hours

更新一下时间倒计时插件（jQUery） 1 $.fn.genTimer = function (e) { 2 function u(e) { 3 var t = Math.floor(e / n), 4 r = Math.floor((e - t * n) / 36e5), 5 i = Math.floor((e - t * n - r * 1e3 * 60 * 60) / 6e4), 6 s = Math.floor((e - t * n - r * 1e3 * 60 * 60 - i * 1e3 * 60) / 1e3); 7 return { 8 hours: ("0" + r).slice(-2), 9 minutes: ("0" + i).slice(-2), 10 seconds: ("0" + s).slice(-2), 11 dates: t 12 } 13 } 14 if (this.data("handled")) return this; 15 this.data("handled", !0); 16 var t = { 17 beginTime: new Date, 18 day_label: "day", 19 days_label: "days", 20 unitWord: { 21 hours: ":", 22 minutes: ":", 23

1.首先是先将时间取出来并保存起来 var now = new Date();//新建一个时间对象 var hours = now.getHours();//取出当前小时数,保存于变量中 var minutes = now.getMinutes();//取出当前分钟数,保存地变量中 var seconds = now.getSeconds();//取出当前秒数 (1.1 显示统一格式,用两位数字统一显示时间格式,如:09:20:00 ,只要分别判断数值是否小于9,小于9就在前面加0,) if (hours<=9) hours = "0"+hours; if (minutes<=9) minutes = "0"+minutes; if (seconds<=9) seconds = "0"+seconds; 2.之后要解决的问题就在网页上显示出来,可以使用form,利用input 的值进行显示,这里我使用另一种方法,在一个带ID的标签作为该内容显示出来 2.1首先在HTML 里建一个标签,这里使用标签<span>,并且定义ID=TIME, 代码如下: < html > < head ></ head > < body > < span id =time ></ span > < body > </ html > 2.2 接着要解决就是把时间显示到该标签的内容中 var showtime

用于获取当前日期字符串 /** * 获取当前的日期时间 格式“yyyy-MM-dd HH:MM:SS” * @return {} */ getNowFormatDate : function () { var date = new Date(); var seperator1 = "-"; var seperator2 = ":"; var month = date.getMonth() + 1; var strDate = date.getDate(); if (month >= 1 && month <= 9) { month = "0" + month; } if (strDate >= 0 && strDate <= 9) { strDate = "0" + strDate; } var hours = date.getHours(); if(hours >=0 && hours <=9){ hours = "0" + hours; } var minutes = date.getMinutes(); if(minutes >=0 && minutes <=9){ minutes = "0" + minutes; } var seconds = date.getSeconds(); if(seconds >=0 && seconds <=9){ seconds = "0"

昨天晚上搭建好了k8s多主集群，启动了一个nginx的pod，然而每启动一个pod就伴随这一个pause容器，考虑到之前在做kubelet的systemd unit文件时有见到： 123456 [root@node01 ~]CONTAINER ID IMAGE COMMAND CREATED STATUS PORTS NAMES43884d79fe6f nginx "nginx -g 'daemon of…" 11 hours ago Up 11 hours k8s_nginx-pod_nginx-con-594b8d6b48-46gf7_default_25b0048f-a24f-11e9-8149-00163e0134cf_0eff67394c9c8 nginx "nginx -g 'daemon of…" 11 hours ago Up 11 hours k8s_nginx-pod_nginx-con-594b8d6b48-vt589_default_25aefc99-a24f-11e9-8149-00163e0134cf_1261226f6b92a registry.cn-hangzhou.aliyuncs.com/google_containers/pause-amd64:3.1 "/pause" 11 hours ago Up 11 hours k8s_POD

