google-api-python-client

google search console, search analytics, get more data

╄→гoц情女王★ 提交于 2019-12-10 11:58:07
问题 I'am trying to use google search console api to get some data out of my website. Below my code used to do that:à service = build('webmasters', 'v3', http=http) collection = service.searchanalytics() request = { 'startDate': '2015-10-24', 'endDate': '2015-10-25', 'dimensions': ['query','page', 'device'], 'searchType': 'web', 'rowLimit': '5000' } response = collection.query(siteUrl=property_uri, body=request).execute() My problem is that I'am only able to about 1000 row. I was wondering if

Google Contacts API - Accessing Other Users

爱⌒轻易说出口 提交于 2019-12-09 03:35:27
I am trying to use the Google Contacts API and the Python / GDATA client handlers to access Contacts via OAuth 2.0 for users in the domain. I'm ultimately wanting to create a web service to add contacts for users, but the first step is getting this test working. I can access my own Contacts just fine if I use the default URI. However, when I pass in the email address to construct the URI for another user, I can't seem to access the other user's Contacts. Here is the code that I'm using: client.GetContacts(uri=client.GetFeedUri(contact_list=userEmail)) A 403 error is returned when I execute

Specifying a Date Range in Google Custom Search api

冷暖自知 提交于 2019-12-08 10:10:39
问题 Its trivial to search a set of keywords in a certain website in a specific date range -> in the google search box you enter: desired-kewords site:desired-website then from the Tools menu you pick the date range. e.g. here "arab spring" search term in www.cnn.com between 1th Jan 2011 and 31th Dec 2013: As you can see in the second picture there are about 773 results! the search URI looks like this : https://www.google.co.nz/search?tbs=cdr%3A1%2Ccd_min%3A1%2F1%2F2011%2Ccd_max%3A12%2F31%2F2013

Move a sheet to a particular position using Python & the Google Sheets API

风流意气都作罢 提交于 2019-12-07 19:31:46
问题 I am trying to use the Google sheet API via python. So far I have been successful in performing some tasks. My problem is for example I have 4 sheets in a particular worksheet in the order of [sheet1][sheet2][sheet3][sheet4]. What I want is to manipulate the positions of the sheets. For example, sheet 4 would now be located at the second position. So now, the positions of the sheets would become [sheet1][sheet4][sheet2][sheet3] Is there a way to do this in python? Thanks! 回答1: It should be

How to Convert XLSX to Sheets in Google Drive API v3

人盡茶涼 提交于 2019-12-07 14:24:36
问题 I want to convert xlsx files automatically to Google spreadsheets when I upload them with my code to Google Drive. However, while the conversion works successfully for csv files, I get: <HttpError 400 when requesting https://www.googleapis.com/upload/drive/v3/files?uploadType=resumable&alt=json returned "Bad Request"> when trying to upload xlsx. Here is my code: def upload_service(filepath, name="", description="", fileID="", parentID=""): """ Uses a Resource (service) object to upload a file

Manage files from public Google Drive URL using PyDrive

六月ゝ 毕业季﹏ 提交于 2019-12-07 13:18:57
问题 I`m using PyDrive QuickStart script to list my Google Drive files. Code: from pydrive.auth import GoogleAuth from pydrive.drive import GoogleDrive gauth = GoogleAuth() gauth.LocalWebserverAuth() drive = GoogleDrive(gauth) file_list = drive.ListFile({'q': "'root' in parents and trashed=false"}).GetList() print(file_list) I'm able to list my files normally, but I need to list and manage files from another public drive URL (which is not the my personal authenticated drive) from my already

No Google Drive files are listed in Drive API request

戏子无情 提交于 2019-12-07 06:02:43
问题 I am trying to get a list of the files in my Google Drive using a desktop app. The code is as follows: def main(argv): storage = Storage('drive.dat') credentials = storage.get() if credentials is None or credentials.invalid: credentials = run(FLOW, storage) # Create an httplib2.Http object to handle our HTTP requests and authorize it # with our good Credentials. http = httplib2.Http() http = credentials.authorize(http) service = build("drive", "v2", http=http) retrieve_all_files(service) Then

Google Python Admin SDK using Oauth2 for a Service Account (Education Edition)-“oauth2client.client.AccessTokenRefreshError: access_denied” exception

萝らか妹 提交于 2019-12-07 04:50:18
问题 I have been trying to get the Service Account authentication working for the Google Admin SDK for a few days now to no avail. I am using the google-api-python-client-1.2 library freshly installed from Google. I have been following Google's documentation on the topic. Links are here: htps://developers.google.com/accounts/docs/OAuth2ServiceAccount htps://developers.google.com/api-client-library/python/guide/aaa_oauth htp://google-api-python-client.googlecode.com/hg/docs/epy/oauth2client.client

google admin sdk directory api 403 python

故事扮演 提交于 2019-12-07 03:15:32
i want to use admin sdk directory api to create eamil account of users. i am using google-api-python-client-1.2 library. in folder /samples/service_account/tasks.py works for me. but when i chance that file to list users from admin directory api it doesn't works and throws errors. below is the code i am using. import httplib2 import pprint import sys import inspect from apiclient.discovery import build from oauth2client.client import SignedJwtAssertionCredentials def main(argv): f = file('my-privatekey.p12', 'rb') key = f.read() f.close() credentials = SignedJwtAssertionCredentials( 'my

Reading in a file with Google datalab

爷,独闯天下 提交于 2019-12-07 03:14:46
问题 I am trying to use Google Datalab to read in a file in ipython notebook, the basic pd.read_csv() as I can't find the path of the file. I have it locally and also uploaded it to google cloud storage in a bucket. I ran the following commands to understand where I am os.getcwd() gives '/content/myemail@gmail.com' os.listdir('/content/myemail@gmail.com') gives ['.git', '.gitignore', 'datalab', 'Hello World.ipynb', '.ipynb_checkpoints'] 回答1: The following reads the contents of the object into a