function

JavaScript - Persistent data in function between calls?

由 ╄→гoц情女王★ 提交于 2021-01-24 13:48:08
问题 I want to call a function with an argument and store the value so that next time I call that function without arguments it uses the last argument that was set. Is this possible with JavaScript? Edit: Here's more info on what I'm trying to achieve... var track = 0; $.getJSON('songsMetadata.json', function(data){ appendData(data); }); player.bind("ended", function(){ track++ appendData(); }); function appendData(data){ /* Here I want to populate the inside 'data' argument only once (in the

function that squares the values in an array

由 懵懂的女人 提交于 2021-01-24 11:44:49
问题 i've been instructed to create a function that takes values from an array and squares each value, and logging the numbers to the console. i've attempted two methods, neither of which work so far: first attempt: var numbers = [2, 7, 13, 24]; function squareAll(numbers) { var newArray = []; for(i = 0; i < numbers.length; i++) { numbers = newArray.push(Math.pow(numbers[i], 2)) return newArray; } console.log(squareAll(numbers)); } second attempt: var numbers = [2, 7, 9, 25]; var newArray = [];

Javascript - change paragraph Text on Each Button Click

由 北城余情 提交于 2021-01-21 12:28:35
问题 I am trying to create 3 buttons, and using javascript, If button 1 is clicked then it changes the "Click a button" text to "You pressed Button 1" Same for Button 2 and 3! And if Button 3 is pressed, the text colour changes to GREEN However, I can't seem to get it to work! Any help would be appreciated Here is my Current Code: <!DOCTYPE html> <html> <head> <title>Button</title> </head> <body> <script type="text/javascript"> function changeText() { var b1 = document.getElementById('b1'); var b2

Deparse, substitute with three-dots arguments

由 天涯浪子 提交于 2021-01-21 09:13:36
问题 Let consider a typical deparse(substitute( R call: f1 <-function(u,x,y) {print(deparse(substitute(x)))} varU='vu' varX='vx' varY='vy' f1(u=varU,x=varX,y=varY) That results in [1] "varX" which is what we expect and we want. Then, comes the trouble, I try to get a similar behaviour using the ... arguments i.e. f2 <- function(...) { l <- list(...) x=l$x print(deparse(substitute(x))) ### this cannot work but I would like something like that } That, not surprisingly, does not work : f2(u=varU,x

Deparse, substitute with three-dots arguments

由 谁都会走 提交于 2021-01-21 09:12:35
问题 Let consider a typical deparse(substitute( R call: f1 <-function(u,x,y) {print(deparse(substitute(x)))} varU='vu' varX='vx' varY='vy' f1(u=varU,x=varX,y=varY) That results in [1] "varX" which is what we expect and we want. Then, comes the trouble, I try to get a similar behaviour using the ... arguments i.e. f2 <- function(...) { l <- list(...) x=l$x print(deparse(substitute(x))) ### this cannot work but I would like something like that } That, not surprisingly, does not work : f2(u=varU,x

Frustrating recursive functions in JS [duplicate]

由 北城以北 提交于 2021-01-21 06:18:46
问题 This question already has answers here : How does this recursion work? (11 answers) Closed 18 days ago . I've been wracking my brain on this all day, and I still don't get it. Could someone please explain to me, how on earth does this function work?!?!?! function findSolution(target) { function find(current, history) { if (current == target) { return history; } else if (current > target) { return null; } else { return find(current + 5, `(${history} + 5)`) || find(current * 3, `(${history} * 3

Frustrating recursive functions in JS [duplicate]

由 ε祈祈猫儿з 提交于 2021-01-21 06:16:24
问题 This question already has answers here : How does this recursion work? (11 answers) Closed 18 days ago . I've been wracking my brain on this all day, and I still don't get it. Could someone please explain to me, how on earth does this function work?!?!?! function findSolution(target) { function find(current, history) { if (current == target) { return history; } else if (current > target) { return null; } else { return find(current + 5, `(${history} + 5)`) || find(current * 3, `(${history} * 3

Frustrating recursive functions in JS [duplicate]

由 人盡茶涼 提交于 2021-01-21 06:16:05
问题 This question already has answers here : How does this recursion work? (11 answers) Closed 18 days ago . I've been wracking my brain on this all day, and I still don't get it. Could someone please explain to me, how on earth does this function work?!?!?! function findSolution(target) { function find(current, history) { if (current == target) { return history; } else if (current > target) { return null; } else { return find(current + 5, `(${history} + 5)`) || find(current * 3, `(${history} * 3

Frustrating recursive functions in JS [duplicate]

由 旧巷老猫 提交于 2021-01-21 06:15:40
问题 This question already has answers here : How does this recursion work? (11 answers) Closed 18 days ago . I've been wracking my brain on this all day, and I still don't get it. Could someone please explain to me, how on earth does this function work?!?!?! function findSolution(target) { function find(current, history) { if (current == target) { return history; } else if (current > target) { return null; } else { return find(current + 5, `(${history} + 5)`) || find(current * 3, `(${history} * 3

Using “watch” to run a function repeatedly in Bash?

由 最后都变了- 提交于 2021-01-21 04:08:50
问题 This is my first Bash script. I have a WiFi issue with my Debian machine. I'm not here to ask about the cause, but rather how to put a band-aid on the issue with Bash. My WiFi will drop out at a random time, usually every 12-15 minutes. I use SSH on this server, and do not want to have to run ifdown wlan0 and ifup wlan0 (which reconnects the WiFi) manually from the physical server. The function of this Bash script is to attempt to connect three times. If it fails three times, it will give up.
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