function

问题 I am just doing a revision task and was running into the error too few arguments to function, so I did some research and apparently can use NULL for the statement not in use. However, when I run my program all that happens is the prompt for the user to enter the 3 values then it ends. It doesn't perform the calculations. Below is my code, if anyone can help with that, it would be greatly appreciated. #include <stdio.h> #include <stdlib.h> float res_calculation (float r1, float r2, float r3,

问题 I am just doing a revision task and was running into the error too few arguments to function, so I did some research and apparently can use NULL for the statement not in use. However, when I run my program all that happens is the prompt for the user to enter the 3 values then it ends. It doesn't perform the calculations. Below is my code, if anyone can help with that, it would be greatly appreciated. #include <stdio.h> #include <stdlib.h> float res_calculation (float r1, float r2, float r3,

问题 I am just doing a revision task and was running into the error too few arguments to function, so I did some research and apparently can use NULL for the statement not in use. However, when I run my program all that happens is the prompt for the user to enter the 3 values then it ends. It doesn't perform the calculations. Below is my code, if anyone can help with that, it would be greatly appreciated. #include <stdio.h> #include <stdlib.h> float res_calculation (float r1, float r2, float r3,

问题 I've been trying to get this function to return a Bool value but I don't understand why i'm getting the error "missing return in a function expected to return 'Bool'. I've been looking around online and tried different things but I can't seem to find a solution. Any help would be appreciated! func trueSquare(a:[Int], b:[Int]) -> Bool { for i in b[0]...b.endIndex { if b[i] == a[i]*a[i] { return true } else { return false } } } EDIT: I have changed the loop to for i in 0...(b.count - 1) but I

问题 This question already has answers here : How does dereferencing of a function pointer happen? (5 answers) Closed last month . According to the GNU C manual, functions can be called using function pointers like so: func (j); /* (*func) (j); would be equivalent. */ So my reasoning here is: func itself is a pointer to the func(int) function. When you call func(j) , you are implicitly accessing the value of the pointer func (you are moving to the memory location where func is), in the same way as

问题 I am trying to calculate the average value of columns in 2D array, but I cannot figure out the code. The function should return the average value of each column. And I cannot print the result in the function. The print should be in main function. static double average_columns(double matrix[][]) { int i, j, sum = 0, average=0; for (i = 0; i < matrix.length; i++) { for (j = 0; j < matrix[i].length; j++) { sum=(int) (sum+matrix[i][j]); } average=sum/matrix[i].length; sum=0; } return average; }

问题 I am trying to calculate the average value of columns in 2D array, but I cannot figure out the code. The function should return the average value of each column. And I cannot print the result in the function. The print should be in main function. static double average_columns(double matrix[][]) { int i, j, sum = 0, average=0; for (i = 0; i < matrix.length; i++) { for (j = 0; j < matrix[i].length; j++) { sum=(int) (sum+matrix[i][j]); } average=sum/matrix[i].length; sum=0; } return average; }

问题 I am trying to calculate the average value of columns in 2D array, but I cannot figure out the code. The function should return the average value of each column. And I cannot print the result in the function. The print should be in main function. static double average_columns(double matrix[][]) { int i, j, sum = 0, average=0; for (i = 0; i < matrix.length; i++) { for (j = 0; j < matrix[i].length; j++) { sum=(int) (sum+matrix[i][j]); } average=sum/matrix[i].length; sum=0; } return average; }

问题 I am trying to calculate the average value of columns in 2D array, but I cannot figure out the code. The function should return the average value of each column. And I cannot print the result in the function. The print should be in main function. static double average_columns(double matrix[][]) { int i, j, sum = 0, average=0; for (i = 0; i < matrix.length; i++) { for (j = 0; j < matrix[i].length; j++) { sum=(int) (sum+matrix[i][j]); } average=sum/matrix[i].length; sum=0; } return average; }

问题 was the idea of nested functions considered to be useless during the time of developing older c++ standard, because its usage is basically covered by another concept like object-oriented programming; or it wasn't implemented just as a matter of simplification? 回答1: Nested functions - to be useful - need the stack frame of the containing function as context. Look at this: class Foo() { void Tripulate() { int i=0; void Dip() { // ... } int x = 12; for(i=1; i<=3; ++i) { int z= 33; Dip(); // ...