hql

Is it possible to do indexed element access in JPQL like in HQL : select o from Order o where o.items[0].id = 1234 I couldn't find something related in the JPA 2 specs, I am targeting EclipseLink JPA here, so if you come up with an EclipseLink solution, that's ok as well, although a JPQL standard solution is preferred. The INDEX function should do the trick (actually I tested it and it does): SELECT o FROM Order o JOIN o.items i WHERE i.id = 1234 AND INDEX(i) = 0 From the JPA 2.0 specification ( 4.6.17.2.2 Arithmetic Functions ): The INDEX function returns an integer value corresponding to the

I am new with this. Please help me. My inner join looks like this: select p.idprodus, p.denumire, p.cantitate from Produs p inner join Furnizor f on p.idfurn = f.idfurn I want to make the inner join on the column idfurn, but I get these errors: org.hibernate.QueryException: outer or full join must be followed by path expression select p.idprodus, p.denumire, p.cantitate from sakila.entity.Produs p inner join Furnizor f on p.idfurn = f.idfurn at org.hibernate.hql.classic.FromParser.token(FromParser.java:170) at org.hibernate.hql.classic.ClauseParser.token(ClauseParser.java:86) at org.hibernate

I have figured out that I can use hibernate to get the sum of a number of entities using HQL as follows... public Long getEnvelopeTotal(AbstractEnvelope envelope) { String query = "select sum(t.amount) from User_Transaction t"; Long result = (Long) hibernateUtil.getSession().createQuery(query).uniqueResult(); return result; } Currently the rest of my application is able to seamlesly navigate the database via the object graph only. The problem with having to use the function above is that I have to do the following psuedo code... Get instance of Entity "Envelope" Pass Envelope instance i Based

I'm getting crazy with an error that I'm having using Spring MVC 3.1.2 and Jackson 2. I have the following model Class: @Entity @Table(name = "USER") @JsonIgnoreProperties(ignoreUnknown=true) public class User implements Serializable { @Id @SequenceGenerator(name = "USER_ID", sequenceName = "USER_ID_SEQ", allocationSize = 1) @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "USER_ID") private Long id; @Column(length = 50, nullable = false) private String firstName; @Column(length = 50, nullable = false) private String lastName; @ManyToMany @JoinTable(name = "FRIENDS", joinColumns

i want to achieve the following in HQL - select top n from table1 where table1.id IN (some select sub query) i have found the setMaxResult(n) method, but it can only retrieve top n of the entire result.. but what i want to achieve is top n of each group... Thanks... Here is JPQL you need: select a from Employee a where ( select count(*) from Employee b where a.department = b.department and a.salary <= b.salary ) <= 10 order by salary DESC 来源： https://stackoverflow.com/questions/4264528/hql-query-to-retrieve-top-n-from-each-group