hue

css3控制字体动态变换颜色

由 ▼魔方 西西 提交于 2019-12-05 03:18:33
css3控制字体动态变换颜色 <!doctype html> <html> <head> <meta charset="utf-8"> <title>css3文字颜色更改</title> </head> <style> .site__title { color: #f35626; font-family: 微软雅黑; background-image: -webkit-linear-gradient(92deg, #f35626, #feab3a); -webkit-background-clip: text; -webkit-text-fill-color: transparent; -webkit-animation: hue 10s infinite linear; } @-webkit-keyframes hue { from { -webkit-filter: hue-rotate(0deg); -moz-filter: hue-rotate(0deg); } to { -webkit-filter: hue-rotate(-360deg); -moz-filter: hue-rotate(-360deg); } } </style> <body> <h1 class="site__title">色彩会变</h1> </body> </html> 来源： https:/

Impala SQL: Merging rows with overlapping dates. WHERE EXISTS and recursive CTE not supported

由 若如初见. 提交于 2019-12-04 13:58:40
I am trying to merge rows with overlapping date intervals in a table in Impala SQL. However the solutions I have found to solve this are not supported by Impala eg. WHERE EXISTS and recursive CTEs. How would I write a query for this in Impala? Table: @T ID StartDate EndDate 1 20170101 20170201 2 20170101 20170401 3 20170505 20170531 4 20170530 20170531 5 20170530 20170831 6 20171001 20171005 7 20171101 20171225 8 20171105 20171110 Required Output: StartDate EndDate 20170101 20170401 20170505 20170831 20171001 20171005 Example of what I am trying to achieve that is not supported in Impala:

Install Hue without Cloudera

由 老子叫甜甜 提交于 2019-12-04 01:37:55
Has anyone tried/succeeded in installing Hue on Hadoop without Cloudera? I have gotten to a point where I can reliably reproduce a hadoop cluster with hbase and hive and can set it all up in about 15 minutes. I'd love to have Hue along with all this without having to go back and redo my setup with Cloudera. Checkout slides #19 & #5, Hue is getting everywhere and is compatible with Hadoop 0.20 / 1.2.0 / 2.2.0: http://gethue.com/hue-goes-to-paris-hug-france/ Hue has tarball releases releases that you are free to install. You can also simply clone the source code (Hue is open source and Apache

How to calculate mean and standard deviation for hue values from 0 to 360?

由 余生颓废 提交于 2019-12-03 14:22:13
Suppose 5 samples of hue are taken using a simple HSV model for color, having values 355, 5, 5, 5, 5, all a hue of red and "next" to each other as far as perception is concerned. But the simple average is 75 which is far away from 0 or 360, close to a yellow-green. What is a better way to calculate this mean and associated std? The simple solution is to convert those angles to a set of vectors, from polar coordinates into cartesian coordinates. Since you are working with colors, think of this as a conversion into the (a*,b*) plane. Then take the mean of those coordinates, and then revert back

Rotate Hue in C#

由 匿名 (未验证) 提交于 2019-12-03 08:51:18
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm looking to replicate the CSS3 hue rotation behaviour found here original image image with hue rotated 180deg I can already accurately convert an RGB value to a HSL value and back again but I'm not sure what the mathematical function to apply to the hue component to replicate the output is. 回答1: Addition. It's that simple, just add 180 to the hue value, then make sure that it wraps around at 360: hue = (hue + 180) % 360; 回答2: I wanted to point out how to actually do this. This was the exact question, but no good answer. Given a GDI+ Image

Converting RGB to HSB Colors

由 匿名 (未验证) 提交于 2019-12-03 08:28:06
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to convert a HSB Color to RGB. The way I am doing that is System.Windows.Media.Color winColor = value; System.Drawing.Color drawColor = System.Drawing.Color.FromArgb(winColor.R, winColor.G, winColor.B); Hue = (byte)(drawColor.GetHue()*255); Saturation = (byte)(drawColor.GetSaturation()*255); Luminosity = (byte)(drawColor.GetBrightness()*255); I find that when I have FF0000 , it will be converted to H = 0, S = 255, L = 127 which converts to RGB FF0E0E . I think Luminosity should be 120? Or am I getting the whole HSB thing wrong?

How to connect backend service with philips hue bridge remotely?

由 匿名 (未验证) 提交于 2019-12-03 02:49:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm looking to write a philips hue service that needs to allow users to register their hue bridge with my service. This service would change the color of bulbs based on an event. I'm aware that I can use IFTTT but in this scenario, I'd like to not use IFTTT and I'd like to register my website with philips hue's apps. Any idea how I can do this? Your help is very much appreciated. Thanks! EDIT: Not sure why I was down voted but I definitely did do my research. I looked on philips hue's developer website and couldn't find anything

Fastest formula to get Hue from RGB

由 匿名 (未验证) 提交于 2019-12-03 02:46:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: If you are given red, green, and blue values that range from 0-255, what would be the fastest computation to get just the hue value? This formula will be used on every pixel of a 640x480 image at 30fps (9.2 million times a second) so every little bit of speed optimization helps. I've seen other formulas but I'm not happy with how many steps they involve. I'm looking for an actual formula, not a built in library function. 回答1: Convert the RGB values to the range 0-1, this can be done by dividing the value by 255 for 8-bit color depth (r,g,b -

Given a hex for a color, how can I make that color lighter and darker? [duplicate]

由 匿名 (未验证) 提交于 2019-12-03 02:33:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: Return lighter color from SKColor using HSL lightness factor 2 answers Let's say I have a hex such as: 5fc9f8 Is there a function that accepts "levels of darkness" (-10 to 10) and returns a hex that reflects that? By darkness I mean add black/remove black from the color. 回答1: import UIKit extension String { subscript (range: Range<Int>) -> String { return range.startIndex < 0 || range.endIndex > count(self) ? "Out of Range" : substringWithRange(Range(start:advance(startIndex,range.startIndex),end
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