google-sheets-formula

Count rows with not empty value

由 大憨熊 提交于 2019-11-29 22:43:55
In a Google Spreadsheet: How can I count the rows of a given area that have a value? All hints about this I found up to now lead to formulas that do count the rows which have a not empty content (including formula), but a cell with =IF(1=2;"";"") // Shows an empty cell is counted as well. What is the solution to this simple task? Make another column that determines if the referenced cell is blank using the function "CountBlank". Then use count on the values created in the new "CountBlank" column. Mike I just used =COUNTIF(Range, "<>") and it counted non-empty cells for me. Delta_zulu =counta

Appending google spreadsheet arrays

由 陌路散爱 提交于 2019-11-29 22:17:29
问题 When I append arrays in google spreadsheets, all of the resulting elements are not rendered in cells. For example, if I enter the formula: ={{1,2,3}, {4,5,6}} the values rendered in spreadsheet cells are 1,4,5,6. Any ideas about why this is happening, or alternatives? My broader problem is to accumulate rows from separate sheets into another sheet - I can do that via ={ImportRange(...), ImportRange(...)} but the same problem is apparent (missing the second element and beyond from the first

Split string and get last element

由 半世苍凉 提交于 2019-11-29 11:17:00
问题 Let's say I have a column which has values like: foo/bar chunky/bacon/flavor /baz/quz/qux/bax I.e. a variable number of strings separated by / . In another column I want to get the last element from each of these strings, after they have been split on / . So, that column would have: bar flavor bax I can't figure this out. I can split on / and get an array, and I can see the function INDEX to get a specific numbered indexed element from the array, but can't find a way to say "the last element"

Multiple IF statements between number ranges

由 痴心易碎 提交于 2019-11-29 02:17:41
问题 I'm trying to set up a formula with multiple IF statements between number ranges but I'm seeing the error: Formula parse error Here is the forumula: =IF((AND(A2>0,A2<500),"Less than 500", If(AND(A2>=500,A2<1000),"Between 500 and 1000"), If(AND(A2>=1000,A2<1500),"Between 1000 and 1500"), If(AND(A2>=1500,A2<2000),"Between 1500 and 2000"))) 回答1: It's a little tricky because of the nested IFs but here is my answer (confirmed in Google Spreadsheets): =IF(AND(A2>=0, A2<500), "Less than 500", IF(AND

Filter a range by array

由 谁都会走 提交于 2019-11-29 00:58:10
问题 I have a Google Spreadsheet containing the teams of the UEFA EURO 2012, and their scores: Team Points Goals scored ------ ------ ------------ Germany 6 3 Croatia 3 3 Ireland 0 1 ... ... ... Now I want to filter that list, so that the result contains only a subset of the teams involved. Specifically, I want the resulting list to contain only the teams Germany, Netherlands, Portugal, Italy, England, France, Spain and Croatia . I know I can use the FILTER function to extract a single value from

Google Spreadsheets: Filter a range by array

由 孤街醉人 提交于 2019-11-28 21:29:59
I have a Google Spreadsheet containing the teams of the UEFA EURO 2012, and their scores: Team Points Goals scored ------ ------ ------------ Germany 6 3 Croatia 3 3 Ireland 0 1 ... ... ... Now I want to filter that list, so that the result contains only a subset of the teams involved. Specifically, I want the resulting list to contain only the teams Germany, Netherlands, Portugal, Italy, England, France, Spain and Croatia . I know I can use the FILTER function to extract a single value from the table. Thus, I could probably write a FILTER expression like =FILTER(A2:C; A2:A = 'Germany' OR A2:A

Count rows with not empty value

由 自作多情 提交于 2019-11-28 18:03:20
问题 In a Google Spreadsheet: How can I count the rows of a given area that have a value? All hints about this I found up to now lead to formulas that do count the rows which have a not empty content (including formula), but a cell with =IF(1=2;"";"") // Shows an empty cell is counted as well. What is the solution to this simple task? 回答1: Make another column that determines if the referenced cell is blank using the function "CountBlank". Then use count on the values created in the new "CountBlank

Is there a script to bypass 50000 characters for in-cell formula?

由 …衆ロ難τιáo~ 提交于 2019-11-28 06:23:32
问题 I have this (insanely) long formula I need to run in Google Sheets, and I came across the limit error: There was a problem Your input contains more than the maximum of 50000 characters in a single cell. Is there a workaround for this? my formula is: =ARRAYFORMULA(SPLIT(QUERY({B!A1:A100; ........ ; CA!DZ1:DZ100}, "select * where Col1 is not null order by Col1 asc", 0), " ")) full formula is: pastebin.com/raw/ZCkZahpw apologies for Pastebin... I got a few errors here too: note 1: due to fact

Count cells that contain any text

由 末鹿安然 提交于 2019-11-28 05:35:36
I want to count the cells that contain anything within a range. Any cell that contain text, or numbers or something else should do a plus one in my result-cell. I found this function, countif(range; criteria) but this doesn't work for me, because I don't know what to type in the criteria. How can I do this? SwDevMan81 You can pass "<>" (including the quotes) as the parameter for criteria . This basically says, as long as its not empty/blank, count it. I believe this is what you want. =COUNTIF(A1:A10, "<>") Otherwise you can use CountA as Scott suggests COUNTIF function will only count cells

How do you get the formula from a cell instead of the value?

由 两盒软妹~` 提交于 2019-11-27 22:15:12
How do you get the literal value (the formula) from a cell instead of the result value? EXAMPLE DESIRED: A2: "Foo" B3: "=A2" - so it displays "Foo" C3: "=CELL("formula", B3)" displays "=A2" Of course, CELL() doesn't support a "formula" parameter, that's just for demonstrating the intent. I've looked over the function list and nothing jumps out at me. USE CASE: I would like to make a reference to another row, and based on that reference get other cells from the row. Putting an explicit row number won't work (e.g. B3 = "2"), since it will not auto-correct when rows are modified. Specifically, I
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