function

问题 I want to set the first day of the week to Thursday (not Sunday or Monday), because it's the company's cut-off date. I already have a code to determine the current week number of a date but it starts in Sunday or Monday. How to modify these to my preference? function findweek($date) { $monthstart=date("N",strtotime(date("n/l/Y",strtotime($date)))); $newdate=(date("j",strtotime($date))+$monthstart)/7; $ddate=floor($newdate); if($ddate != $date) { $ddate++; } return $ddate; } 回答1: http://php

问题 I have a dictionary that has values sometimes as strings, and sometimes as a functions. For the values that are functions is there a way to execute the function without explicitly typing () when the key is accessed? Example: d = {1: "A", 2: "B", 3: fn_1} d[3]() # To run function I want: d = {1: "A", 2: "B", 3: magic(fn_1)} d[3] # To run function 回答1: Another possible solution, is to create a custom dictionary object that implements this behavior: >>> class CallableDict(dict): ... def _

问题 I have a dictionary that has values sometimes as strings, and sometimes as a functions. For the values that are functions is there a way to execute the function without explicitly typing () when the key is accessed? Example: d = {1: "A", 2: "B", 3: fn_1} d[3]() # To run function I want: d = {1: "A", 2: "B", 3: magic(fn_1)} d[3] # To run function 回答1: Another possible solution, is to create a custom dictionary object that implements this behavior: >>> class CallableDict(dict): ... def _

问题 I have a dictionary that has values sometimes as strings, and sometimes as a functions. For the values that are functions is there a way to execute the function without explicitly typing () when the key is accessed? Example: d = {1: "A", 2: "B", 3: fn_1} d[3]() # To run function I want: d = {1: "A", 2: "B", 3: magic(fn_1)} d[3] # To run function 回答1: Another possible solution, is to create a custom dictionary object that implements this behavior: >>> class CallableDict(dict): ... def _

问题 I have a dictionary that has values sometimes as strings, and sometimes as a functions. For the values that are functions is there a way to execute the function without explicitly typing () when the key is accessed? Example: d = {1: "A", 2: "B", 3: fn_1} d[3]() # To run function I want: d = {1: "A", 2: "B", 3: magic(fn_1)} d[3] # To run function 回答1: Another possible solution, is to create a custom dictionary object that implements this behavior: >>> class CallableDict(dict): ... def _

问题 I have a function: def delete(title=None, pageid=None): # Deletes the page given, either by its title or ID ... pass However, my intention is for the function to take only one argument (either title OR pageid ). For example, delete(title="MyPage") or delete(pageid=53342) are valid, while delete(title="MyPage", pageid=53342) , is not. Zero arguments can not be passed. How would I go about doing this? 回答1: There is no Python syntax that'll let you define exclusive-or arguments, no. You'd have

问题 #I EDITED MY ORIGINAL POST in order to put a simpler example. I use differential evolution (DE) of Scipy to optimize certain parameters. I would like to use all the PC processors in this task and I try to use the option "workers=-1" The codition asked is that the function called by DE must be pickleable. If I run the example in https://docs.scipy.org/doc/scipy/reference/generated/scipy.optimize.differential_evolution.html#scipy.optimize.differential_evolution, the optimisation works. from

问题 Trying to create a timer loop in TypeScript: timeout() { setTimeout(function () { console.log('Test'); this.timeout(); }, 1000/60); } But after the first loop works correctly I'm getting this error: "Uncaught TypeError: this.timeout is not a function". It seems that the this variable does not exist after the initial loop. Any ideas? 回答1: Because your this doesn't refer to the object. Every function has it's own this. So your this is the one which is defined by anonymous function inside the

问题 Trying to create a timer loop in TypeScript: timeout() { setTimeout(function () { console.log('Test'); this.timeout(); }, 1000/60); } But after the first loop works correctly I'm getting this error: "Uncaught TypeError: this.timeout is not a function". It seems that the this variable does not exist after the initial loop. Any ideas? 回答1: Because your this doesn't refer to the object. Every function has it's own this. So your this is the one which is defined by anonymous function inside the

问题 I am trying to loop an array using a recursive function. The loop should stop and return the value of the key, if it matches a given regex pattern. The loop stops correctly when the condition is met. However, it only returns the key's value if the match occurs for the first key (index 0) in the array and returns 'undefined' for the rest. Where's my mistake? Here's the code to better illustrate: function loop(arr,i) { var i = i||0; if (/i/gim.test(arr[i])){ console.log("key value is now: " +