indexof

We are given a string, say, "itiswhatitis" and a substring, say, "is" . I need to find the index of 'i' when the string "is" occurs a second time in the original string. String.indexOf("is") will return 2 in this case. I want the output to be 10 in this case. Rohit Jain Use overloaded version of indexOf() , which takes the starting index (fromIndex) as 2nd parameter: str.indexOf("is", str.indexOf("is") + 1); int first = string.indexOf("is"); int second = string.indexOf("is", first + 1); This overload starts looking for the substring from the given index. I am using: Apache Commons Lang:

I know that i could return the index of a particular character of a string with indexof() function. But how i could return the character with the particular index? string s = "hello"; char c = s[1]; // now c == 'e' See also Substring , to return more than one character. Do you mean like this int index = 2; string s = "hello"; Console.WriteLine(s[index]); string also implements IEnumberable<char> so you can also enumerate it like this foreach (char c in s) Console.WriteLine(c); 来源： https://stackoverflow.com/questions/2416894/how-to-return-the-character-which-is-at-the-index

This Java code is giving me trouble: String word = <Uses an input> int y = 3; char z; do { z = word.charAt(y); if (z!='a' || z!='e' || z!='i' || z!='o' || z!='u')) { for (int i = 0; i==y; i++) { wordT = wordT + word.charAt(i); } break; } } while(true); I want to check if the third letter of word is a non-vowel, and if it is I want it to return the non-vowel and any characters preceding it. If it is a vowel, it checks the next letter in the string, if it's also a vowel then it checks the next one until it finds a non-vowel. Example: word = Jaemeas then wordT must = Jaem Example 2: word=Jaeoimus

I have an ArrayList in Java, and I need to find all occurrences of a specific object in it. The method ArrayList.indexOf(Object) just finds one occurrence, so it seems that I need something else. André C. Andersen I don't think you need to be too fancy about it. The following should work fine: static <T> List<Integer> indexOfAll(T obj, List<T> list) { final List<Integer> indexList = new ArrayList<>(); for (int i = 0; i < list.size(); i++) { if (obj.equals(list.get(i))) { indexList.add(i); } } return indexList; } I suppose you need to get all indices of the ArrayList where the object on that

I've been surfing around a little trying to find an efficient way to do this, but have gotten nowhere. I have an array of objects that looks like this: array[i].id = some number; array[i].name = some name; What i want to do is to find the INDEXES of the objects where id is equal to, for example, one of 0,1,2,3 or 4. I suppose I could just do something like : var indexes = []; for(i=0; i<array.length; i++) { (array[i].id === 0) ? { indexes[0] = i } (array[i].id === 1) ? { indexes[1] = i } (array[i].id === 2) ? { indexes[2] = i } (array[i].id === 3) ? { indexes[3] = i } (array[i].id === 4) ? {

Not quite grasping what's going on here. Given the array (arr): [ { "first_name": "Dan", "last_name": "Woodson", "id": 1 }, { "first_name": "Jen", "last_name": "Woodson", "id": 2 }, { "first_name": "Yoshi", "last_name": "Woodson", "id": 3 } ] And the object (obj): { "first_name": "Yoshi", "last_name": "Woodson", "id": 3 } Why would arr.indexOf(obj) return -1 (especially since I retrieved the object from the array using it's 'id' parameter earlier in the function)? Array.indexOf() will only work on objects if the supplied object is exactly the same object you put in . An exact copy is