indexOf in a string array

问题

Is there anyway to get indexOf like you would get in a string.

output.add("1 2 3 4 5 6 7 8 9 10);  
String bigger[] = output.get(i).split(" ");
int biggerWher = bigger.indexOf("10");

I wrote this code but its returning an error and not compiling! Any advice ?

回答1:

Use this ...

output.add("1 2 3 4 5 6 7 8 9 10");  
String bigger[] = output.get(i).split(" ");
int biggerWher = Arrays.asList(bigger).indexOf("3");

回答2:

When the array is an array of objects, then:

Object[] array = ..
Arrays.asList(array).indexOf(someObj);

Another alternative is org.apache.commons.lang.ArrayUtils.indexOf(...) which also has overloads for arrays of primitive types, as well as a 3 argument version that takes a starting offset. (The Apache version should be more efficient because they don't entail creating a temporary List instance.)

回答3:

Arrays do not have an indexOf() method; however, java.util.List does. So you can wrap your array in a list and use the List methods (except for add() and the like):

output.add("1 2 3 4 5 6 7 8 9 10");  
String bigger[] = output.get(i).split(" ");
int biggerWhere = Arrays.asList(bigger).indexOf("10");

回答4:

You can use java.util.Arrays.binarySearch(array, item); That will give you an index of the item, if any...

Please note, however, that the array needs to be sorted before searching.

Regards

回答5:

There is no direct indexOf method in Java arrays.

回答6:

output.add("1 2 3 4 5 6 7 8 9 10");

you miss a " after 10.

来源：https://stackoverflow.com/questions/6249537/indexof-in-a-string-array