goto

I'm working on a simplish game (this isn't the whole code, just the bit that I'm having issues with) and I've run into this issue; After the condition is furfilled, it goes back to the start and it offers me to reenter the string, however, whatever I enter, I just get 'Not Valid' . Does anyone know why? I'm using the GNU C++ Compiler . #include <iostream> #include <string> using namespace std; int main() { string command; mainscreen: cout << "blab"; getlinething: cin.ignore(); getline(cin, command); if (command == "task") { goto mainscreen; } else { cout << "Not valid."; goto getlinething; }

I have some image files. I'm trying to perform some calculations using each file and if a certain condition is met, I'd like to go back to a particular line in the code and run it from there once more. But only just once again. Regardless of whether the if condition is satisfied or not satisfied the second time, I want to go to the next iteration. But, MATLAB doesn't seem to have a goto function and also, using goto implies bad programming so I thought I'd just iterate the for loop twice for a particular 'i' value which satisfies the if condition. file = dir('*.jpg'); n = length(file); for i =

This question already has an answer here: Why is scanf() causing infinite loop in this code? 15 answers In the example below, if I enter a character in Mac OS X terminal, the program will get stuck in an infinite loop, printing Please enter a number: line after line and never allowing the user to input anything. What's wrong with this code? What is the fix? I want to change the code in a way that if a number is not entered, the user is prompted with an error message and asked to enter a number again. #include <stdio.h> int main(int argc, const char * argv[]) { int number = 0, isnumber; getagin

so in some sample code from this upcoming Core Audio Book i've encountered an unfamiliar symbol cleanup: which is used before some dispose(myStuff) functions are called. It's not preceded by an '@' or a '#'. Seems you can type any word, followed by a colon, and it will act like a comment? int main (int argc, const char * argv[]) { @autoreleasepool { NSLog(@"i am code."); cleanup: foop: lol: NSLog(@"even more code."); } return 0; } It's not a comment. It's a label specifying a location for goto . E.g. int main (int argc, const char * argv[]) { while (1) { printf("Is this an infinite loop?\n");

This question already has an answer here: Examples of good gotos in C or C++ [closed] 16 answers I know lots of questions about why not use goto , why goto is bad practice, why goto was create by devil, why the fingers of those who type goto should be ripped off, etc... And in many answers to this questions , this question , and even at wikipedia it's possible to find reasons pro / against goto . Even Stackoverflow has a goto tag :) But, obviously, goto is accepted as a valid command, otherwise your compiler / interpreter wouldn't know what to do with it. Even in C / C++ it's possible to use

This question is a duplicate of Goto Still Considered Harmful . If you wish to discuss this further please use the original question. Why exactly is GOTO poor programming practise? It makes sense on some occasions to use it. Note that Djkstra wrote "GOTO Considered Harmful", not "GOTO Considered Deadly". It has its places. Unfortunately, the judgement to know when to use it comes after you've got some experience in maintaining other people's code, especially code that was written years ago by people who no longer work in your company. Thus, it's best to avoid goto as much as you can until you

I have a piece of code like the following: try { Work: while(true) { // Do some work repeatedly... } } catch(Exception) { // Exception caught and now I can not continue // to do my work properly // I have to reset the status before to continue to do my work ResetStatus(); // Now I can return to do my work goto Work; } Are there better alternatives compared to using goto ? Or is this a good solution? It sounds like you really want a loop. I'd write it as: bool successful = false; while (!successful) { try { while(true) { // I hope you have a break in here somewhere... } successful = true; }