fractions

Is there any controls available for star rating in ios ? So i can use that in UITableviewCell ?? I know there are some open open source controls like DYRating etc.. But iam not able to add it in tableview cell . You can check the ASStar rating . Add the control directly to your view controller or you can add into your cell . And here is github link . I recommend HCSStarRatingView . It is native-looking and it also supports IB_DESIGNABLE and IBInspectable . Take a look, it should suit you just fine: https://www.cocoacontrols.com/search?utf8=%E2%9C%93&q=star+rating Note: This is a "DISPLAY ONLY"

I wonder what would be the best way to format numbers so that the NumberGroupSeparator would work not only on the integer part to the left of the comma, but also on the fractional part, on the right of the comma. Math.PI.ToString("###,###,##0.0##,###,###,###") // As documented .. // ..this doesn't work 3.14159265358979 // result 3.141,592,653,589,79 // desired result As documented on MSDN the NumberGroupSeparator works only to the left of the comma. I wonder why?? A little clunky, and it won't work for scientific numbers but here is a try: class Program { static void Main(string[] args) { var

So, I am Writing this little program in c++, it's made to compute various values with lines (sorry i am french, i don't know how to say it in English, but they are the lines with equation types Y = kx + t). And I want my program to output fractions instead of decimals (2/3 instead of 0.666666666...). Can anyone tell me how ? I read online that there are some libraries for that purpose, can anyone help me on how to use them and/or how to implement them in my code ? Thanks :) #include "pch.h" #include <iostream> #include <string> std::string mainAnswer; bool endVar = false; void

An interview question: Given two int N (numerator) and D (denominator), return the fraction in string. if the fraction is repeating, then display the repeating part in bracket. Example: Input: N=1, D=3 output: 0.[3] Example: Input: N=2, D=5 output: 0.4 My idea: get a = N/D with double value. for part after decimal point, get each digit by x 10 in the process, if find repeating, record the index and insert [] finally. for part before decimal point, get each digit by / 10 Any better ideas? thanks I would avoid using a double like the plague. Due to finite precision, it will not give you the

I have this static method, it receives a double and "cuts" its fractional tail leaving two digits after the dot. works almost all the time. I have noticed that when it receives 2.3 it turns it to 2.29. This does not happen for 0.3, 1.3, 3.3, 4.3 and 102.3. Code basically multiplies the number by 100 uses modf divides the integer value by 100 and returns it. Here the code catches this one specific number and prints out: static double dRound(double number) { bool c = false; if (number == 2.3) c = true; int factor = pow(10, 2); number *= factor; if (c) { cout << " number *= factor : " << number <

I need to us python to convert an improper fraction to a mixed number or even a float to a mixed number. My code is as follows: from fractions import Fraction numerator = int(input("Enter numerator ") ) denominator = int(input("Enter denominator ") ) num = numerator / denominator num = Fraction(num) print(num) If input is 5 and 4, the output is '5/4' not a mixed number. You can use the divide and modulo operators to print this: The integer part is numerator // denominator . The numerator of the proper fraction remainder is numerator % denominator . And, of course, the denominator doesn't