goto

问题 I'm trying below code. It gives me a warning "Use of unassigned local variable 'hak' ". I guess I'm missing something here. I want it to display " 3 defa yanlış giriş yaptınız. Müşteri hizmetleri temsilcisiyle görüşünüz. İyi günler dileriz. " when local variable "hak" equals to "0". But it always display " Hatalı Giriş Yaptınız. Lütfen tekrar deneyiniz. 2 hakkınız kalmıştır. " Console.Write("Seçmek istediğiniz 'Kullanıcı Adı'nı belirtiniz: "); string kullanici_adi = Console.ReadLine();

问题 This question already has answers here : GOTO still considered harmful? [closed] (49 answers) Closed 6 years ago . Possible Duplicate: Is there a goto statement in java? Why is goto considered evil in Java, and why is is not suitable for use in high-level programming languages? 回答1: The simplest answer is it makes code unmanageable and difficult to follow after it exceeds certain lines of code. A better reason.. Image courtesy of xkcd 来源： https://stackoverflow.com/questions/13785068/why-is

问题 I wonder if something like this is possible in PHP $goto = 'end'; goto $goto; when I use it I get Parse error: syntax error, unexpected T_VARIABLE, expecting T_STRING . Furthermore, how would I do something like this (considering a() returns true or false ) a() or goto end; as opposed to the longer version if (!a()) goto end; Thanks so much! purely theoretically :) Later edit: This has certainly got a lot of reaction. I think mentioning two of PHP's most debated areas (goto and eval) helped

问题 I have a simple function written to check for directories: :direxist if not exist %~1 ( echo %~1 could not be found, check to make sure your location is correct. goto:end ) else ( echo %~1 is a real directory goto:eof ) :end is written as :end endlocal I don't understand why the program would not stop after goto:end has been called. I have another function that uses the same method to stop the program and it work fine. :PRINT_USAGE echo Usage: echo ------ echo <file usage information> goto

问题 I saw a program in C that had code like the following: static void *arr[1] = {&& varOne,&& varTwo,&& varThree}; varOne: printf("One") ; varTwo: printf("Two") ; varThree: printf("Three") ; I am confused about what the && does because there is nothing to the left of it. Does it evaluate as null by default? Or is this a special case? Edit: Added some more information to make the question/code more clear for my question. Thank you all for the help. This was a case of the gcc specific extension.

问题 I saw a program in C that had code like the following: static void *arr[1] = {&& varOne,&& varTwo,&& varThree}; varOne: printf("One") ; varTwo: printf("Two") ; varThree: printf("Three") ; I am confused about what the && does because there is nothing to the left of it. Does it evaluate as null by default? Or is this a special case? Edit: Added some more information to make the question/code more clear for my question. Thank you all for the help. This was a case of the gcc specific extension.

问题 I am a very beginner in python and I want to repeat this code. But I dont't really know how to do this without "goto". I tried to learn about loops for hours but still no sucess. Any ideas ? import requests addr = input() vendor = requests.get('http://api.macvendors.com/' + addr).text print(addr, vendor) 回答1: Create a function repeat and add your code in it. Then use while True for infinite call or for i in range(6) for 6 times call`: import requests def repeat(): addr = input() vendor =

来源： https://stackoverflow.com/questions/18535283/why-cant-i-add-a-goto-label-at-the-end-of-a-method

问题 Is it good practice to use 'goto' statements in SQL queries? 回答1: Depends on the SQL - some of the dialects don't provide a useful mechanism for flow control other than GOTO. GOTO is generally bad form. 回答2: Not in production code but for testing could be ok. For example, wanting to provide regression testing for a stored procedure where the "common bit" is the call to the procedure being tested and debug statements. declare @test int; set @test = 1; goto tests common: print "common bit"

问题 I unfortunately own a batch program that has duplicate label names. Can anyone explain why the GOTO goes to the label in the second block, not the first? The code: @ECHO OFF SET FLAG=1 IF [%FLAG%]==[1] ( ECHO IN THE FIRST IF... GOTO TD_NEXT :TD_NEXT ECHO HERE AT TD_NEXT IN THE FIRST BLOCK ) IF [%FLAG%]==[1] ( ECHO IN THE SECOND IF... GOTO TD_NEXT :TD_NEXT ECHO HERE AT TD_NEXT IN THE SECOND BLOCK ) The output: IN THE FIRST IF... HERE AT TD_NEXT IN THE SECOND BLOCK I can add a third block, and