gpu-warp

Some intrinsics named with `_sync()` appended in CUDA 9; semantics same?

拟墨画扇 提交于 2019-12-04 15:13:29
In CUDA 9, nVIDIA seems to have this new notion of "cooperative groups"; and for some reason not entirely clear to me, __ballot() is now (= CUDA 9) deprecated in favor of __ballot_sync() . Is that an alias or have the semantics changed? ... similar question for other builtins which now have __sync() added to their names. No the semantics are not the same. The function calls themselves are different, one is not an alias for another, new functionality has been exposed, and the implementation behavior is now different between Volta architecture and previous architectures. First of all, to set the

__activemask() vs __ballot_sync()

﹥>﹥吖頭↗ 提交于 2019-12-03 21:52:39
After read this post on CUDA Developer Blog I am struggling to understand when is safe\correct use __activemask() in place of __ballot_sync() . In section Active Mask Query , the authors wrote: This is incorrect, as it would result in partial sums instead of a total sum. and after, in section Opportunistic Warp-level Programming they are using the function __activemask() because: This may be difficult if you want to use warp-level programming inside a library function but you cannot change the function interface. There is no __active_mask() in CUDA. That is a typo (in the blog article). It

__activemask() vs __ballot_sync()

荒凉一梦 提交于 2019-12-03 20:33:10
问题 After read this post on CUDA Developer Blog I am struggling to understand when is safe\correct use __activemask() in place of __ballot_sync() . In section Active Mask Query , the authors wrote: This is incorrect, as it would result in partial sums instead of a total sum. and after, in section Opportunistic Warp-level Programming they are using the function __activemask() because: This may be difficult if you want to use warp-level programming inside a library function but you cannot change

Do the threads in a CUDA warp execute in parallel on a multiprocessor?

 ̄綄美尐妖づ 提交于 2019-12-02 00:24:39
A warp is 32 threads. Does the 32 threads execute in parallel in a Multiprocessor? If 32 threads are not executing in parallel then there is no race condition in the warp. I got this doubt after going through the some examples. In the CUDA programming model, all the threads within a warp run in parallel. But the actual execution in hardware may not be parallel because the number of cores within a SM (Stream Multiprocessor) can be less than 32. For example, GT200 architecture have 8 cores per SM, and the threads within a warp would need 4 clock cycles to finish the execution. If multiple

Why bother to know about CUDA Warps?

ε祈祈猫儿з 提交于 2019-11-28 16:21:35
问题 I have GeForce GTX460 SE, so it is: 6 SM x 48 CUDA Cores = 288 CUDA Cores. It is known that in one Warp contains 32 threads, and that in one block simultaneously (at a time) can be executed only one Warp. That is, in a single multiprocessor (SM) can simultaneously execute only one Block, one Warp and only 32 threads, even if there are 48 cores available? And in addition, an example to distribute concrete Thread and Block can be used threadIdx.x and blockIdx.x. To allocate them use kernel <<<

How are CUDA blocks divided into warps?

a 夏天 提交于 2019-11-27 04:39:29
If I start my kernel with a grid whose blocks have dimensions: dim3 block_dims(16,16); How are the grid blocks now split into warps? Do the first two rows of such a block form one warp, or the first two columns, or is this arbitrarily-ordered? Assume a GPU Compute Capability of 2.0. Threads are numbered in order within blocks so that threadIdx.x varies the fastest, then threadIdx.y the second fastest varying, and threadIdx.z the slowest varying. This is functionally the same as column major ordering in multidimensional arrays. Warps are sequentially constructed from threads in this ordering.

How are CUDA blocks divided into warps?

强颜欢笑 提交于 2019-11-26 08:24:59
问题 If I start my kernel with a grid whose blocks have dimensions: dim3 block_dims(16,16); How are the grid blocks now split into warps? Do the first two rows of such a block form one warp, or the first two columns, or is this arbitrarily-ordered? Assume a GPU Compute Capability of 2.0. 回答1: Threads are numbered in order within blocks so that threadIdx.x varies the fastest, then threadIdx.y the second fastest varying, and threadIdx.z the slowest varying. This is functionally the same as column