hour

问题 I want to calculate the average for each hours using a CSV file: Below is my DATA SET: Timestamp Temperature 9/1/2016 0:00:08 53.8 9/1/2016 0:00:38 53.8 9/1/2016 0:01:08 53.8 9/1/2016 0:01:38 53.8 9/1/2016 0:02:08 53.8 9/1/2016 0:02:38 54.1 9/1/2016 0:03:08 54.1 9/1/2016 0:03:38 54.1 9/1/2016 0:04:38 54 9/1/2016 0:05:38 54 9/1/2016 0:06:08 54 9/1/2016 0:06:38 54 9/1/2016 0:07:08 54 9/1/2016 0:07:38 54 9/1/2016 0:08:08 54.1 9/1/2016 0:08:38 54.1 9/1/2016 0:09:38 54.1 9/1/2016 0:10:32 54 9/1

问题 I want to calculate the average for each hours using a CSV file: Below is my DATA SET: Timestamp Temperature 9/1/2016 0:00:08 53.8 9/1/2016 0:00:38 53.8 9/1/2016 0:01:08 53.8 9/1/2016 0:01:38 53.8 9/1/2016 0:02:08 53.8 9/1/2016 0:02:38 54.1 9/1/2016 0:03:08 54.1 9/1/2016 0:03:38 54.1 9/1/2016 0:04:38 54 9/1/2016 0:05:38 54 9/1/2016 0:06:08 54 9/1/2016 0:06:38 54 9/1/2016 0:07:08 54 9/1/2016 0:07:38 54 9/1/2016 0:08:08 54.1 9/1/2016 0:08:38 54.1 9/1/2016 0:09:38 54.1 9/1/2016 0:10:32 54 9/1

问题 I want to calculate the average for each hours using a CSV file: Below is my DATA SET: Timestamp Temperature 9/1/2016 0:00:08 53.8 9/1/2016 0:00:38 53.8 9/1/2016 0:01:08 53.8 9/1/2016 0:01:38 53.8 9/1/2016 0:02:08 53.8 9/1/2016 0:02:38 54.1 9/1/2016 0:03:08 54.1 9/1/2016 0:03:38 54.1 9/1/2016 0:04:38 54 9/1/2016 0:05:38 54 9/1/2016 0:06:08 54 9/1/2016 0:06:38 54 9/1/2016 0:07:08 54 9/1/2016 0:07:38 54 9/1/2016 0:08:08 54.1 9/1/2016 0:08:38 54.1 9/1/2016 0:09:38 54.1 9/1/2016 0:10:32 54 9/1

问题 According to the toLocaleString() MDN Documentation the option hour: "2-digit" should return a 2 digit representation of the hour, but it returns only 1 digit if the locale is en-US and the format is AM/PM . (Update: AM/PM mention) let d = new Date("2019-05-03 15:00:00").toLocaleString("en-US", {hour: "2-digit", minute: "2-digit"}); console.log(d); Is there a workaround or another easy way to get the 2-digit hour for the US locale, displaying the AM and PM? 回答1: You just have to explicitly

问题 I need a regular expression for hours in PHP, I am using ereg. I need it to accept 1-23 without leading zeros. ^([1-9])|([1][0-9])|([2][0-3])$ That's what I am using but I cannot find where is the mistake. 回答1: Alternations ( | ) apply to everything in the surrounding group or globally if not in a group. So in your pattern, the ^ only applies to the first pattern and the $ only applies to the last pattern. In other words, your pattern matches any string which begins with a digit from 1 to 9,

问题 I am using this code to generate a range of hourly datetime 's: from datetime import datetime, timedelta def daterange(start_date, end_date): # timedelta only has days and seconds attributes for n in range(int ((end_date - start_date).seconds/3600 + 1)): yield start_date + timedelta(n) start_date = datetime(2013, 1, 1, 14, 00) end_date = datetime(2015, 6, 2, 5, 00) for single_date in daterange(start_date, end_date): print single_date.strftime("%Y-%m-%d %H:%M") But I am getting an unexpected

问题 I am using this code to generate a range of hourly datetime 's: from datetime import datetime, timedelta def daterange(start_date, end_date): # timedelta only has days and seconds attributes for n in range(int ((end_date - start_date).seconds/3600 + 1)): yield start_date + timedelta(n) start_date = datetime(2013, 1, 1, 14, 00) end_date = datetime(2015, 6, 2, 5, 00) for single_date in daterange(start_date, end_date): print single_date.strftime("%Y-%m-%d %H:%M") But I am getting an unexpected

问题 I need help please, How can I calculate business hours between two dates? For example we have two dates; 01/01/2017 10:00 and 04/01/2017 15:00. And we have working hours 09:30 to 17:30 (8 hours) on weekdays. How can I calculate working hours and minutes with Java? Thanks for your help. 回答1: Off the top of my head. Let me suggest you begin by studying the java.time package with subpackages, the modern Java date and time API. There’s an Oracle tutorial as well as other good reading material on

问题 I’m fairly new to R and it would be great if you could help out with this problem as i havent been able to find any answers to this problem online. This is part of my data frame (DF) (it goes on until 2008 in this format) Counter Date Hour counts 1245 26/05/2006 0 1 1245 26/05/2006 100 0 1245 26/05/2006 200 2 1245 26/05/2006 300 0 1245 26/05/2006 400 5 1245 26/05/2006 500 3 1245 26/05/2006 600 9 1245 26/05/2006 700 10 1245 26/05/2006 800 15 This is my question: I need to subset my code so

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 6 years ago . How can I isolate and convert the local time format in JavaScript's new Date() to a 24 hour format? Example: 2016-09-22T23:21:56.027Z just becomes 22:56 in local time. 回答1: new Date("2000-01-01 10:30 AM").getHours() // 10 This is 24 hours: new Date("2000-01-01 10:30 PM").getHours() // 22 If you