hibernate-mapping

i try to create composite primary key in table from 2 foreign key using hibernate JPA,but gives me error.I find some solution on net but nothing The relations between tables looks like this: Table Client clientID(PK) FirstName LastName . Table CarService serviceID(PK) DescriptionOfFailure . . Table ServiceDepartment clientID(PK) serviceID(PK) price . implementation of my code looks like this: @Entity public class ServiceDepartmentBean implements ServiceDepartmentI { @EmbeddedId private ServiceDepartmentPK serviceDepartmentPK = new ServiceDepartmentPK(); @Column(name="clientID", nullable=false,

I'm having two entities Car and CarDescription where CarDescription is depending on another foreign key from the table Language . What I' trying to accomplish is to have a HashMap in Car such that whenever I'm having a Car entity-object I am able to access all descriptions from the language id. Entity Car.java @Entity @Table(name = "Car") public class Car extends AbstractTimestampEntity implements Serializable { private static final long serialVersionUID = -5041816842632017838L; @Id @GeneratedValue(strategy=GenerationType.IDENTITY) @Column(name = "ID", unique = true, nullable = false) private

Here is parent class Enterprise. It has employers and one of them is president of enterprise. @Entity class Enterprise { // fields @OneToMany public List<Employee> getEmployers() // implementation @OneToOne public Employee getPresident() // implementation } Here is child Employee class. It has only info about Enterprise where he works. But question is what association should I use? @Entity class Employee { // fields // what association should I use? public Enterprise getEnterprise() // implementation } Given that you've defined the Enterprise -> Employers association with @OneToMany , which

I'm using Hibernate as our Object-Relational Mapping, with a custom dialect for an obscure database. The Entity I'm retrieving from this database has a column thus: @Column(name = "GROSS_WEIGHT", precision = 9, scale = 3) private BigDecimal grossWeight; The database has this column defined as numeric with a precision of 9 and a scale of 3. I can see the SQL that Hibernate generates to retrieve the data, and when I perform the same Query using the database query tool it returns '9.68' for the GROSS_WEIGHT column. However, in the Entity that is retrieved by Hibernate, the 'grossWeight' field

Im trying to configure my entities but hibernate throws the following exception: org.hibernate.MappingException: Could not determine type for: com.sd.entity.SDUserProductAcess, at table: SDUser, for columns: [org.hibernate.mapping.Column(productAccess)] [PersistEngine] Failed to initialize persistence engine!java.lang.NullPointerException These are my Entities: @Entity @Inheritance(strategy = InheritanceType.JOINED) public class SDObject { @Id @GeneratedValue private long sdId; private String sdType; public long getSdId() { return sdId; } public void setSdId(long sdId) { this.sdId = sdId; }

Suppose I have this enum: public enum TestEnum { EXAMPLE, FURTHER_EXAMPLE, LAST_EXAMPLE } With this mapping in the .hbm : <property name="testEnum" column="TEST_COLUMN"> <type name="org.hibernate.type.EnumType"> <param name="enumClass">p.a.c.k.TestEnum</param> </type> </property> The enum is sent to the database as 0 , 1 , 2 . I'd like the values to be instead stored as EXAMPLE , FURTHER_EXAMPLE or LAST_EXAMPLE in a varchar column. How can I map enum to a varchar column? bvulaj Add this as a parameter of EnumType: <param name="type">12</param> This is because 12 is equivalent to java.sql.Types

Working on some legacy hibernate code. How do I do the following with hbm.xml(hibernate mapping file) instead of with annotations? @Table(name="users", uniqueConstraints = { @UniqueConstraint(columnNames={"username", "client"}), @UniqueConstraint(columnNames={"email", "client"}) }) public class User implements Serializable { private static final long serialVersionUID = 1L; @Id private int id; private String username; private String email; private Client client; } Use the properties tag: ... <properties name="uk1" unique="true"> <property name="username" .../> <many-to-one name="client" .../> <