getline

I am trying to read the memory addresses from /proc//maps and I use the following code for (ptr = NULL; getline(&ptr, &n, file) > 0;) { if (ptr[0]== ' ') { continue; } sscanf(ptr, "%lx-%lx", &r0, &r1); printf("r0: %lx, r1: %lx\n", r0, r1); } Assume that file points to /proc//maps & ptr is the line pointer. But when you consider a maps file, it doesn't read the file proper. It drops the zero, it does not pick the zeros up. So consider: 00110000-00123000 r-xp 00000000 08:01 129925 /lib/i686/cmov/libnsl-2.11.1.so After running through my program: r0: 110000, r1: 123000 How I keep the leading

This looks like a similar question to this one , however I think my case might actually be a bit different. The code is as below: void readOmronResults(string fileName) { ifstream inFile(fileName); ofstream testRead("test_read.txt"); string line; //getline(inFile, line); //cout << line << endl; while (getline(inFile, line)) { testRead << line << endl; } inFile.close(); testRead.close(); cout << "Finished reading omron results" << endl; } testRead is just used for debugging. The input file is a .csv file which looks like: IMAGE,RIGHT_EYE_IN_X,RIGHT_EYE_IN_Y,RIGHT_EYE_OUT_X,RIGHT_EYE_OUT_Y,LEFT

I ran into an unexpected compilation error when trying to use getline() with a temporary stream object: #include <iostream> #include <string> #include <sstream> using namespace std; int main() { string input = "hello\nworld\nof\ndelimiters"; string line; if (getline(stringstream(input), line)) // ERROR! { cout << line << endl; } } It looks like no overload of getline() exists that accepts an rvalue reference to a stream object. If I change main() to use an lvalue, it compiles and runs as expected: int main() { string input = "hello\nworld\nof\ndelimiters"; string line; stringstream ss(inpupt);

I'm trying to store every line separately in an array of strings. It doesn't work the way I've written it obviously all I'm getting when I try to print array[0] is the last line of the textfile. But when I print the variable "line" inside of the while loop I can print every single line in the text file but I can only seem to store the last line of the txt file. Is this possible to do? Or is this a limitation of getline..? int main() { FILE * fp; char *line; ssize_t read; size_t bufsize = 32; int i=0; char **array; array = malloc(bufsize * sizeof(char)); line = malloc(bufsize * sizeof(char));

I'm creating a simple console application in C++ that gets string and char inputs from the user. To make things simple, I would like to use the string and char data types to pass input from cin to. To get string inputs, I'm using the getline method: string var; cin.ignore(); //I used ignore() because it prevents skipping a line after using cin >> var getline(cin, var); To get char inputs, I'm using the cin >> var method: char var; cin >> var; This works fine for the most part. However, when I enter a string using getline , it ignores the first character of my string. Is it possible to use

I want it to consider anything that isn't an alphabet character to be a delimiter. How can I do this? You can't. The default delimiter is \n : while (std::getline (std::cin, str) // '\n' is implicit For other delimiters, pass them: while (std::getline (std::cin, str, ' ') // splits at a single whitespace However, the delimiter is of type char, thus you can only use one "split-character", but not what not to match. If your input already happens to be inside a container like std::string , you can use find_first_not_of or find_last_not_of . In your other question, are you sure you have considered