forms

Symfony 4 - how to add csrf token without building form?

由 被刻印的时光 ゝ 提交于 2020-12-08 07:13:07
问题 I am reading tutorial here https://symfony.com/doc/current/form/csrf_protection.html how to add csrf token. It says to use form_end() in the template. But this is not working, gives error: Type error: Too few arguments to function Symfony\Component\Form\FormRenderer::renderBlock(), 0 passed in E:\projektai\php projektai\htdocs\mokomieji\symfony_4_demo\var\cache\dev\twig\bb\bb2248f7be504240fcc2ab43dabf593090ebc4c897ce72b1a979082d62914b47.php on line 48 and at least 2 expected Here is answer

Laravel display validation error

由 丶灬走出姿态 提交于 2020-12-06 14:58:50
问题 I try use this code: @foreach($errors->all() as $error) <li>{!! $error !!}</li> @endforeach and in view have this: I would like the error to be displayed correctly. exemple The name is required. In debbuger I can see. How to replace validation.required upon "The name is required" 回答1: you need to add validation in controller method like this.. $request->validate([ 'name' => 'required' ]); then you can show your validation error in view : @if ($errors->has('name')) <li>{{ $errors->first('name'

Redirection after successful form submit

由 孤街醉人 提交于 2020-12-06 07:06:09
问题 I have a form which should submit data after pressing the submit button. After tagging a few input fields as required the form always shows me when there is no input in the required field after pressing the submit button - so far, so good. What I would like to realize is that there is a redirection to another page if the submission was successful. If there are some empty required fields the form should show me, without redirecting me to another page. By now I have the following code: Submit

Using cascading combo boxes in a datasheet subform

由 一个人想着一个人 提交于 2020-12-06 04:08:36
问题 In Access 2010, I have tables Task and Action that have a many-to-many relationship through table ActionTask . In the form for Task , I want to put a subform for all the Action s related to the current task through the ActionTask junction table. This, in itself, I can do. The trick is that Action is actually the bottom rank of a four-tier hierarchy of tables. Each Action belongs to a Goal , each Goal belongs to a Theme , each Theme belongs to a Strategy . Rather than just have a combo box

Using cascading combo boxes in a datasheet subform

由 假如想象 提交于 2020-12-06 04:07:36
问题 In Access 2010, I have tables Task and Action that have a many-to-many relationship through table ActionTask . In the form for Task , I want to put a subform for all the Action s related to the current task through the ActionTask junction table. This, in itself, I can do. The trick is that Action is actually the bottom rank of a four-tier hierarchy of tables. Each Action belongs to a Goal , each Goal belongs to a Theme , each Theme belongs to a Strategy . Rather than just have a combo box

AJAX - Classic ASP - Post a Form

由 你离开我真会死。 提交于 2020-12-06 03:50:25
问题 I have a TEST.ASP with this code: <HTML> <HEAD> <SCRIPT src="ajaxScript.js" type="text/javascript"></SCRIPT> </HEAD> <BODY> <FORM action="action_page.asp" method="post"> First Name:<BR> <INPUT type="text" name="FName"><BR> Last Name:<BR> <INPUT type="text" name="LName"><BR> <INPUT type="submit" value="Submit"> <BUTTON type="button" onClick="loadXMLDoc('action_page.asp',this.form);">GoGoGo!</BUTTON> </FORM> <DIV id="msgBoxDiv">TEST!!</DIV> </BODY> </HTML> The Javascript file that is called

AJAX - Classic ASP - Post a Form

由 二次信任 提交于 2020-12-06 03:48:08
问题 I have a TEST.ASP with this code: <HTML> <HEAD> <SCRIPT src="ajaxScript.js" type="text/javascript"></SCRIPT> </HEAD> <BODY> <FORM action="action_page.asp" method="post"> First Name:<BR> <INPUT type="text" name="FName"><BR> Last Name:<BR> <INPUT type="text" name="LName"><BR> <INPUT type="submit" value="Submit"> <BUTTON type="button" onClick="loadXMLDoc('action_page.asp',this.form);">GoGoGo!</BUTTON> </FORM> <DIV id="msgBoxDiv">TEST!!</DIV> </BODY> </HTML> The Javascript file that is called

Save form data in Django

由 梦想的初衷 提交于 2020-12-05 05:00:26
问题 I'm trying to set up a form in Django and save the data to my database, without using a ModelForm. My form is working, but the part I am stuck on is how to process the form data and save it within the view. As you can see, after 'if form.is_valid():' I am stuck and cannot think of the right code. # models.py from django.db import models class Listing(models.Model): business_name = models.CharField(max_length=80) business_email = models.EmailField() business_website = models.CharField(max

WooCommerce lost password form on another page

由 不问归期 提交于 2020-12-03 18:05:07
问题 Using the latest version of WooCommerce, I'm trying to get the lost password form to show up on several different pages. The problem is, copying the default form from woocommerce > templates > myaccount > form-lost-password.php and placing the code on another page would not work. Here is the default code for the form: <form method="post" class="lost_reset_password"> <?php if( 'lost_password' == $args['form'] ) : ?> <p><?php echo apply_filters( 'woocommerce_lost_password_message', __( 'Lost

WooCommerce lost password form on another page

由 六月ゝ 毕业季﹏ 提交于 2020-12-03 18:02:00
问题 Using the latest version of WooCommerce, I'm trying to get the lost password form to show up on several different pages. The problem is, copying the default form from woocommerce > templates > myaccount > form-lost-password.php and placing the code on another page would not work. Here is the default code for the form: <form method="post" class="lost_reset_password"> <?php if( 'lost_password' == $args['form'] ) : ?> <p><?php echo apply_filters( 'woocommerce_lost_password_message', __( 'Lost
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