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Hey, say I have a url just being passed through my php is there any easy way to get some GET variables that are being passed through it? It's not the actual url of the page or anything. like a just have a string containing http://www.somesite.com/index.php?url=var&file_id=var&test=var Whats the best way to get the values for those variables? parse_str(parse_url($url, PHP_URL_QUERY), $array) , see the manpage for parse_str for more info. $href = 'http://www.somesite.com/index.php?url=var&file_id=var&test=var'; $url = parse_url($href); print_r($url); /* Array ( [scheme] => http [host] => www

Possible Duplicate: Get query string values in JavaScript how can i get the get variable in javascript? i want to pass it in jquery function. function updateTabs(){ //var number=$_GET['number']; how can i do this? alert(number); $( "#tabs" ).tabs({ selected: number }); } var $_GET = {}; if(document.location.toString().indexOf('?') !== -1) { var query = document.location .toString() // get the query string .replace(/^.*?\?/, '') // and remove any existing hash string (thanks, @vrijdenker) .replace(/#.*$/, '') .split('&'); for(var i=0, l=query.length; i<l; i++) { var aux = decodeURIComponent

I am trying to send a get or a post through a command-line argument. That is test the script in the command line before I test through a browser (the server has issues). I tried searching online, and I suppose I was probably using incorrect terminology because I got nothing. I know this is possible because I saw someone do it. I just don't remember how it was done. Thanks! :) Are you using the standard CGI module? For example, with the following program (notice -debug in the arguments to use CGI ) #! /usr/bin/perl use warnings; use strict; use CGI qw/ :standard -debug /; print "Content-type:

What is the difference when encrypting GET and POST data? Thx for answer Edit: i need to write it more specific. When https-SSL encrypts both of this methods, what is the difference in way browser does this. Which parts are encrypted and which are not? I somewhere read, that the destination url is not encrypted in POST, is that true? If it is true and same in GET, where are all the parameters? Edit2: still dont know the answer on my question. When both methods are encrypted with same data, does the look the same when sniffed? What parts are encrypted and which are not? Ben S GET data is

How do I make an HTTP GET request with parameters in Ruby? It's easy to do when you're POST ing: require 'net/http' require 'uri' HTTP.post_form URI.parse('http://www.example.com/search.cgi'), { "q" => "ruby", "max" => "50" } But I see no way of passing GET parameters as a hash using 'net/http' . Chris Moos Use the following method: require 'net/http' require 'cgi' def http_get(domain,path,params) return Net::HTTP.get(domain, "#{path}?".concat(params.collect { |k,v| "#{k}=#{CGI::escape(v.to_s)}" }.join('&'))) if not params.nil? return Net::HTTP.get(domain, path) end params = {:q => "ruby",

I am making a library to get response from a particular URL with specified data and method type. For this, I am making a request with url. But when I set its method type, it shows an exception of unrecognized selector send in [NSURLRequest setHTTPMethod:] I am setting it as [requestObject setHTTPMethod:@"GET"]; Tell me what could be the problem. Also provide me the code if you have. Mobile Developer iOS Android NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:serverAddress] cachePolicy:NSURLRequestReloadIgnoringLocalAndRemoteCacheData timeoutInterval:10 ]

I am using WordPress. I have an image folder like mytheme/images/myimages . I want to retrieve all the images name from the folder myimages Please advice me, how can I get images name. sharif2008 try this $directory = "mytheme/images/myimages"; $images = glob($directory . "/*.jpg"); foreach($images as $image) { echo $image; } zur4ik you can do it simply with PHP opendir function. example: $handle = opendir(dirname(realpath(__FILE__)).'/pictures/'); while($file = readdir($handle)){ if($file !== '.' && $file !== '..'){ echo '<img src="pictures/'.$file.'" border="0" />'; } } Shafiqul Islam when