hash

问题 sub function{ my $storedata=shift; my $storenameandaddress=$storedata->{$storeid}->{name} ."_".$storedata->{$storeid}->{location}->{address} ."_".$storedata->{$storeid}->{location}->{city} ."_".$storedata->{$storeid}->{location}->{state} ."_".$storedata->{$storeid}->{location}{country};} My codes are shown above. and it gives me error message: Using a hash as a reference is deprecated at main.pl line 141. However, the function is still runable. And all the rests seem fine. So what is this

问题 Relating to this: stack overflow question, where I found out that .Net dictionaries resize to the next prime size that is at least twice the current size, I was wondering if there is any balanced tree-like data structure that can resize to prime sizes (similar to B-Trees or Binomial trees maybe). What is the tree-like data structure behind .Net's dictionaries? Thanks. 回答1: The Dictionary uses a hash table algorithm, which stores the data in an array, it is this array that is sized/re-sized

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I have 2 arrays of the following form: root rhino root root root root root root root root root root domainte root stam rhino jam onetwo domante ftpsi jay testwp contra raul vnod foos raul bruce Notice that they are of equal length (and always will be). I want to create a hash such that there is one single key

问题 I am trying to break a javascript object in to small array so that I can easily access the innerlevel data whenever I needed. I have used recursive function to access all nodes inside json, using the program http://jsfiddle.net/SvMUN/1/ What I am trying to do here is that I want to store these in to a separate array so that I cn access it like newArray.Microsoft= MSFT, Microsoft; newArray.Intel Corp=(INTC, Fortune 500); newArray.Japan=Japan newArray.Bernanke=Bernanke; Depth of each array are

问题 This is a similar question to Linear Probing Runtime but it regards quadratic probing. It makes sense to me that "Theoretical worst case is O(n)" for linear probing because in the worst case, you may have to traverse through every bucket(n buckets) What would runtime be for quadratic probing? I know that quadratic probes in a quadratic fashion -1, 4, 9, 16, ..... My initial thought was that it's some variation of log n(exponential) but there isn't a consistent base. 回答1: If there are n - 1

问题 I am trying to create a nested hash from an array that has several elements saved to it. I've tried experimenting with each_with_object , each_with_index , each and map . class Person attr_reader :name, :city, :state, :zip, :hobby def initialize(name, hobby, city, state, zip) @name = name @hobby = hobby @city = city @state = state @zip = zip end end steve = Person.new("Steve", "basketball","Dallas", "Texas", 75444) chris = Person.new("Chris", "piano","Phoenix", "Arizona", 75218) larry =

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 5 years ago . How do I keep duplicates and maintain order? For example: keys = [1, 2, 1] values = ["a", "b", "c"] Hash[keys.zip(values)] # => {1=>"c", 2=>"b"} 回答1: As Justin & Luca said: Hashes don't allow duplicate keys. Best you can do is by having array of values, found this solution in this SO question: Hash

问题 I have a directory $tmp that contains files with the name syntax .X*-lock as well as other plain files and directories. I compare the contents of $tmp with values in a hash table corresponding to .X*-lock file names that should NOT be deleted. I then want the script to delete any, and ONLY .X*-lock files that aren't in the hash table. It cannot delete plain files (non "." files), directories, or . & .. here's some code: my %h = map { $_ => 1 } @locked_ports; #open /tmp and find the .X*-lock

问题 When a user registers at our site we check the address with an address validation service. This service can return an address suggestion if the entered address is found but has some errors. This sugggestion is returned to the user. The user can accept the suggestion and is trusted. If he changes the address he is not trusted. Is there a good way to check if the data displayed to the user is the same as the data he posts? I guess I need a hidden field with the hash of the addressdata. But I am

问题 Hey Friends, I'm trying to implement a java "hash" function in ruby. Here's the java side: import java.nio.charset.Charset; import java.security.MessageDigest; /** * @return most significant 8 bytes of the MD5 hash of the string, as a long */ protected long hash(String value) { byte[] md5hash; md5hash = md5Digest.digest(value.getBytes(Charset.forName("UTF8"))); long hash = 0L; for (int i = 0; i < 8; i++) { hash = hash << 8 | md5hash[i] & 0x00000000000000FFL; } return hash; } So far, my best