getchar

GetKeyState() vs. GetAsyncKeyState() vs. getch()?

烈酒焚心 提交于 2019-12-20 18:04:38
问题 What's the difference between getting a key press with: GetKeyState() GetAsyncKeyState() getch() ? When should I use one over the other? 回答1: GetKeyState() and GetAsyncKeyState() are Windows specific APIs, while getch() works on other non-Windows-specific C compilers. GetKeyState() gets the key status returned from the thread's message queue . The status does not reflect the interrupt-level state associated with the hardware. GetAsyncKeyState() specifies whether the key was pressed since the

getchar() skips every other char in C

痴心易碎 提交于 2019-12-20 07:28:16
问题 I have been having problems fully using getchar() for a while now in C. And in this case I am trying to read a line and put the char's of the line into an array. However upon assigning the getchar() to the array it skips some characters. For example the input "It skips every other" the output is...I\n \n k\n p\n \n v\n r\n \n t\n e\n. (the \n is just to represent the new line.) int N = 0; char message[80] = {}; do { message[N] = getchar(); N++; printf("%c\n", message[N-1]); } while(getchar()

getchar() skips every other char in C

故事扮演 提交于 2019-12-20 07:28:03
问题 I have been having problems fully using getchar() for a while now in C. And in this case I am trying to read a line and put the char's of the line into an array. However upon assigning the getchar() to the array it skips some characters. For example the input "It skips every other" the output is...I\n \n k\n p\n \n v\n r\n \n t\n e\n. (the \n is just to represent the new line.) int N = 0; char message[80] = {}; do { message[N] = getchar(); N++; printf("%c\n", message[N-1]); } while(getchar()

Compiling c code with bool without using c99 standard

帅比萌擦擦* 提交于 2019-12-20 07:18:05
问题 I've tried to compile a code using a bool variable in C and I've included the stdbool header but when I compiled it I didn't specify that I want to compile it with the c99 standard (so it was compiled with ANSI C standard) but it worked anyway. I was wondering why is that ? Here's the code : #include <stdio.h> #include <stdbool.h> int main() { char name[20]; printf("What's your name ? "); gets(name); printf("Nice to meet you %s.\n", name); bool exit = false; char c; printf("Do you wish to

Terminate a while loop using `getchar()`

无人久伴 提交于 2019-12-20 03:26:15
问题 For my homework assignment, I need to implement Horners Algorithm for converting between bases. I have been told to use getchar() for this assignment. But I am having a problem where when I hit enter, the program doesn't terminate and just takes in more chars. Example: bryce> ./pa1 Enter the fromRadix:16 Enter the toRadix:2 abc abc ^C bryce> Code: int readRadixA(int radixA) { char myChar = getchar(); int result = 0; int run = 0; while(myChar != EOF) { if(myChar == "\n") break; Horners();

Comet OJ Contest 4

和自甴很熟 提交于 2019-12-20 02:52:00
  A:签到。 #include<bits/stdc++.h> using namespace std; #define ll long long #define inf 1000000010 char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c>'z')&&(c<'0'||c>'9')) c=getchar();return c;} int gcd(int n,int m){return m==0?n:gcd(m,n%m);} int read() { int x=0,f=1;char c=getchar(); while (c<'0'||c>'9') {if (c=='-') f=-1;c=getchar();} while (c>='0'&&c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar(); return x*f; } int T,a[6],cnt[6]; signed main() { T=read(); while (T--) { for (int i=1;i<=5;i++) a[i]=read(); memset(cnt,0,sizeof(cnt)); for (int i=1;i<=5;i++) cnt[a[i]]++; int mx=0; for (int i

c语言输入输出函数

…衆ロ難τιáo~ 提交于 2019-12-19 18:28:20
上学年学习c语言的时候比较匆忙,没好好吸收。 现在有时间好好复习下。 本文就c语言常见输入函数进行简单介绍,对比。 ps:由于自己能力有限,时间有限,多数介绍,总结都是摘录网上相关学习资料,下面给出本文参考资料的原文链接。 C语言的输入输出函数 C/C++学习笔记1 - 深入了解scanf()/getchar()和gets()等函数 -。常见输入输出函数简介。 getchar() //从键盘上输入一个字符常量,此常量就是该函数返回的值; putchar() //把变量中的一个字符常量输出; scanf() //从键盘上输入各类数据,并存放到程序变量中; printf() //把键盘中的各类数据,加以格式控制输出; gets() //读入一行字符串常量并放到程序的数组中; puts() //把数组变量中的一个字符串常量输出,并且带有回车'\n'; sscanf() //从一个字符串中提取各类数据; sprintf() //将各类数据写入字符串中; 一、printf()函数 printf()函数是格式化输出函数, 一般用于向标准输出设备按规定格式输出 信息。在编写程序时经常会用到此函数。printf()函数的调用格式为: printf(" <格式化字符串>", <参量表>); 其中格式化字符串包括两部分内容: 一部分是正常字符, 这些字符将按原 样输出; 另一部分是格式化规定字符, 以

Forethought Future Cup - Elimination Round

拈花ヽ惹草 提交于 2019-12-19 12:00:05
  A:签到。 #include<bits/stdc++.h> using namespace std; #define ll long long char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c>'z')&&(c<'0'||c>'9')) c=getchar();return c;} int gcd(int n,int m){return m==0?n:gcd(m,n%m);} int read() { int x=0,f=1;char c=getchar(); while (c<'0'||c>'9') {if (c=='-') f=-1;c=getchar();} while (c>='0'&&c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar(); return x*f; } int n;char s[100]; signed main() { #ifndef ONLINE_JUDGE freopen("a.in","r",stdin); freopen("a.out","w",stdout); #endif scanf("%s",s+1);n=strlen(s+1);int cnt=0; for (int i=1;i<=n;i++) if (s[i]=='a') cnt+

Why do I need to press CTRL+D twice to break out of `while ((c=getchar())!=EOF)` in Ubuntu 14.10?

独自空忆成欢 提交于 2019-12-19 10:21:54
问题 I am new to C Programming and Ubuntu. I was reading the "The C Programming Language" by D.M Ritchie where I found the following code: #include <stdio.h> int main() { int c; int nc=0; while((c = getchar()) != EOF) { nc++; } printf("%d Characters \n",nc); return 0; } But while running the program I enter "Hello" ,then CTRL+D twice to get the actual number of characters which is 5. But when I enter "Hello" then CTRL+D once , nothing happens, the terminal still waits for input. Why? 回答1: Quoting

Codeforces Round #460 (Div. 2)

你。 提交于 2019-12-19 05:34:53
最后把记忆化搜索乱搞的点给写串了,又炸裂了 但是因为馒神操作了一番 避免了掉rating T1 T2 T3 sb题,随便搞一搞50分钟过 1 // T1: 2 #include<iostream> 3 #include<cstdio> 4 #include<cstring> 5 #include<cstdlib> 6 #include<cmath> 7 #include<algorithm> 8 #include<queue> 9 #include<vector> 10 #include<map> 11 #define inf 2139062143 12 #define ll long long 13 #define MAXN 14 #define MOD 15 using namespace std; 16 inline int read() 17 { 18 int x=0,f=1;char ch=getchar(); 19 while(!isdigit(ch)) {if(ch=='-') f=-1;ch=getchar();} 20 while(isdigit(ch)) x=x*10+ch-'0',ch=getchar(); 21 return x*f; 22 } 23 int n,m; 24 double a,b,t; 25 int main() 26 { 27 n=read