getline

reading a line from ifstream into a string variable

情到浓时终转凉″ 提交于 2019-11-26 20:27:24
In the following code : #include <iostream> #include <fstream> #include <string> using namespace std; int main() { string x = "This is C++."; ofstream of("d:/tester.txt"); of << x; of.close(); ifstream read("d:/tester.txt"); read >> x; cout << x << endl ; } Output : This Since >> operator reads upto the first whitespace i get this output. How can i extract the line back into the string ? I know this form of istream& getline (char* s, streamsize n ); but i want to store it in a string variable. How can i do this ? jonsca Use the std::getline() from <string> . istream & getline(istream & is,std:

c++ Read from .csv file

我们两清 提交于 2019-11-26 19:06:32
I have this code which is supposed to cout in console the information from the .csv file; while(file.good()) { getline(file, ID, ','); cout << "ID: " << ID << " " ; getline(file, nome, ',') ; cout << "User: " << nome << " " ; getline(file, idade, ',') ; cout << "Idade: " << idade << " " ; getline(file, genero, ' ') ; cout << "Sexo: " << genero<< " " ; } And a csv file that has this (when I open with notepad): 0,Filipe,19,M 1,Maria,20,F 2,Walter,60,M Whenever I run the program the console will display this: My question is why isn't the program repeating those cout messages in every line instead

c++ getline() isn't waiting for input from console when called multiple times

这一生的挚爱 提交于 2019-11-26 18:56:26
I'm attempting to get a few user-input parameters from the console, two strings, two ints and a double. The relevant code I'm trying to use is this: #include <string> #include <iostream> using namespace std; // ... string inputString; unsigned int inputUInt; double inputDouble; // ... cout << "Title: "; getline(cin, inputString); tempDVD.setTitle(inputString); cout << "Category: "; getline(cin, inputString); tempDVD.setCategory(inputString); cout << "Duration (minutes): "; cin >> inputUInt; tempDVD.setDuration(inputUInt); cout << "Year: "; cin >> inputUInt; tempDVD.setYear(inputUInt); cout <<

getline() does not work if used after some inputs [duplicate]

混江龙づ霸主 提交于 2019-11-26 17:40:51
问题 Possible Duplicate: Need help with getline() getline() is not working, if I use it after some inputs, i.e. #include<iostream> using namespace std; main() { string date,time; char journal[23]; cout<<"Date:\t"; cin>>date; cout<<"Time:\t"; cin>>time; cout<<"Journal Entry:\t"; cin.getline(journal,23); cout<<endl; system("pause"); } where as if I use getline() on top of inputs, it does work i.e. cout<<"Journal Entry:\t"; cin.getline(journal,23); cout<<"Date:\t"; cin>>date; cout<<"Time:\t"; cin>

What am I not understanding about getline+strings?

痴心易碎 提交于 2019-11-26 16:43:37
This is my first time using stackoverflow. I've been unable to find out the information I need regarding getline. I'm in a simple programming class for engineering transfers so the code that we write is pretty simple. All i'm trying to do here is put a user-defined number of questions and answers into two different arrays. My while loop looks like this (I was using a for loop but switched to while just to see if it would stop breaking): int main () { srand((unsigned)time(0)); string quest1[100], answ1[100]; int size1, x = 0, num, count1, visit[100], shuffle[100]; fstream flashcard1; cout <<

Are there alternate implementations of GNU getline interface?

