hql

Hibernate4实战 之 第三部分:Hibernate的基本开发

邮差的信 提交于 2019-12-01 20:37:15
1:瞬时(Transient) - 由new操作符创建,且尚未与Hibernate Session 关联的对象被认定为瞬时的。瞬时对象不会被持久化到数据库中,也不会被赋予持久化标识(identifier)。 如果瞬时对象在程序中没有被引用,它会被垃圾回收器销毁。 使用Hibernate Session可以将其变为持久状态,Hibernate会自动执行必要的SQL语句。 2:持久(Persistent) - 持久的实例在数据库中有对应的记录,并拥有一个持久化标识。 持久的实例可能是刚被保存的,或刚被加载的,无论哪一种,按定义,它存在于相关联的Session作用范围内。 Hibernate会检测到处于持久状态的对象的任何改动,在当前操作单元执行完毕时将对象数据与数据库同步。开发者不需要手动执行UPDATE。将对象从持久状态变成瞬时状态同样也不需要手动执行DELETE语句。 3:脱管(Detached) - 与持久对象关联的Session被关闭后,对象就变为脱管的。 对脱管对象的引用依然有效,对象可继续被修改。脱管对象如果重新关联到某个新的Session上, 会再次转变为持久的,在脱管期间的改动将被持久化到数据库。 通过Session接口来操作Hibernate 新增——save方法、persist方法 1:persist() 使一个临时实例持久化。然而

Hibernate4实战 之 第三部分:Hibernate的基本开发

不问归期 提交于 2019-12-01 20:32:33
1:瞬时(Transient) - 由new操作符创建,且尚未与Hibernate Session 关联的对象被认定为瞬时的。瞬时对象不会被持久化到数据库中,也不会被赋予持久化标识(identifier)。 如果瞬时对象在程序中没有被引用,它会被垃圾回收器销毁。 使用Hibernate Session可以将其变为持久状态,Hibernate会自动执行必要的SQL语句。 2:持久(Persistent) - 持久的实例在数据库中有对应的记录,并拥有一个持久化标识。 持久的实例可能是刚被保存的,或刚被加载的,无论哪一种,按定义,它存在于相关联的Session作用范围内。 Hibernate会检测到处于持久状态的对象的任何改动,在当前操作单元执行完毕时将对象数据与数据库同步。开发者不需要手动执行UPDATE。将对象从持久状态变成瞬时状态同样也不需要手动执行DELETE语句。 3:脱管(Detached) - 与持久对象关联的Session被关闭后,对象就变为脱管的。 对脱管对象的引用依然有效,对象可继续被修改。脱管对象如果重新关联到某个新的Session上, 会再次转变为持久的,在脱管期间的改动将被持久化到数据库。 通过Session接口来操作Hibernate 新增——save方法、persist方法 1:persist() 使一个临时实例持久化。然而

hibernate--HQL语法与详细解释

女生的网名这么多〃 提交于 2019-12-01 20:02:03
HQL查询: Criteria查询对查询条件进行了面向对象封装,符合编程人员的思维方式,不过HQL(Hibernate Query Lanaguage)查询提供了更加丰富的和灵活的查询特性,因此 Hibernate将HQL查询方式立为官方推荐的标准查询方式,HQL查询在涵盖Criteria查询的所有功能的前提下,提供了类似标准SQL语句的查询方式,同时也提供了更 加面向对象的封装。完整的HQL语句形势如下: Select/update/delete…… from …… where …… group by …… having …… order by …… asc/desc 其中的update/delete为Hibernate3中所新添加的功能,可见HQL查询非常类似于标准SQL查询。由于HQL查询在整个Hibernate实体操作体系中的核心地位,这一节我 将专门围绕HQL操作的具体技术细节进行讲解。 1、 实体查询: 有关实体查询技术,其实我们在先前已经有多次涉及,比如下面的例子: String hql=”from User user ”; List list=session.CreateQuery(hql).list(); 上面的代码执行结果是,查询出User实体对象所对应的所有数据,而且将数据封装成User实体对象,并且放入List中返回。这里需要注意的是

