gson

问题 I am trying to use Gson to deserialize a json string returned from my webservice The structure would be returned as TypeDTO[] . where TypeDTO is like int id; String name; ArrayList<ItemDTO> items[] and ItemDTO is like int id; String name; Boolean valid; When I call the code as follows Gson gson = new Gson(); TypeDTO[] mytypes = (TypeDTO[]) gson.fromJson(reply, TypeDTO[].class); Everything inside the objects is null However, If I use the JSONArray and JSONObject to pull them out piece by piece

问题 I have requirement where I need to convert java object to json. I am using Gson for that but i need the converter to only serialize the non null or not empty values. For example: //my java object looks like class TestObject{ String test1; String test2; OtherObject otherObject = new OtherObject(); } now my Gson instance to convert this object to json looks like Gson gson = new Gson(); TestObject obj = new TestObject(); obj.test1 = "test1"; obj.test2 = ""; String jsonStr = gson.toJson(obj);

问题 I have a JsonObject named "mapping" with the following content: { "client": "127.0.0.1", "servers": [ "8.8.8.8", "8.8.4.4", "156.154.70.1", "156.154.71.1" ] } I know I can get the array "servers" with: mapping.get("servers").getAsJsonArray() And now I want to parse that JsonArray into a java.util.List ... What is the easiest way to do this? 回答1: Definitely the easiest way to do that is using Gson's default parsing function fromJson() . There is an implementation of this function suitable for

问题 I have a JsonObject named "mapping" with the following content: { "client": "127.0.0.1", "servers": [ "8.8.8.8", "8.8.4.4", "156.154.70.1", "156.154.71.1" ] } I know I can get the array "servers" with: mapping.get("servers").getAsJsonArray() And now I want to parse that JsonArray into a java.util.List ... What is the easiest way to do this? 回答1: Definitely the easiest way to do that is using Gson's default parsing function fromJson() . There is an implementation of this function suitable for

问题 There are some other answers to this question on here but not sure how to get them to work with my code. I have a lot of JSON to pass so I need to stream it rather than do it all at once. I cannot quite get the errors out of the code. Here is my code: HttpGet request = new HttpGet(getUri + "&" + credentials.getOauthStructure()); HttpResponse response = client.execute(request); ICustomerDAO customerDAO = (ICustomerDAO) DAOFactory.getDAO( ICustomerDAO.class.getName(), context); customerDAO.open

问题 My app try to consume an API using Retrofit and Gson . My request is to https://nahuatiliztli.herokuapp.com/laws.json and it returns back: [{"id":1,"title":"Constitución Política de los Estados Unidos Mexicanos","url":"http://www.diputados.gob.mx/LeyesBiblio/pdf/1_29ene16.pdf","created_at":"2016-07-10T02:36:00.641Z","updated_at":"2016-07-10T02:36:00.641Z"}] My code is structured as follow… My model is Law class: public class Law { @SerializedName("id") private Integer mId; @SerializedName(

问题 I am trying to write simple function that converts Json strings into Objects. The language I am using is objective-c however this question discusses issues doesn't relate to this lang. My question is, How to know the Type of Objects that laid inside a json array that is to be mapped into non-parameterized (a.k.a non-generic) lists?? I found two Json Java libraries unable to solve this issue, Jakson and Gson and here's the example: import java.io.Serializable; import java.util.List; import com

问题 I am getting response in a sequence: "parameters": { "parameter": { "Data":"value" } }, "parameters":{ "parameter": [ { "Data":"value" }, { "Data":"value" }, ] }, Getting the error if I call List<Class> parameter: Expected BEGIN_OBJECT but getting BEGIN_ARRAY I need to parse parameter to get values public class ApiClient { public static final String BASE_URL ="http://........."; private static Retrofit retrofit = null; public static Retrofit getClient() { OkHttpClient client = new

问题 I want to include in my Service objects a generic way of deserializing lists of objects from a json string. Below was my first attempt. public abstract class AbstractService<T>{ public abstract Class<T> getClazz(); public List<T> deserialize(final String json){ Gson gson = gsonFactory.create(); Type listType = new TypeToken<List<T>>() {}.getType(); List<T> entityList = gson.fromJson(json, listType); return entityList; } } However due to type erasure, the T in: new TypeToken<List<T>>() {}

问题 I am parsing a json string using gson . It is similar to this: { "ACode": "aa", "RCode": "rr", "Errors": "e1,e2,e3" } I think that the errors should have been a proper json array, but I don't have control of that. I want to get the errors into an array or collection in java . This is easy enough using String.split with comma as separator. However I am new to gson and I don't know if I would be ignoring functionality that it provides to parse a comma separated string. Does anyone know whether