aaa/bbb/ccc[@x='1' and @y="/aaa[name='z']"] => /aaa/bbb Because the patterns inside the square brackets might contain brackets within quotes, I decided to try to achieve this with the use of regular expressions. Here's a code snippet: string input = "/aaa/bbb/ccc[@x='1' and @y=\"/aaa[name='z'] \"]"; // ^-- remove

Why is this code an infinite loop?

由 两盒软妹~` 提交于 2019-12-07 17:59:29
Before completing this code, I just tested it by mistake and realized that it will not stop: $var = "any"; for ($i=1; $i < 2; $i++){ $var.$i = "any"; } Why does this produce an infinite loop? And why doesn't PHP produce an error? I did a simple test : echo $i; $var.$i = "any"; var_dump($var); Result : 1string(3) "any" anzstring(3) "any" So $i get transformed to "anz" and doesn't pass the validation to get out of the loop. $var.$i = "any"; is not really correct, i don't know what you are trying to do, but if you want to fill and array you should do something more like : $var = array(); for ($i

Infinite loop problem with while loop and threading [duplicate]

由 心已入冬 提交于 2019-12-07 06:18:14
问题 This question already has an answer here : Loop doesn't see value changed by other thread without a print statement (1 answer) Closed 5 years ago . Using a basic example to illustrate my problem I have 2 near-identical bits of code. This code causes the while loop to run infinitely. private boolean loadAsset() { new Thread(new Runnable() { @Override public void run() { // Do something loaded = true; } }).start(); while (!loaded) { // System.out.println("Not Loaded"); } System.out.println(
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