【hibernate系列】hibernate的n+1问题

一个人想着一个人 提交于 2019-12-01 20:00:05
什么叫n+1次select查询问题? 在Session的缓存中存放的是相互关联的对象图。默认情况下,当Hibernate从数据库中加载Customer对象时,会同时加载所有关联的Order对象。以Customer和Order类为例,假定ORDERS表的CUSTOMER_ID外键允许为null,图1列出了CUSTOMERS表和ORDERS表中的记录。 以下Session的find()方法用于到数据库中检索所有的Customer对象: List customerLists=session.find("from Customer as c"); 运行以上find()方法时,Hibernate将先查询CUSTOMERS表中所有的记录,然后根据每条记录的ID,到ORDERS表中查询有参照关系的记录,Hibernate将依次执行以下select语句: select * from CUSTOMERS; select * from ORDERS where CUSTOMER_ID=1; select * from ORDERS where CUSTOMER_ID=2; select * from ORDERS where CUSTOMER_ID=3; select * from ORDERS where CUSTOMER_ID=4; 通过以上5条select语句

How to dynamically search between two dates in hql?

眉间皱痕 提交于 2019-12-01 17:04:07
问题 I have two Date search field namely from and to. I have to retrieve records from the user table whose startDate lies between the from and to dates entered in the search fields and if the from and to dates are null I have to retrieve all the records from the user table. I tried the following hql query: FROM USER WHERE :start_flag =1 OR STARTDATE between :from and :to Here start_flag is of type int which is set to 1 if from and to are null. query.setParameter("from",startDt); query.setParameter

How to put 'null' into column using HQL?

眉间皱痕 提交于 2019-12-01 16:54:34
How to build valid HQL string, which is equivalent to UPDATE table SET field = null WHERE .... Do you mean bulk HQL update? Try this UPDATE myEntity e SET e.myProperty = null WHERE ... You can also use a parameterized version of the above UPDATE myEntity e SET e.myProperty = :param WHERE ... In your code: int updatedEntities = session.createQuery(updateQueryHQL) .setString( "param", myValue ) // or .setString( "param", null ) .executeUpdate(); See documentation for details. If you're not doing bulk updates, you should just set your property to NULL and persist the entity normally. Why does

hibernate: Unable to locate appropriate constructor on class - HQL

有些话、适合烂在心里 提交于 2019-12-01 15:41:18
When I trying to execute this HQL to return an object Ponto I receive this error: ERROR [org.hibernate.hql.PARSER] (http-localhost-127.0.0.1-8080-2) Unable to locate appropriate constructor on class [br.com.cdv.model.entity.Ponto] [cause=org.hibernate.PropertyNotFoundException: no appropriate constructor in class: br.com.cdv.model.entity.Ponto] DAO @SuppressWarnings("unchecked") @Override public List<Ponto> listLoja(Integer idLoja) { Query q = getSession().createQuery("select new Ponto(0,ss.cliente,ss.loja,null,null,null,null,null,sum(qtdPontos),'',0) " + "from Ponto as ss where ss.loja.id =

hibernate: Unable to locate appropriate constructor on class - HQL

让人想犯罪 __ 提交于 2019-12-01 15:19:42
问题 When I trying to execute this HQL to return an object Ponto I receive this error: ERROR [org.hibernate.hql.PARSER] (http-localhost-127.0.0.1-8080-2) Unable to locate appropriate constructor on class [br.com.cdv.model.entity.Ponto] [cause=org.hibernate.PropertyNotFoundException: no appropriate constructor in class: br.com.cdv.model.entity.Ponto] DAO @SuppressWarnings("unchecked") @Override public List<Ponto> listLoja(Integer idLoja) { Query q = getSession().createQuery("select new Ponto(0,ss

HQL make query searching by date (Java+NetBeans)

佐手、 提交于 2019-12-01 12:02:10
问题 Hi all I have the following issue. I have a table of reserves in my MySQL DB, the date columns is defined DATETIME. I need to make a query using hibernate to find all reserves in one day no matter the hour, just that its the same year month and date, and I'm doing this public List<Reserve> bringAllResByDate(Date date){ em = emf.createEntityManager(); Query q = em.createQuery("SELECT r FROM Reserve r WHERE r.date=:date "); q.setParameter("date", date); ... I really dont know how to make it

hibernate query language or using criteria?

☆樱花仙子☆ 提交于 2019-12-01 11:13:49
Any one who tell me the query using criteria/hql/sql. Requirement is that user enter email or username the query return the password of the user from table user. If all you're doing is fetching one field, you probably just want to go hql (or possibly sql). If you do criteria, I believe you're pulling back the entire object, just to eventually use one field. Edit: That's a really broad question. Here is a tutorial The Criteria API is very appropriate for dynamic query generation and would have my preference here. You could do something like this: Criteria criteria = session.createCriteria(User