hyperlink

How to make link of the database in PHP

删除回忆录丶 提交于 2019-12-23 04:51:40
问题 Hi I want to show URL as a link in PHP the URL is shown by query from database but it is not a link so I want to make it link like using <a href=""></a> but I don't know what I am doing wrong My data show like this in browser ID Name URL 2 This localhost/p_uploads/00.jpg 3 Nissan localhost/p_uploads/7a.jpg I want these URL's to be link so anyone can click on the url to open the image Here is my PHP Code: <?php if(!isset($_COOKIE['loggedin'])){ header("location:index.php"); } session_start();

PHP str_replace to change link paths

淺唱寂寞╮ 提交于 2019-12-23 04:35:37
问题 I'm using file_get_contents to get a certain files contents. So far that is working. But then I would want to search the file and replace all <a href=" with <a href="site.php?url= before showing the file. How can I do this? I know I should use some kind of str_replace or even preg_replace . But I don't know how to actually search and do it for the file I'm getting with file_get_contents . 回答1: file_get_contents returns a string containing the file's content. So, you can work in this string

Link practice without “/” in the beginning of href

為{幸葍}努か 提交于 2019-12-23 04:34:43
问题 I am using this rewrite code to be able to link like this http://page.com/subpage but still be working with html files like so http://page.com/subpage.html (all html files are located in the root folder). RewriteEngine On RewriteCond %{SCRIPT_FILENAME} !-d RewriteRule ^([^\.]+)$ $1.html [NC,L] Would it be good practise to have a menu like this (without the "/" on the subpages)? <a href="/">Home</a> <a href="subpage-1">Subpage 1</a> <a href="subpage-2">Subpage 2</a> <a href="subpage-3">Subpage

How to convert a link that has javascript:__doPostBack in href to normal url which wget/curl/lynx can understand?

本小妞迷上赌 提交于 2019-12-23 03:55:08
问题 I searched in SO first, and found this question. How to click a link that has javascript:__doPostBack in href? but it gives the answer in python only. What I need is, when go through a website, some pages (2,3,4, etc) with links like below: javascript:__doPostBack('AspNetPager1','2') javascript:__doPostBack('AspNetPager1','3') javascript:__doPostBack('AspNetPager1','4') If I click it, and it will display the next page, but the real url isn't displayed in browser. So my questions is, how can I

Laravel Pagination with pretty urls than query string

拜拜、爱过 提交于 2019-12-23 03:32:44
问题 with credit to the user called Kindari @ irc room #laravel in freenode , also credit goes to user iampseudo and Debolaz . with following laravel route code, Route::bind('key_pairs', function($s) { // some logic to transform string to associative array $arr = explode("/",$s); $arr2 = array(); if(count($arr)%2 == 0) { for($i=0;$i<count($arr);$i+=2) { $arr2[$arr[$i]] = $arr[$i+1]; } } return $arr2; }); Route::get('foo/{key_pairs}', function($key_pairs) { var_dump($key_pairs); })->where('key

Laravel Pagination with pretty urls than query string

你离开我真会死。 提交于 2019-12-23 03:32:10
问题 with credit to the user called Kindari @ irc room #laravel in freenode , also credit goes to user iampseudo and Debolaz . with following laravel route code, Route::bind('key_pairs', function($s) { // some logic to transform string to associative array $arr = explode("/",$s); $arr2 = array(); if(count($arr)%2 == 0) { for($i=0;$i<count($arr);$i+=2) { $arr2[$arr[$i]] = $arr[$i+1]; } } return $arr2; }); Route::get('foo/{key_pairs}', function($key_pairs) { var_dump($key_pairs); })->where('key

Xcode clang link: Build Dynamic Framework (or dylib) not embed dependencies

冷暖自知 提交于 2019-12-23 03:31:34
问题 I’m building a dynamic framework for iOS. It needs reference some symbols from code or other libraries, but I not want link them into the framework. This can be achieved when build an static library, just setup search path and make sure them not included in target’s build phases. But when build a dynamic framework or dylib, this result undefined symbol error. I tried all kinds of link options, eg -l -weak_library -weak_framework -I -rpath -rpath-link . But none works. The link command looks

Create hyperlink to some text in NSTextView

て烟熏妆下的殇ゞ 提交于 2019-12-23 03:14:54
问题 I can create a hyperlink to some url in an NSTextView using the "Link Panel". Or I can add a link manually using the NSLinkAttributeName attribute of NSAttributedString. I don't want to make a hyperlink to some external url though, I want to be able to create a hyperlink to some text within the NSTextView. Do you know how in Pages you can set some text as a Bookmark, and then you can make a hyperlink to that bookmark? Any ideas or examples of how to go about that? 回答1: I haven't done this in

Linking to an id not working in Firefox - Working in Chrome/Safari

跟風遠走 提交于 2019-12-23 02:55:08
问题 I am trying to link to a specific id on another page in a rails app. The html markup that I am targeting is: <h3 id="about">About</h3> When I manually put localhost:3000/#about into the browser address bar, it opens up to the correct spot in the page in Chrome and Safari. But when I paste that path into Firefox, it seems to stall - it opens up midway through the first page. Then if I hit enter on my keyboard again in the address bar, it goes to the correct spot. Any ideas what may be causing

How to get link_to in Rails output an SEO friendly url?

冷暖自知 提交于 2019-12-23 02:36:35
问题 My link_to tag is: <%= link_to("My test title",{:controller=>"search", :action=>"for-sale", :id=> listing.id, :title => listing.title, :search_term => search_term}) %> and produces this ugly URL: http://mysite.com/search/for-sale/12345?title=premium+ad+%2B+photo+%5Btest%5D How can I get link_to to generate: http://mysite.com/search/for-sale/listing-title/search-term/12345 Been trying this a few different ways and cannot find much online, really appreciate any help! 回答1: Tahe a look at this