回眸只為那壹抹淺笑 提交于 2019-11-26 16:09:15
问题 The experiment I am currently working uses a software base with a complicated source history and no well defined license. It would be a considerable amount of work to rationalize things and release under a fixed license. It is also intended to run a a random unixish platform, and only some of the libc's we support have GNU getline, but right now the code expects it. Does anyone know of a re-implementation of the GNU getline semantics that is available under a less restrictive license? Edit::

awk输入命令getline

筅森魡賤 提交于 2019-11-26 15:14:16
转自:http://www.cnblogs.com/276815076/archive/2011/12/05/2276605.html awk输入命令getline getline为awk所提供的输入命令 如果找到一条记录则getline返回1,如果到了文件结束(EOF)则返回0,如果错误则返回-1 A.getline从整体上来说,应这么理解它的用法: 当其左右无重定向符 | 或 < 时,getline作用于当前文件,读入当前文件的第一行给其后跟的变量var 或$0(无变量);应该注意到,由于awk在处理getline之前已经读入了一行,所以getline得到的返回结果是隔行的。 当其左右有重定向符 | 或 < 时,getline则作用于定向输入文件,由于该文件是刚打开,并没有被 awk读入一行,只是getline读入,那么getline返回的是该文件的第一行,而不是隔行。 B.getline用法大致可分为三大类(每大类又分两小类),即总共有6种用法。代码如下: QUOTE: awk ‘BEGIN{“cat data.txt”|getline d; print d}’ data2.txt awk ‘BEGIN{“cat data.txt”|getline; print $0}’ data2.txt $0可以省略 awk ‘BEGIN{getline d < “data.txt”;

awk输入命令getline

六眼飞鱼酱① 提交于 2019-11-26 15:08:35
getline为awk所提供的输入命令 如果找到一条记录则getline返回1,如果到了文件结束(EOF)则返回0,如果错误则返回-1 A.getline从整体上来说,应这么理解它的用法: 当其左右无重定向符 | 或 < 时,getline作用于当前文件,读入当前文件的第一行给其后跟的变量var 或$0(无变量);应该注意到,由于awk在处理getline之前已经读入了一行,所以getline得到的返回结果是隔行的。 当其左右有重定向符 | 或 < 时,getline则作用于定向输入文件,由于该文件是刚打开,并没有被 awk读入一行,只是getline读入,那么getline返回的是该文件的第一行,而不是隔行。 B.getline用法大致可分为三大类(每大类又分两小类),即总共有6种用法。代码如下: QUOTE: awk ‘BEGIN{“cat data.txt”|getline d; print d}’ data2.txt awk ‘BEGIN{“cat data.txt”|getline; print $0}’ data2.txt $0可以省略 awk ‘BEGIN{getline d < “data.txt”; print d}’ data2.txt awk ‘BEGIN{getline < “data.txt”; print $0}’ data2.txt 此种方法不成立

awk——getline

北城余情 提交于 2019-11-26 15:08:27
A.getline从整体上来说,应这么理解它的用法: 当其左右无重定向符 | 或 < 时,getline作用于当前文件,读入当前文件的第一行给其后跟的变量var 或$0(无变量);应该注意到,由于awk在处理getline之前已经读入了一行,所以getline得到 的返回结果是隔行的。 当其左右有重定向符 | 或 < 时,getline则作用于定向输入文件,由于该文件是刚打开,并没有被awk读入一行,只是getline读入,那么getline返回的是该文件的第一行,而不是隔行。 下面的代码就体现了这两种用法: awk ' BEGIN{ Nfile=4 getline for(i=2; i<=Nfile; i++) { file="DOSP"i getline < file } } { for(j=1; j<=NF; j++) sum[j]=$j for(i=2; i<=Nfile; i++) { file="DOSP"i getline < file for(j=2; j<=NF; j++) sum[j]+=$j } for(j=1; j<=NF; j++) printf "%12.8f ",sum[j] print " " } ' DOSP1 B.getline用法大致可分为三大类(每大类又分两小类),即总共有6种用法。代码如下: nawk ‘BEGIN{“cat data

std::getline on std::cin

不羁岁月 提交于 2019-11-26 14:49:40
问题 Is there any good reason why: std::string input; std::getline(std::cin, input); the getline call won't wait for user input? Is the state of cin messed up somehow? 回答1: Most likely you are trying to read a string after reading some other data, say an int . consider the input: 11 is a prime if you use the following code: std::cin>>number; std::getline(std::cin,input) the getline will only read the newline after 11 and hence you will get the impression that it's not waiting for user input. The