hql

How to implement pagination in spring boot with hibernate

梦想与她 提交于 2019-12-03 16:19:13
问题 I am using spring boot with hibernate and I want to use pagination in my project. I have searched on google and saw many examples but I am unable to implement it in my project. I want like if I pass 1 in my url then 10 results should come and if I pass 2 then next 10 results should come and so on. Here is my my Dao @Transactional public interface PostDao extends CrudRepository<Post, Long>{ @Query(getAllPostsByRank) List<Post> getAllPostsByRank(); final String getAllPostsByRank= "from Post

Write HQL clause using Hibernate Criteria API

我与影子孤独终老i 提交于 2019-12-03 16:09:14
I want to write a method that returns a list of last added objects grouped by field 'serviceId'. The following HQL works, but I want to write this using Criteria API: FROM Notification WHERE date IN (SELECT MAX(date) FROM Notification GROUP BY serviceId) ORDER BY date ASC Something like this: Criteria crit = session.createCriteria(Notification.class); crit.add(Restrictions.in("date", <MAX dates>)); criteria.addOrder(Order.desc("date")); Thanks in advance. EDIT: Now I need a similar query that works using eclipselink API =/ Basically, I need the last N rows (max date), which status is one of

HQL: Fetch Join Collections from Eager Table

不羁的心 提交于 2019-12-03 13:22:10
I have four tables: RootNode // Will return multiple root nodes SubNode // Will return one sub node per root node SubNodeChildren1 // Will return multiple for each sub node SubNodeChildren2 // Will return multiple for each sub node and a similar entity structure: RootNode -> SubNode -> SubNodeChildren1 -> SubNodeChildren2 I need one query that will return all the RootNodes in the table with its SubNode and SubNode children initialized. The SubNode is eagerly fetched, but the SubNode children is lazy fetched. I know how to write a query that will LEFT OUTER JOIN FETCH the immediate children of

NHibernate Query across multiple tables

半世苍凉 提交于 2019-12-03 12:47:21
I am using NHibernate, and am trying to figure out how to write a query, that searchs all the names of my entities, and lists the results. As a simple example, I have the following objects; public class Cat { public string name {get; set;} } public class Dog { public string name {get; set;} } public class Owner { public string firstname {get; set;} public string lastname {get; set;} } Eventaully I want to create a query , say for example, which and returns all the pet owners with an name containing "ted", OR pets with a name containing "ted". Here is an example of the SQL I want to execute:

Date Compare in HQL without timestamp

两盒软妹~` 提交于 2019-12-03 12:32:12
I have to compare two dates in hibernate hql query. I am using java.util.Date in my java bean and using timestamp as datatype in mysql database. select t from Task t where t.modifiedDate > t.endDate; Above query compares time with date. What should i do to compare date in above query without time. See the Hibernate documentations for available date functions http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/queryhql.html In section 14.10 notice this line second(...), minute(...), hour(...), day(...), month(...), and year(...) So this should work ... where year(t.endDate) > year(t

Ordering a join fetched collection in JPA using JPQL/HQL

喜你入骨 提交于 2019-12-03 11:33:01
Given the below JPQL statement, how do I modify it so that the kittens in the resulting list are ordered by their age property? SELECT c FROM Cat c left join fetch c.kittens WHERE c.id = :id I've tried multiple approches but without any luck. This is esentially what I would like to do, but it doesn't work: SELECT c FROM Cat c left join fetch c.kittens k WHERE c.id = :id ORDER BY k.age Hej, I don't think this is possible when applied using queries. But as far as I remember, you can use this to add default ordering to your collection in the mapping: @OrderBy("myColumName asc") In addition to

Hibernate is using wrong table name for order by expression with three level inheritance

╄→尐↘猪︶ㄣ 提交于 2019-12-03 10:57:53
In our project we have different user types presented by different classes. And we have a BaseEntity class as @MappedSuperclass. When we try to use user classes with InheritanceType.JOINED hibernate creates an sql that we think it is wrong. Base Entity : @MappedSuperclass public abstract class BaseEntity implements java.io.Serializable { private Integer id; private Date createdDate = new Date(); public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } @Temporal(TemporalType.TIMESTAMP) @Column(name = "CREATED_DATE", nullable = true) public Date getCreatedDate() {

Using a join in a Hibernate HQL update query

旧城冷巷雨未停 提交于 2019-12-03 10:43:25
i have the following hibernate mapping: <class name="Domain.Roomreservation, Core" table="Reservationroom"> <id name="ID" unsaved-value="undefined"> <generator class="native"> <!--<param name="sequence">GLOBALSEQUENCE</param>--> </generator> </id> <property name="FromTime" not-null="true" index="IDX_RESRAUM_FromTime" /> <property name="UntilTime" not-null="true" index="IDX_RESRAUM_UntilTime"/> <many-to-one name="Booking" column="Book_ID" index="IDX_RAUMRES_BOOK" lazy="false" class="Domain.Booking, Core" not-null="true" /> </class> And the Reservationroom table looks like: ID <pk> Book_ID <fk>

NHibernate HQL's Equivalent to T-SQL's TOP Keyword

余生颓废 提交于 2019-12-03 09:39:57
What is NHibernate HQL's Equivalent to T-SQL's TOP Keyword? Also what is the non-HQL way for saying give me the first 15 of a class? It's actually pretty easy in HQL: var top15 = session.CreateQuery("from SomeEntity") .SetFirstResult(0) .SetMaxResults(15) .List<SomeEntity>(); Don't know how to do this using the criteria API though. Criteria API Method: ICriteria criteria = DaoSession.CreateCriteria(typeof(T)); criteria.SetFirstResult(StartIndex); criteria.SetMaxResults(MaximumObjects); return criteria.List<T>(); From NHibernate 3.2 you could use SKIP n / TAKE n in hql at the end of the query.

HQL make query searching by date (Java+NetBeans)

匿名 (未验证) 提交于 2019-12-03 09:14:57
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Hi all I have the following issue. I have a table of reserves in my MySQL DB, the date columns is defined DATETIME. I need to make a query using hibernate to find all reserves in one day no matter the hour, just that its the same year month and date, and I'm doing this public List<Reserve> bringAllResByDate(Date date){ em = emf.createEntityManager(); Query q = em.createQuery("SELECT r FROM Reserve r WHERE r.date=:date "); q.setParameter("date", date); ... I really dont know how to make it compare, and bring me just those from the specified