http-status-code-404 | 易学教程

CodeIgniter 404 Page Not Found, but why?

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I am using CodeIgniter for two applications (a public and an admin app). The important elements of the document structure are: /admin /admin/.htaccess /admin/index.html /application /application/admin /application/public /system .htaccess index.php The /admin/.htaccess file looks like this: DirectoryIndex index.php RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ ./index.php/$1 [L,QSA] The /admin/index.php has the following changes: $system_folder = "../system"; $application_folder = "../application/admin"; (this line exists of course

Route mit special characters are not parsed correctly in Zend Framework 2

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URIs with german special characters don't work (error 404). I've already had this problem ( here ) and it has been resolved with the unicode modifier and a custom view helper , that uses it. Now I have the same issue with a Segment child route, but this time the approach with the unicode identifier and a custom view helper isn't working. Alle requests like sld.tld/sport/sportäöüÄÖÜß/cityäöüÄÖÜß or sld.tld/sport/sportäöüÄÖÜß/cityäöüÄÖÜß/page/123 are ending with a 404 error. /module/Catalog/config/module.config.php <?php return array( ... 'router' => array( 'routes' => array( 'catalog' => array(

How to call servlet from jQuery $.ajax without getting HTTP 404 error

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I am trying to call a servlet using ajax call as below: $.ajax({ url: 'CheckingAjax', type: 'GET', data: { field1: "hello", field2 : "hello2"} , contentType: 'application/json; charset=utf-8', success: function (response) { //your success code alert("success"); }, error: function (errorThrown) { //your error code alert("not success :"+errorThrown); } }); However, it goes to error function and shows alert: not success :Not Found How is this caused and how can I solve it? When you specify a relative URL (an URL not starting with scheme or / ), then it will become relative to the current request

How to determine if a url object returns '404 Not Found'?

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Simply put: if x <- read.csv(url) exists, then R will return the contents of that url. A good example, if you want to try it, might be " http://ichart.finance.yahoo.com/table.csv?s=IBM&a=00&b=1&c=2008&d=03&e=4&f=2014&g=d&ignore=.csv " . That particular url, if assigned to url and run as above, will load up a data.frame into x from the Yahoo website containing the past 5 years of IBM stock data. But how to tell, beforehand, if any given url will get you 404'd ? something like: is.404.or.not(url) or maybe status(connect.to(url)) Thanks! You could use the RCurl package: R> library(RCurl) Loading

NSError * domain: @“com.google.HTTPStatus” - code: 404

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问题 I am trying to read images from Firebase storage, and I am getting this error: NSError * domain: @"com.google.HTTPStatus" - code: 404 In function: - (void)invokeFetchCallbacksOnCallbackQueueWithData:(GTM_NULLABLE NSData *)data error:(GTM_NULLABLE NSError *)error { // Callbacks will be released in the method stopFetchReleasingCallbacks: GTMSessionFetcherCompletionHandler handler; @synchronized(self) { GTMSessionMonitorSynchronized(self); handler = _completionHandler; if (handler) { [self

WebClient.DownloadString(url) when this url returns a 404 page, how can i skip this?

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I'm using WebClient.DownloadString(url) to download a web page, when a url a 404 web page it stops and doesn't work anymore. I want to skip these pages when I got this fault. if the url is 404 page, it doesn't start to download. so i can't parse the undownloaded data... You will have to catch the Exception and test for a 404: try { string myString; using (WebClient wc = new WebClient()) myString= wc.DownloadString("http://foo.com"); } catch (WebException ex) { if (ex.Status == WebExceptionStatus.ProtocolError && ex.Response != null) { var resp = (HttpWebResponse)ex.Response; if (resp

PHP: prevent direct access to page

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问题 I have some pages that I don't want users to be able to access directly. I have this function I came up with which works: function prevent_direct_access() { if($_SERVER['REQUEST_URI'] == $_SERVER['PHP_SELF']) { //include_once('404.php'); header("Location: 404.php"); } } This does exactly what I want, the URL does not change but the content does. However I am wondering if there is something I need to add to tell search engines that this is a 404 and not to index it. keep in mind I do not want

node.js + express + socket.io cannot load javascript files into index.html

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问题 I'm developing an application and the server is currently set up and working well. This is the index.html that shows when you access the server: <!doctype html> <html> <head> <title>Socket.IO chat</title> </head> <body> <script src="https://cdn.socket.io/socket.io-1.2.0.js"></script> <script type="text/javascript" src="./client.js"></script> <script type="text/javascript" src="./main.js"></script> </body> </html> However I get a 404 error "Failed to load resource: the server responded with a

include after PHP 404 header returning “Oops! This link appears to be broken.”

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To make a long story short, I have dynamic pages on a website that display reviews. If there are no reviews associated with a particular city/county/area/etc the mysql query returns 0 rows which triggers the following code: if (!$validRevQuery) { header("HTTP/1.0 404 Not Found"); include("http://{$PDS['site']}/404.php?request=".urlencode($_SERVER['REQUEST_URI'])); exit; } On some webhosts this triggers a "URL file-access is disabled" error. Which is fine, but on the ones that allow URL file-access, the 404 file is included and properly displayed. I changed the code slightly to display an

HttpWebResponse returns 404 error

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How to let Httpwebresponse ignore the 404 error and continue with it? It's easier than looking for exceptions in input as it is very rare when this happens. I'm assuming you have a line somewhere in your code like: HttpWebResponse response = request.GetResponse() as HttpWebResponse; Simply replace it with this: HttpWebResponse response; try { response = request.GetResponse() as HttpWebResponse; } catch (WebException ex) { response = ex.Response as HttpWebResponse; } try { HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create("http://mysite.com"); HttpWebResponse response =