httpserver

问题 We have a Web Application on Tomcat. The App accesses content(confidential) from dedicated Apache HTTPServers. We do not want un-authorized users accessing this content. i.e. Only users authenticated through WebApp(on Tomcat) can access HttpServer content. (We are using HTTPS to secure the network, but if someone gets the direct httpserver url for content they may download content). We are thinking of hosting content in side the same webapp on Tomcat. Any ideas? 回答1: The easy/lazy way to do

问题 How can create session used with in idhttpserver ? I tryed alot of ways to do but I can't able to reach session object in ARequestInfo.Session or AResponseInfo.Session these are both of them always nil. please help procedure TFolsecPermissionManager.IdHTTPServerCommandGet(AContext: TIdContext; ARequestInfo: TIdHTTPRequestInfo; AResponseInfo: TIdHTTPResponseInfo); var Command: TCommand; Session: TIdHTTPSession; begin Session := IdHTTPServer.CreateSession(AContext, AResponseInfo, ARequestInfo);

问题 I have a following code snippet to make my HttpServer a multithreaded one,but its still working as single threaded.Can you please help me out? I'm using Java HttpServer API : // Bind to port 8083 httpServer = HttpServer.create(new InetSocketAddress(HTTP_PORT), 0); // Adding '/send' context httpServer.createContext("/send", new SendHandler()); ExecutorService executor = Executors.newCachedThreadPool(); httpServer.setExecutor(executor); // Start the server httpServer.start(); Full Java Class :

问题 I am implement html5 player. It is similar to streaming, but it is not strictly streaming. First I tried. Using Media Source Extensions. But I can not implement seeking. I do not know the byte offset. So I thought. If you can create an http server in your browser, I can only respond to range requests. Can I create http server in browser using javascript? It is support mobile/pc browser. It is must support mobile/pc browser. 回答1: Can I create http server in browser using javascript? No.

问题 The Google Cloud documentation isn't very precise on the available syntax for the app.yaml file used for my Node.js application. I used the syntax described in the Python documentation for GAE, from which I've found the handlers mecanism: handlers: - url: /index.html static_files: /public/index.html upload: /public/index.html I've avoid my expressjs rule to serve the /public/index.html content and finally I got a 404 error, meaning GAE is not serving my page as a static content: $ curl -i

问题 I have some email PHP Scripts which I do not want the user to have a look by a GET, but I am using it to send as an email, using wufoo's webHook if anyone knows about it, so it uses POST so I just want POST Requests to be allowed otherwise, 403 or 404 how do I do that? I tried some answers given on SO and browsed documentation of apache web server, the best answer I found was this: RewriteEngine On RewriteCond %{REQUEST_METHOD} !=GET RewriteRule ^.*$ /path/to But I suppose this should be

问题 I have a java echo httpserver up. It works with test sites, but the client code I'm working with fails to get the data. The server works perfectly with https://www.hurl.it/ The client works perfectly with https://requestb.in/ and http://httpbin.org/post When combining the two I get a response with a status code of 200, but no metadata / body content shows up in the client even though it's being sent. My only guess is because the content type isn't included, the client might be picky about

问题 I want to customize 404 response, that the server (not me) throws whenever it can't find a requested resource, (or throw a customized WebApplicationException myself, if it's possible to test if a requested resource is present in one app? probably a List of resources is stored somewhere?). please don't refer me to solutions that suggest to extend WebApplicationException, because even doing so, my problem is when to throw it?, when resource is not found! but how to express this need in jersey

问题 This question was migrated from Server Fault because it can be answered on Stack Overflow. Migrated 4 years ago . I would like to launch a SimpleHTTPServer in a separate thread, while doing something else (here, time.sleep(100) ) in the main one. Here is a simplified sample of my code: from SimpleHTTPServer import SimpleHTTPRequestHandler from BaseHTTPServer import HTTPServer server = HTTPServer(('', 8080), SimpleHTTPRequestHandler) print 'OK UNTIL NOW' thread = threading.Thread(target =

问题 I'm trying to implement a simple HTTP endpoint for an application written in node.js. I've created the HTTP server, but now I'm stuck on reading the request content body: http.createServer(function(r, s) { console.log(r.method, r.url, r.headers); console.log(r.read()); s.write("OK"); s.end(); }).listen(42646); Request's method, URL and headers are printed correctly, but r.read() is always NULL. I can say it's not a problem in how the request is made, because content-length header is greater