hibernate-mapping

How do I use a sequence in Hibernate XML mappings? The documentation mentions the <generator> element. However, I want the sequence to be a column instead of an ID. Karl Walsh I know when using Hibernate with Oracle the id in the mapping file is defined something like: <id name="id" column="item_id"> <generator class="sequence"> <param name="sequence">NAME_OF_YOUR_SEQUENCE</param> </generator> </id> You can also specify the generator class as "native", which is handy if you then switch to an auto incrementing RDMS such as MySQL. The sequence bit is then ignored in MySQL. Edit: Just re-read

This question already has an answer here: @OrderBy causing org.hibernate.HibernateException: Unable to parse order-by fragment 3 answers I'm trying to use the @OrderBy annotation on a Spring MVC project that run on a JBoss EAP 6.1+ server. I have 2 projects: the first one is named model-gen-wifipnsd and it contains only the model classes that are used by the second project (named WIFIPNSD ) that represent the web application. 1) So for the model-gen-wifipnsd I have this pom.xml file: <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi

I have made a class with name of Movie with folowing fields: @Id @GeneratedValue private Long id; private String name; @ElementCollection(targetClass = String.class) private Map<String, String> properties; private Double rate; private Integer votersCount; private Date releaseDate; private Integer runtime; @ManyToMany @JoinTable(name = "movie_director") @IndexColumn(name = "directorIndex") private List<Person> directors; @ManyToMany @JoinTable(name = "movie_writer") @IndexColumn(name = "writerIndex") private List<Person> writers; @OneToMany @IndexColumn(name = "roleIndex") private List

Assuming the following mappings are provided: <class name="A" table="a_table"> <id name="id"/> <many-to-one name="entityB" column="fk_B" not-null="false" unique="true"/> </class> <class name="B" table="b_table"> <id name="id"/> </class> Java class: public class A { private long id; private B entityB; // getters and setters skipped } Is it possible to change the Hibernate mapping so that foreign key is still enforced and created by Hibernate upon startup , but class A would look like as the following: public class A { private long id; private long idOfB; // getters and setters skipped } I

I've got a User an a Log class (which I cannot change): class User { private long id; private String name; private Set<Log> accessLogs; private Set<Log> actionLogs; } class Log { private String what; private Date when; } A possible mapping will look like: <class name="com.example.User" table="users"> <id name="id" access="field"> <generator class="native" /> </id> <property name="name" length="256" /> <set name="accessLogs" table="user_access_logs" cascade="all-delete-orphan" order-by="`when`"> <key column="user_id" /> <composite-element class="com.example.Log"> <property name="what" length=