【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 今天有人把数据库两个time类型的字段查出来并做了减法，得到一个长形的数字。这个数字是什么？ 首先在数据库里建立一张test表（mysql的数据库） CREATE TABLE `NewTable` ( `id` int(10) NOT NULL AUTO_INCREMENT , `time1` timestamp NULL DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP , `time2` timestamp NULL DEFAULT NULL , PRIMARY KEY (`id`) ) 然后录入两条数据，用如下语句查询 SELECT time2,time1,time2-time1 FROM `test`; 查询结果如下，结论是这个差值1的单位貌似是秒。 2012-05-15 19:02:17 2012-05-15 19:02:16 1 把time1和time2的类型改成date。这个结果的单位是0. 把time1和time2的类型改成datetime，这个结果如下，貌似单位还是秒。 2012-05-15 19:02:16 2012-05-15 19:02:17 -1.000000 今天遇到的数字结果不确定的情形并没有复现，难道数据库是因为数据库的类型是oracle？

Harbor启动都是多个容器的，首先查看一下是否有相关容器未启动 docker ps | grep harbor cae340214e57 goharbor/nginx-photon:v1.9.3 "nginx -g 'daemon of…" 4 hours ago Up 15 minutes (unhealthy) 0.0.0.0:10000->8080/tcp nginx a111d0141ed8 goharbor/harbor-jobservice:v1.9.3 "/harbor/harbor_jobs…" 4 hours ago Up 12 minutes (healthy) harbor-jobservice 66010e33921c goharbor/harbor-core:v1.9.3 "/harbor/harbor_core" 4 hours ago Up 11 minutes (healthy) harbor-core 6c522b6bb1a6 goharbor/clair-photon:v2.1.0-v1.9.3 "/docker-entrypoint.…" 4 hours ago Up 11 minutes (healthy) 6060-6061/tcp clair 5b9d873b61e0 goharbor/harbor-db:v1.9.3 "/docker

// 连字符转驼峰 String.prototype.hyphenToHump = function () { return this.replace(/-(\w)/g, (...args) => { return args[1].toUpperCase() }) } // 驼峰转连字符 String.prototype.humpToHyphen = function () { return this.replace(/([A-Z])/g, '-$1').toLowerCase() } // 日期格式化 Date.prototype.format = function (format) { const o = { 'M+': this.getMonth() + 1, 'd+': this.getDate(), 'h+': this.getHours(), 'H+': this.getHours(), 'm+': this.getMinutes(), 's+': this.getSeconds(), 'q+': Math.floor((this.getMonth() + 3) / 3), S: this.getMilliseconds(), } if (/(y+)/.test(format)) { format = format.replace(RegExp.$1, `${this

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm trying to get a report from my history table by hourly usage. history table is; CREATE TABLE IF NOT EXISTS `history` ( `history_id` int(11) unsigned NOT NULL AUTO_INCREMENT, `user_id` int(11) unsigned NOT NULL DEFAULT '0', `created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`history_id`), KEY `user_id` (`user_id`), KEY `created` (`created`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ; I want to group by HOUR and COUNT all records in a given date range. Hours | Usage --------------------

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I get an error with this query. Why? I don't understand :( SELECT p.name, p.id, SUM(hours) AS hours, SUM(logged_hours) AS logged_hours FROM ( SELECT project_id, date, hours, null AS logged_hours FROM #{ScheduleEntry.table_name} WHERE user_id = #{User.current.id} AND date BETWEEN '%s' AND '%s' UNION SELECT project_id, spent_on AS date, null AS hours, sum(#{TimeEntry.table_name}.hours) AS logged_hours FROM #{TimeEntry.table_name} WHERE user_id = #{User.current.id} AND spent_on BETWEEN '%s' AND '%s' GROUP BY project_id, date ) AS results LEFT

定义一个表示时间的类Time ，它提供下面操作： a)Time(hours,minutes,seconds)创建一个对象； b) t.hours(),t.minutes(),t.seconds()分别 返回时间对象t的小时，分钟和秒值； c)为Time对象定义加法和减法操作 d)定义时间对象的等于和小于关系运算 代码示例： class Time : def __init__ ( self , hours , minutes , seconds ): self . hours = hours self . minutes = minutes self . seconds = seconds def hours ( self ): return self . hours def minutes ( self ): return self . minutes def seconds ( self ): return self . seconds def __add__ ( self , another ): hours = (( self . hours * 3600 + self . minutes * 60 + self . seconds + another . hours * 3600 + another . minutes * 60 + another . seconds )