illegal-characters

Let's say I have the following data frame: a <- runif(10) dd <- as.data.frame(t(a)) names(dd) <- c("ID", "a", "a2", "b", "b2", "f", "XXX", "1", "4", "8") In dplyr , there is a nice way to select a number of columns. For example, to select the columns between column a and column f , I can use dd %>% dplyr::select(a:f) In my problem, the columns of the last part of the data frame may vary, yet they always have as name a number between 1 and 99. However, I can not seem to be able to do the same trick as above: > dd %>% select(1:99) Error: Position must be between 0 and n > dd %>% select("1":"99")

I'm making an Asteroid Field for an Asteroid Game in my Object Oriented Programming class and I am receiving an illegal character error: '\u200b'. The issue seems to be happening on line 12. (The line between import java.awt.Point; and public class Asteroid extends PolyBlob) /* * University of Central Florida * COP3330 - Spring 2016 * Author: Aundray Ortiz */ package asteroidfield; import java.util.Random; import blobzx.PolyBlob; import blobzx.BlobUtils; import java.awt.Point; ​ public class Asteroid extends PolyBlob { private static final Random random = new Random(); public Asteroid(int a,

I was thinking about Registering an Application to a URL Protocol and I'd like to know, what characters are allowed in a scheme? Some examples: h323 (has numbers) h323:[<user>@]<host>[:<port>][;<parameters>] z39.50r (has a . as well) z39.50r://<host>[:<port>]/<database>?<docid>[;esn=<elementset>][;rs=<recordsyntax>] paparazzi:http (has a : ) paparazzi:http:[//<host>[:[<port>][<transport>]]/ So, what characters can I fancy using? Can we have... @:TwitterUser #:HashTag $:CapitalStock ?:ID-10T ...etc., as desired, or characters in the scheme are restricted by standard? According to RFC 2396 ,

In C# (.net 4.0 and 4.5 / vs2010 and vs12) when I serialize an object containing a string having an illegal character using XMLSerializer, no error is thrown. However, when I deserialize that result, an "invalid character" error is thrown. // add to XML Items items = new Items(); items.Item = "\v hello world"; // contains "illegal" character \v // variables System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(Items)); string tmpFile = Path.GetTempFileName(); // serialize using (FileStream tmpFileStream = new FileStream(tmpFile, FileMode.Open,

I'm looking for a regular expression that removes illegal characters. But I don't know what the characters will be. For example: In a process, I want my string to match ([a-zA-Z0-9/-]*) . So I would like to replace all characters that don't match the regexp above. That would be: [^a-zA-Z0-9/-]+ [^ ] at the start of a character class negates it - it matches characters not in the class. See also: Character Classes Michael Freidgeim Thanks to Kobi 's answer I've created a helper method to strips unaccepted characters . The allowed pattern should be in Regex format, expect them wrapped in square

Let's say I have a data.frame, like so: x <- c(1:10,1:10,1:10,1:10,1:10,1:10,1:10,1:10,1:10,1:10) df <- data.frame("Label 1"=x,"Label 2"=rnorm(100)) head(df,3) returns: Label.1 Label.2 1 1 1.9825458 2 2 -0.4515584 3 3 0.6397516 How do I get R to stop automagically replacing the space with a period in the column name? ie, "Label 1" instead of "Label.1". You don't. With the space you desire the format would not satisfy the requirements for an identifier that come to play when you use df$column.1 -- that could not cope with a space. So see the make.names() function for details or an example: >